Bird
Raised Fist0
DSA Javaprogramming~30 mins

Adjacency Matrix Representation in DSA Java - Build from Scratch

Choose your learning style10 modes available
Adjacency Matrix Representation
📖 Scenario: Imagine you are managing a small network of 4 computers. You want to represent which computers are directly connected to each other using a simple table.
🎯 Goal: You will build an adjacency matrix in Java to show the connections between these 4 computers. Each cell in the matrix will be 1 if two computers are connected, and 0 if they are not.
📋 What You'll Learn
Create a 4x4 integer matrix called adjMatrix initialized with zeros
Create a variable called numComputers and set it to 4
Set the connections between computers using the adjacency matrix
Print the adjacency matrix in a readable format
💡 Why This Matters
🌍 Real World
Adjacency matrices are used in computer networks to represent direct connections between devices, helping in routing and network analysis.
💼 Career
Understanding adjacency matrices is important for software engineers working with graphs, networks, and algorithms in fields like telecommunications and social network analysis.
Progress0 / 4 steps
1
Create the adjacency matrix
Create a 2D integer array called adjMatrix with 4 rows and 4 columns, initialized with zeros.
DSA Java
Hint

Use new int[4][4] to create a 4 by 4 matrix filled with zeros.

2
Add the number of computers
Create an integer variable called numComputers and set it to 4.
DSA Java
Hint

Declare int numComputers = 4; to store the number of computers.

3
Set connections in the adjacency matrix
Set the following connections in adjMatrix: computer 0 connected to 1 and 2, computer 1 connected to 0 and 3, computer 2 connected to 0, and computer 3 connected to 1. Use adjMatrix[row][column] = 1; to mark connections.
DSA Java
Hint

Use adjMatrix[row][column] = 1; to mark each connection.

4
Print the adjacency matrix
Use nested for loops with variables i and j to print the adjMatrix row by row, separating values with spaces.
DSA Java
Hint

Use two for loops to print each row and column, and System.out.print to print values with spaces.

Practice

(1/5)
1. What does an adjacency matrix represent in graph theory?
easy
A. A 2D array showing edges between nodes
B. A list of nodes in the graph
C. A sequence of visited nodes
D. A stack used for graph traversal

Solution

  1. Step 1: Understand adjacency matrix concept

    An adjacency matrix is a 2D array where rows and columns represent nodes.
  2. Step 2: Identify what the matrix stores

    Each cell shows if an edge exists between two nodes (1 for edge, 0 for no edge).
  3. Final Answer:

    A 2D array showing edges between nodes -> Option A
  4. Quick Check:

    Adjacency matrix = 2D array of edges [OK]
Hint: Adjacency matrix is always a 2D array showing connections [OK]
Common Mistakes:
  • Confusing adjacency matrix with adjacency list
  • Thinking it stores node values instead of edges
  • Mixing it up with traversal order
2. Which of the following is the correct way to declare an adjacency matrix for a graph with 4 nodes in Java?
easy
A. int[] matrix = new int[4][4];
B. int matrix = new int[4];
C. int[][] matrix = new int[4][4];
D. int[][] matrix = new int[4];

Solution

  1. Step 1: Recall Java 2D array declaration syntax

    In Java, a 2D array is declared as type[][] name = new type[rows][columns];
  2. Step 2: Match with graph nodes count

    For 4 nodes, we need a 4x4 matrix, so new int[4][4] is correct.
  3. Final Answer:

    int[][] matrix = new int[4][4]; -> Option C
  4. Quick Check:

    2D array for 4 nodes = new int[4][4] [OK]
Hint: 2D array syntax: type[][] name = new type[size][size]; [OK]
Common Mistakes:
  • Using single brackets for 2D array
  • Declaring 1D array instead of 2D
  • Incorrect array initialization syntax
3. Given the following adjacency matrix for a graph with 3 nodes:
int[][] matrix = {
  {0, 1, 0},
  {1, 0, 1},
  {0, 1, 0}
};
What is the output of the code snippet?
for (int i = 0; i < 3; i++) {
  for (int j = 0; j < 3; j++) {
    if (matrix[i][j] == 1) {
      System.out.print(i + "->" + j + " ");
    }
  }
}
medium
A. 0->2 2->0
B. 0->0 1->1 2->2
C. 1->0 2->1
D. 0->1 1->0 1->2 2->1

Solution

  1. Step 1: Analyze the matrix values

    matrix[0][1] = 1, matrix[1][0] = 1, matrix[1][2] = 1, matrix[2][1] = 1; others are 0.
  2. Step 2: Trace the nested loops and print statements

    For each 1, print "i->j ": 0->1, 1->0, 1->2, 2->1.
  3. Final Answer:

    0->1 1->0 1->2 2->1 -> Option D
  4. Quick Check:

    Edges printed where matrix[i][j] = 1 [OK]
Hint: Print edges where matrix cell is 1 [OK]
Common Mistakes:
  • Printing zeros as edges
  • Mixing i and j indices
  • Skipping symmetric edges
4. Identify the error in the following code snippet that tries to create an adjacency matrix for 3 nodes:
int[][] matrix = new int[3];
matrix[0][1] = 1;
medium
A. Index out of bounds error at matrix[0][1]
B. 2D array declared incorrectly with single dimension
C. Matrix values cannot be assigned directly
D. Missing import statement for arrays

Solution

  1. Step 1: Check array declaration syntax

    int[][] matrix = new int[3]; declares a 1D array of int arrays but does not initialize inner arrays.
  2. Step 2: Understand why matrix[0][1] causes error

    Inner arrays are null, so accessing matrix[0][1] causes NullPointerException or compile error.
  3. Final Answer:

    2D array declared incorrectly with single dimension -> Option B
  4. Quick Check:

    2D array needs both dimensions declared [OK]
Hint: Declare both dimensions for 2D arrays: new int[size][size] [OK]
Common Mistakes:
  • Declaring only one dimension for 2D array
  • Not initializing inner arrays
  • Confusing array types
5. You have a directed graph with 4 nodes and edges: 0->1, 0->2, 1->2, 2->3. Which adjacency matrix correctly represents this graph?
hard
A. [[0,1,1,0],[0,0,1,0],[0,0,0,1],[0,0,0,0]]
B. [[0,1,0,0],[1,0,1,0],[0,1,0,1],[0,0,0,0]]
C. [[0,0,1,0],[0,0,0,1],[1,0,0,0],[0,0,0,0]]
D. [[0,1,1,1],[0,0,1,0],[0,0,0,0],[0,0,0,0]]

Solution

  1. Step 1: Map edges to matrix positions

    Edges: 0->1 means matrix[0][1]=1, 0->2 means matrix[0][2]=1, 1->2 means matrix[1][2]=1, 2->3 means matrix[2][3]=1.
  2. Step 2: Check each option for these values

    [[0,1,1,0],[0,0,1,0],[0,0,0,1],[0,0,0,0]] matches exactly these edges with 1s in correct places and 0s elsewhere.
  3. Final Answer:

    [[0,1,1,0],[0,0,1,0],[0,0,0,1],[0,0,0,0]] -> Option A
  4. Quick Check:

    Edges mapped as 1s in matrix [OK]
Hint: Mark 1 for each edge from row to column [OK]
Common Mistakes:
  • Confusing directed edges with undirected
  • Placing 1s symmetrically for directed graph
  • Missing edges in matrix
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard