Complete the code to create a circular linked list node that points to itself.
Node node = new Node(10); node.next = [1];
In a circular linked list with a single node, the node's next pointer points to itself.
Complete the code to insert a new node after the head in a circular linked list.
Node newNode = new Node(20); newNode.next = head.next; head.next = [1];
To insert after head, head's next should point to the new node.
Fix the error in the code to traverse a circular linked list starting from head.
Node current = head;
do {
System.out.println(current.data);
current = [1];
} while (current != head);To move through the list, update current to current.next each iteration.
Fill in the blank to check if the circular linked list has only one node.
if (head != null && head.next [1] head) { System.out.println("Only one node in the list"); } else { System.out.println("Not only one node in the list"); }
If head.next points back to head, the list has only one node.
Fill all three blanks to create a method that counts nodes in a circular linked list.
public int countNodes(Node head) {
if (head == null) return 0;
int count = 1;
Node current = head.next;
while (current != [1]) {
count [2] 1;
current = [3];
}
return count;
}The loop continues until current returns to head. Count increments by 1 each step. Current moves to current.next.
