Roman to Integer Conversion in DSA Java - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the result variable to zero.

DSA Java

int result = [1];

Drag options to blanks, or click blank then click option'

A-1

B1

C0

Dnull

Attempts:

3 left

💡 Hint

Common Mistakes

Initializing result to 1 or null causes wrong calculations or errors.

The result variable should start at 0 to accumulate the integer value.

2fill in blank

medium

Complete the code to get the integer value of the current Roman numeral character.

DSA Java

int currentVal = romanMap.get([1]);

Drag options to blanks, or click blank then click option'

AromanMap.get(i)

Bs.charAt(0)

Ci

Ds.charAt(i)

Attempts:

3 left

💡 Hint

Common Mistakes

Using the index i directly instead of the character causes errors.

Using s.charAt(0) always gets the first character, not the current one.

We get the character at index i from the string s to find its integer value in the map.

3fill in blank

hard

Fix the error in the if condition to check if the current value is less than the next value.

DSA Java

if (i < s.length() - 1 && currentVal [1] nextVal) {

Drag options to blanks, or click blank then click option'

A<

B>

C==

D>=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' reverses the logic and causes wrong results.

Using '==' or '>=' does not correctly identify subtraction cases.

We check if currentVal is less than nextVal to decide if we subtract currentVal.

4fill in blank

hard

Fill both blanks to correctly update the result when current value is less than next value.

DSA Java

result [1]= currentVal;
} else {
    result [2]= currentVal;
}

Drag options to blanks, or click blank then click option'

A-

B+

C*

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition in both cases causes wrong results.

Using multiplication or division is incorrect for this logic.

Subtract currentVal from result if less than nextVal; otherwise, add it.

5fill in blank

hard

Fill all three blanks to complete the method signature and return statement.

DSA Java

public static int [1](String [2]) {
    // method body
    return [3];
}

Drag options to blanks, or click blank then click option'

AromanToInt

Bs

Cresult

Dconvert

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong method or parameter names causes confusion.

Returning a wrong variable causes errors.

The method name is romanToInt, parameter is s, and we return result.

Practice

1. What is the value of the Roman numeral IX when converted to an integer?

easy

A. 6

B. 11

C. 9

D. 19

Solution

1. Step 1: Understand Roman numeral rules for subtraction

   In Roman numerals, when a smaller numeral appears before a larger one, it is subtracted. Here, I (1) is before X (10), so 1 is subtracted from 10.

2. Step 2: Calculate the integer value

   10 - 1 = 9.

3. Final Answer:

   9 -> Option C

4. Quick Check:

   IX = 9 [OK]

Hint: Subtract when smaller numeral precedes larger one [OK]

Common Mistakes:

• Adding values instead of subtracting
• Confusing IX with XI
• Ignoring subtraction rule

2. Which of the following Java code snippets correctly initializes a map for Roman numeral values?

easy

A. Map map = new HashMap<>(); map.add('I', 1); map.add('V', 5);

B. Map map = Map.of("I", 1, "V", 5, "X", 10);

C. Map map = new Map(); map['I'] = 1; map['V'] = 5;

D. Map map = new HashMap<>(); map.put('I', 1); map.put('V', 5); map.put('X', 10);

Solution

1. Step 1: Check correct Map initialization syntax in Java

   Java requires using a concrete class like HashMap to create a Map instance. Then, use put() method to add key-value pairs.

2. Step 2: Verify each option

   Map map = new HashMap<>(); map.put('I', 1); map.put('V', 5); map.put('X', 10); correctly uses new HashMap<>(), then map.put() calls. B uses Map.of with string keys ("I", etc.) causing type mismatch for Map<Character, Integer>. Options C and D use invalid syntax.

3. Final Answer:

   Map map = new HashMap<>(); map.put('I', 1); map.put('V', 5); map.put('X', 10); -> Option D

4. Quick Check:

   Use HashMap and put() for map initialization [OK]

Hint: Use HashMap and put() to add entries [OK]

Common Mistakes:

• Using invalid Map constructor
• Using map.add() instead of map.put()
• Trying to assign values with brackets

3. What is the output of the following Java code snippet?

String s = "MCMXCIV";
int result = 0;
Map map = Map.of('I',1,'V',5,'X',10,'L',50,'C',100,'D',500,'M',1000);
for (int i = 0; i < s.length(); i++) {
    int value = map.get(s.charAt(i));
    if (i + 1 < s.length() && value < map.get(s.charAt(i + 1))) {
        result -= value;
    } else {
        result += value;
    }
}
System.out.println(result);

medium

A. 1904

B. 1994

C. 1094

D. 1949

Solution

1. Step 1: Understand the Roman numeral string and map values

   The string "MCMXCIV" represents a Roman numeral. Map assigns values: M=1000, C=100, X=10, I=1, V=5.

2. Step 2: Trace the loop and calculate result

   Loop through each character:
   - M(1000), next C(100): 1000 > 100, add 1000
   - C(100), next M(1000): 100 < 1000, subtract 100
   - M(1000), next X(10): 1000 > 10, add 1000
   - X(10), next C(100): 10 < 100, subtract 10
   - C(100), next I(1): 100 > 1, add 100
   - I(1), next V(5): 1 < 5, subtract 1
   - V(5), no next, add 5
   Sum = 1000 - 100 + 1000 - 10 + 100 - 1 + 5 = 1994.

3. Final Answer:

   1994 -> Option B

4. Quick Check:

   MCMXCIV = 1994 [OK]

Hint: Subtract if current < next, else add [OK]

Common Mistakes:

• Adding all values without subtraction
• Incorrectly subtracting when not needed
• Misreading character order

4. The following Java method aims to convert a Roman numeral string to an integer but has a bug. What is the bug?

public int romanToInt(String s) {
    Map map = Map.of('I',1,'V',5,'X',10,'L',50,'C',100,'D',500,'M',1000);
    int result = 0;
    for (int i = 0; i < s.length(); i++) {
        int value = map.get(s.charAt(i));
        if (i + 1 < s.length() && value > map.get(s.charAt(i + 1))) {
            result -= value;
        } else {
            result += value;
        }
    }
    return result;
}

medium

A. The comparison operator should be '<' instead of '>' in the if condition.

B. The map initialization is incorrect and causes runtime error.

C. The loop should start from 1 instead of 0.

D. The method does not handle lowercase Roman numerals.

Solution

1. Step 1: Analyze the if condition logic

   The code subtracts value when current value is greater than next. But Roman numerals subtract when current is less than next.

2. Step 2: Identify the correct comparison operator

   The condition should be value < map.get(next char) to subtract, not value > next value.

3. Final Answer:

   The comparison operator should be '<' instead of '>' in the if condition. -> Option A

4. Quick Check:

   Subtract when current < next [OK]

Hint: Subtract if current numeral is smaller than next [OK]

Common Mistakes:

• Using wrong comparison operator
• Ignoring subtraction rule
• Assuming map initialization error

5. You want to convert a list of Roman numerals ["XL", "IX", "MMXX"] to their integer values using Java. Which approach correctly handles this with minimal code duplication?

hard

A. Write a separate method to convert one Roman numeral to integer, then loop over the list calling this method for each element.

B. Manually convert each Roman numeral in the list with separate code blocks for each string.

C. Use a single loop over the list and convert each character individually without a helper method.

D. Convert only the first Roman numeral and reuse the result for all elements.

Solution

1. Step 1: Identify the need for reusable code

   Converting Roman numerals requires the same logic for each string. Writing a helper method avoids repeating code.

2. Step 2: Use a loop to process the list

   Loop through the list and call the helper method for each Roman numeral string to get its integer value.

3. Final Answer:

   Write a separate method to convert one Roman numeral to integer, then loop over the list calling this method for each element. -> Option A

4. Quick Check:

   Use helper method + loop for clean code [OK]

Hint: Use helper method and loop to avoid repetition [OK]

Common Mistakes:

• Repeating conversion code for each string
• Ignoring code reuse principles
• Using incorrect logic for all elements