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DSA Javaprogramming~10 mins

Stack Using Linked List vs Array Stack Trade-offs in DSA Java - Interactive Comparison Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to push an element onto an array-based stack.

DSA Java
stack[top] = element; top[1]=1;
Drag options to blanks, or click blank then click option'
A*
B-
C+
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using '-' instead of '+' causes overwriting previous elements.
2fill in blank
medium

Complete the code to pop an element from a linked list stack.

DSA Java
Node temp = top; top = top.[1]; return temp.data;
Drag options to blanks, or click blank then click option'
Aprev
Bchild
Cparent
Dnext
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'prev' causes errors because stack nodes link forward, not backward.
3fill in blank
hard

Fix the error in checking if the array stack is full.

DSA Java
if (top [1] stack.length) { throw new StackOverflowError(); }
Drag options to blanks, or click blank then click option'
A>=
B>
C<
D<=
Attempts:
3 left
💡 Hint
Common Mistakes
Using '>' misses the case when top equals length, causing overflow.
4fill in blank
hard

Fill both blanks to complete the linked list stack push method.

DSA Java
Node newNode = new Node(element); newNode.[1] = top; top = [2];
Drag options to blanks, or click blank then click option'
Anext
Bprev
Ctop
DnewNode
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'prev' instead of 'next' breaks the link direction.
Assigning top incorrectly causes stack corruption.
5fill in blank
hard

Fill all three blanks to create a dictionary comprehension that filters stack elements greater than 10.

DSA Java
Map<Integer, Integer> filtered = stackElements.entrySet().stream().filter(e -> e.getValue() [1] 10).collect(Collectors.toMap(e -> e.[2], e -> e.[3]));
Drag options to blanks, or click blank then click option'
A>
BgetKey()
CgetValue()
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<' filters wrong elements.
Mixing getKey() and getValue() causes wrong map construction.

Practice

(1/5)
1. Which of the following is a key advantage of using a linked list to implement a stack compared to using an array?
easy
A. Accessing elements by index is faster.
B. Memory usage is always less than an array.
C. The stack size can grow dynamically without a fixed limit.
D. It uses less memory overhead per element.

Solution

  1. Step 1: Understand stack size behavior in linked list

    A linked list stack can grow dynamically as nodes are added, limited only by available memory.
  2. Step 2: Compare with array stack size

    An array stack has a fixed size or requires resizing, which can be costly and limits immediate growth.
  3. Final Answer:

    The stack size can grow dynamically without a fixed limit. -> Option C
  4. Quick Check:

    Dynamic size = B [OK]
Hint: Linked list stacks grow dynamically; arrays have fixed size [OK]
Common Mistakes:
  • Thinking array stacks grow dynamically without resizing
  • Assuming linked list uses less memory always
  • Confusing access speed advantages
2. Which of the following is the correct way to declare an array-based stack of integers in Java?
easy
A. int stack = new int[10];
B. int[] stack = new int[10];
C. int[] stack = int[10];
D. int stack[] = int(10);

Solution

  1. Step 1: Recall Java array declaration syntax

    In Java, arrays are declared with type[], variable = new type[size];
  2. Step 2: Check each option

    int[] stack = new int[10]; matches correct syntax: int[] stack = new int[10]; others have syntax errors.
  3. Final Answer:

    int[] stack = new int[10]; -> Option B
  4. Quick Check:

    Correct Java array syntax = A [OK]
Hint: Java arrays use type[] var = new type[size]; [OK]
Common Mistakes:
  • Missing 'new' keyword
  • Using parentheses instead of brackets
  • Declaring array without []
3. Consider the following Java code implementing a stack using a linked list. What will be printed after pushing 10, 20, then popping once?
class Node {
  int data;
  Node next;
  Node(int d) { data = d; next = null; }
}

class Stack {
  Node top;
  void push(int x) {
    Node n = new Node(x);
    n.next = top;
    top = n;
  }
  int pop() {
    if (top == null) return -1;
    int val = top.data;
    top = top.next;
    return val;
  }
}

public class Main {
  public static void main(String[] args) {
    Stack s = new Stack();
    s.push(10);
    s.push(20);
    System.out.println(s.pop());
  }
}
medium
A. 20
B. null
C. 10
D. Compilation error

Solution

  1. Step 1: Trace push operations

    Push 10: top points to node with 10. Push 20: top points to node with 20, next points to 10.
  2. Step 2: Trace pop operation

    Pop removes top node (20), returns 20, top now points to node with 10.
  3. Final Answer:

    20 -> Option A
  4. Quick Check:

    Last pushed, first popped = 20 [OK]
Hint: Stack pop returns last pushed value [OK]
Common Mistakes:
  • Confusing order of push and pop
  • Assuming pop returns bottom element
  • Ignoring null check in pop
4. The following code attempts to implement a stack using an array but has a bug. What is the error?
class ArrayStack {
  int[] stack = new int[5];
  int top = -1;
  void push(int x) {
    top++;
    stack[top] = x;
  }
}
medium
A. stack array should be declared static
B. top should start at 0, not -1
C. Array size should be dynamic
D. No check for stack overflow before push

Solution

  1. Step 1: Analyze push method

    Push increments top and assigns value without checking if top exceeds array size.
  2. Step 2: Identify missing overflow check

    Without checking top < stack.length, pushing beyond capacity causes ArrayIndexOutOfBoundsException.
  3. Final Answer:

    No check for stack overflow before push -> Option D
  4. Quick Check:

    Missing overflow check = A [OK]
Hint: Always check stack size before pushing [OK]
Common Mistakes:
  • Assuming top starts at 0 is mandatory
  • Thinking array must be dynamic always
  • Confusing static keyword necessity
5. You need to implement a stack for a program where the maximum number of elements is unknown and memory efficiency is important. Which implementation is best and why?
hard
A. Linked list stack, because it grows dynamically and uses memory only as needed.
B. Linked list stack, because it uses less memory overhead per element than arrays.
C. Array stack, because it provides faster push and pop operations always.
D. Array stack, because arrays use less memory per element and resizing is automatic.

Solution

  1. Step 1: Consider unknown max size and memory efficiency

    Unknown max size means dynamic growth is needed; linked list grows as needed without fixed size.
  2. Step 2: Compare memory usage and operation speed

    Linked list uses extra memory per node for pointers but avoids wasted space from large arrays; resizing arrays can be costly.
  3. Step 3: Choose best fit

    Linked list stack fits unknown size and memory efficiency better despite pointer overhead.
  4. Final Answer:

    Linked list stack, because it grows dynamically and uses memory only as needed. -> Option A
  5. Quick Check:

    Dynamic size + memory efficient = D [OK]
Hint: Unknown size? Use linked list stack for dynamic memory [OK]
Common Mistakes:
  • Assuming arrays resize automatically without cost
  • Ignoring pointer memory overhead in linked lists
  • Confusing speed with memory efficiency
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10 questions~5 mineasy hard