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DSA Javaprogramming~10 mins

Why Circular Linked List and Real World Use Cases in DSA Java - Test Your Knowledge

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a circular linked list node that points to itself.

DSA Java
Node node = new Node(10);
node.next = [1];
Drag options to blanks, or click blank then click option'
Anode
Bnull
Cnew Node(10)
Dhead
Attempts:
3 left
💡 Hint
Common Mistakes
Setting next to null instead of pointing to the node itself.
Creating a new node instead of pointing to the existing node.
2fill in blank
medium

Complete the code to insert a new node after the head in a circular linked list.

DSA Java
Node newNode = new Node(20);
newNode.next = head.next;
head.next = [1];
Drag options to blanks, or click blank then click option'
Ahead
Bnew Node(20)
Cnull
DnewNode
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning head to head.next instead of newNode.
Assigning null which breaks the circular link.
3fill in blank
hard

Fix the error in the code to traverse a circular linked list starting from head.

DSA Java
Node current = head;
do {
    System.out.println(current.data);
    current = [1];
} while (current != head);
Drag options to blanks, or click blank then click option'
Anull
Bhead
Ccurrent.next
Dhead.next
Attempts:
3 left
💡 Hint
Common Mistakes
Setting current to head causes infinite loop.
Setting current to null breaks traversal.
4fill in blank
hard

Fill in the blank to check if the circular linked list has only one node.

DSA Java
if (head != null && head.next [1] head) {
    System.out.println("Only one node in the list");
} else {
    System.out.println("Not only one node in the list");
}
Drag options to blanks, or click blank then click option'
A>
B==
C<
D!=
Attempts:
3 left
💡 Hint
Common Mistakes
Using != instead of == causes wrong condition.
Using relational operators like < or > which are invalid for references.
5fill in blank
hard

Fill all three blanks to create a method that counts nodes in a circular linked list.

DSA Java
public int countNodes(Node head) {
    if (head == null) return 0;
    int count = 1;
    Node current = head.next;
    while (current != [1]) {
        count [2] 1;
        current = [3];
    }
    return count;
}
Drag options to blanks, or click blank then click option'
Ahead
B+=
Ccurrent.next
Dnull
Attempts:
3 left
💡 Hint
Common Mistakes
Using null instead of head in loop condition.
Using = instead of += for count increment.
Assigning current to null instead of current.next.

Practice

(1/5)
1. What is the main advantage of using a Circular Linked List over a regular singly linked list?
easy
A. It uses less memory than a singly linked list
B. It allows continuous traversal from any node without reaching null
C. It automatically sorts the elements
D. It prevents duplicate elements

Solution

  1. Step 1: Understand traversal in singly linked list

    A singly linked list ends with a null pointer, so traversal stops at the last node.
  2. Step 2: Understand traversal in circular linked list

    In a circular linked list, the last node points back to the first node, allowing continuous traversal without null.
  3. Final Answer:

    It allows continuous traversal from any node without reaching null -> Option B
  4. Quick Check:

    Continuous traversal = Advantage of circular linked list [OK]
Hint: Circular lists loop back to start, no null end [OK]
Common Mistakes:
  • Thinking circular lists use less memory
  • Assuming circular lists sort elements automatically
  • Believing circular lists prevent duplicates
2. Which of the following is the correct way to check if a circular linked list is empty in Java?
easy
A. if (head == null) { /* empty */ }
B. if (head.next == null) { /* empty */ }
C. if (head == head.next) { /* empty */ }
D. if (head.data == null) { /* empty */ }

Solution

  1. Step 1: Understand empty list condition

    An empty circular linked list has no nodes, so head is null.
  2. Step 2: Analyze other options

    head.next may not exist if head is null; head == head.next means one node pointing to itself; head.data null is invalid if data is primitive.
  3. Final Answer:

    if (head == null) { /* empty */ } -> Option A
  4. Quick Check:

    Empty list check = head == null [OK]
Hint: Empty list means head is null [OK]
Common Mistakes:
  • Checking head.next without null check
  • Confusing single node with empty list
  • Checking data field for emptiness
3. What will be the output of the following Java code snippet that uses a circular linked list?
class Node {
  int data;
  Node next;
  Node(int d) { data = d; next = null; }
}

public class Test {
  public static void main(String[] args) {
    Node head = new Node(1);
    Node second = new Node(2);
    Node third = new Node(3);
    head.next = second;
    second.next = third;
    third.next = head; // circular link

    Node temp = head;
    int count = 0;
    while (count < 5) {
      System.out.print(temp.data + " ");
      temp = temp.next;
      count++;
    }
  }
}
medium
A. 1 2 3 4 5
B. 1 2 3
C. 1 2 3 1 2
D. Runtime error due to infinite loop

Solution

  1. Step 1: Understand the circular linked list structure

    Nodes 1, 2, 3 are linked circularly: 3 points back to 1.
  2. Step 2: Trace the loop for 5 iterations

    Loop prints data of nodes in order: 1, 2, 3, then again 1, 2 for 5 prints total.
  3. Final Answer:

    1 2 3 1 2 -> Option C
  4. Quick Check:

    5 prints cycling nodes = 1 2 3 1 2 [OK]
Hint: Count iterations, circular list repeats nodes [OK]
Common Mistakes:
  • Assuming infinite loop without count limit
  • Expecting new nodes beyond 3
  • Confusing output with linear list
4. Identify the error in the following code snippet that attempts to insert a node at the end of a circular linked list:
void insertEnd(Node head, int data) {
  Node newNode = new Node(data);
  if (head == null) {
    head = newNode;
    newNode.next = head;
  } else {
    Node temp = head;
    while (temp.next != null) {
      temp = temp.next;
    }
    temp.next = newNode;
    newNode.next = head;
  }
}
medium
A. The while loop condition should check for temp.next != head, not null
B. New node's next should be null, not head
C. No need to return head because Java passes objects by reference
D. New node should be inserted at head, not end

Solution

  1. Step 1: Understand circular linked list traversal

    In circular lists, last node points to head, so temp.next is never null.
  2. Step 2: Identify correct loop condition

    Loop should stop when temp.next == head to find last node, not when temp.next == null.
  3. Final Answer:

    The while loop condition should check for temp.next != head, not null -> Option A
  4. Quick Check:

    Loop condition in circular list = temp.next != head [OK]
Hint: In circular list, last node points to head, not null [OK]
Common Mistakes:
  • Using null check in circular list traversal
  • Setting new node's next to null
  • Confusing Java pass-by-value with pass-by-reference
5. Which real-world scenario is best suited for implementing a circular linked list?
hard
A. Maintaining a queue with fixed start and end
B. Storing a sorted list of unique user IDs
C. Implementing a stack data structure
D. Managing a playlist that loops songs continuously

Solution

  1. Step 1: Understand circular linked list use cases

    Circular linked lists are ideal for repeated cycles without stopping, like looping through items.
  2. Step 2: Match scenario to circular list

    A playlist that loops songs continuously fits perfectly, as after last song it returns to first.
  3. Final Answer:

    Managing a playlist that loops songs continuously -> Option D
  4. Quick Check:

    Continuous looping = Circular linked list use [OK]
Hint: Looping playlists = circular linked list use case [OK]
Common Mistakes:
  • Choosing stack or queue which have different structures
  • Assuming sorted lists need circular links
  • Confusing fixed queues with circular behavior
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10 questions~5 mineasy hard