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DSA Javaprogramming~5 mins

Longest Palindromic Substring in DSA Java - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is a palindrome?
A palindrome is a word, phrase, number, or sequence of characters that reads the same forward and backward.
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beginner
What does the Longest Palindromic Substring problem ask for?
It asks to find the longest continuous substring within a given string that is a palindrome.
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intermediate
Explain the expand around center approach for finding palindromes.
This approach checks for palindromes by expanding from each character (and between characters) outwards, comparing characters on both sides until they don't match.
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intermediate
Why do we check for both odd and even length palindromes separately?
Because palindromes can have a single center character (odd length) or two center characters (even length), so we expand around one or two centers accordingly.
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intermediate
What is the time complexity of the expand around center method for Longest Palindromic Substring?
The time complexity is O(n^2), where n is the length of the string, because we expand around each character and between characters.
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What is the output of the Longest Palindromic Substring for input "babad"?
A"bad"
B"bab" or "aba"
C"babad"
D"aba" only
Which approach is commonly used to find the longest palindromic substring efficiently?
AExpand around center
BSorting the string
CBinary search on substring length
DUsing a stack
How many centers do we consider in the expand around center approach for a string of length n?
An
Bn - 1
C2n - 1
D2n
What is the minimum length of a palindrome?
A1
B0
C2
D3
If the input string is "cbbd", what is the longest palindromic substring?
A"bd"
B"cbbd"
C"cb"
D"bb"
Describe the steps to find the longest palindromic substring using the expand around center method.
Think about how to check palindromes from the middle outwards.
You got /4 concepts.
    Explain why we need to consider both odd and even length palindromes separately.
    Consider the difference in palindrome shapes.
    You got /3 concepts.

      Practice

      (1/5)
      1. What is the main goal of the Longest Palindromic Substring problem?
      easy
      A. Find the longest substring with all unique characters
      B. Find the longest substring with increasing characters
      C. Find the longest substring that reads the same forwards and backwards
      D. Find the longest substring that contains only vowels

      Solution

      1. Step 1: Understand the problem definition

        The problem asks to find a substring that is a palindrome, meaning it reads the same forwards and backwards.
      2. Step 2: Identify the goal

        Among all palindromic substrings, we want the one with the maximum length.
      3. Final Answer:

        Find the longest substring that reads the same forwards and backwards -> Option C
      4. Quick Check:

        Longest Palindromic Substring = Find palindrome substring [OK]
      Hint: Look for substring that mirrors itself [OK]
      Common Mistakes:
      • Confusing palindrome with unique characters
      • Looking for longest substring without repeats
      • Thinking about character order increasing
      2. Which of the following Java method signatures is correct for a function that returns the longest palindromic substring from a given string s?
      easy
      A. public String longestPalindrome(String s)
      B. public void longestPalindrome(String s)
      C. public int longestPalindrome(String s)
      D. public String longestPalindrome(int s)

      Solution

      1. Step 1: Analyze the return type

        The function should return the longest palindromic substring, which is a String.
      2. Step 2: Check parameter type

        The input is a string, so the parameter should be of type String.
      3. Final Answer:

        public String longestPalindrome(String s) -> Option A
      4. Quick Check:

        Return type String and parameter String = public String longestPalindrome(String s) [OK]
      Hint: Return type matches output, parameter matches input [OK]
      Common Mistakes:
      • Using void return type when output is needed
      • Using int parameter instead of String
      • Returning int instead of String
      3. What will be the output of the following Java code snippet?
      public class Test {
        public static String longestPalindrome(String s) {
          int start = 0, maxLen = 1;
          for (int i = 0; i < s.length(); i++) {
            for (int j = i; j < s.length(); j++) {
              String sub = s.substring(i, j + 1);
              if (isPalindrome(sub) && sub.length() > maxLen) {
                start = i;
                maxLen = sub.length();
              }
            }
          }
          return s.substring(start, start + maxLen);
        }
      
        private static boolean isPalindrome(String str) {
          int left = 0, right = str.length() - 1;
          while (left < right) {
            if (str.charAt(left++) != str.charAt(right--)) return false;
          }
          return true;
        }
      
        public static void main(String[] args) {
          System.out.println(longestPalindrome("babad"));
        }
      }
      medium
      A. "babad"
      B. "aba"
      C. "bad"
      D. "bab"

      Solution

      1. Step 1: Understand the code logic

        The code checks all substrings and updates the longest palindrome found.
      2. Step 2: Trace the input "babad"

        Palindromic substrings include "bab" and "aba" both length 3. The code picks the first found longest palindrome, which is "bab".
      3. Final Answer:

        "bab" -> Option D
      4. Quick Check:

        First longest palindrome found = "bab" [OK]
      Hint: Check first longest palindrome substring found [OK]
      Common Mistakes:
      • Assuming "aba" is returned instead of "bab"
      • Thinking entire string is palindrome
      • Ignoring substring length comparison
      4. Identify the bug in the following code snippet for finding the longest palindromic substring:
      public String longestPalindrome(String s) {
        int maxLen = 0, start = 0;
        for (int i = 0; i < s.length(); i++) {
          for (int j = i; j < s.length(); j++) {
            String sub = s.substring(i, j);
            if (isPalindrome(sub) && sub.length() > maxLen) {
              maxLen = sub.length();
              start = i;
            }
          }
        }
        return s.substring(start, start + maxLen);
      }
      medium
      A. The loop should start from j = i + 1
      B. The substring end index should be j + 1, not j
      C. maxLen should be initialized to 1, not 0
      D. The isPalindrome method is missing

      Solution

      1. Step 1: Check substring usage

        Java substring method excludes the end index, so substring(i, j) misses character at j.
      2. Step 2: Correct substring end index

        It should be substring(i, j + 1) to include character at position j.
      3. Final Answer:

        The substring end index should be j + 1, not j -> Option B
      4. Quick Check:

        substring(i, j + 1) includes full substring [OK]
      Hint: Remember substring excludes end index [OK]
      Common Mistakes:
      • Using substring(i, j) which excludes last char
      • Not updating maxLen correctly
      • Ignoring substring indexing rules
      5. Given the string "forgeeksskeegfor", which approach will efficiently find the longest palindromic substring and what is the substring?
      hard
      A. Dynamic programming with memoization; longest palindrome is "geeksskeeg"
      B. Brute force checking all substrings; longest palindrome is "forgeeksskeegfor"
      C. Expand around center approach; longest palindrome is "sskeeg"
      D. Sorting characters and checking; longest palindrome is "sskeeg"

      Solution

      1. Step 1: Identify efficient methods

        Dynamic programming and expand around center are efficient for this problem; brute force is slow.
      2. Step 2: Check longest palindrome in given string

        "geeksskeeg" is the longest palindromic substring inside "forgeeksskeegfor".
      3. Step 3: Match approach and answer

        Dynamic programming with memoization is a common efficient approach returning "geeksskeeg".
      4. Final Answer:

        Dynamic programming with memoization; longest palindrome is "geeksskeeg" -> Option A
      5. Quick Check:

        DP approach finds "geeksskeeg" efficiently [OK]
      Hint: Use DP or center expansion for efficiency [OK]
      Common Mistakes:
      • Assuming entire string is palindrome
      • Using brute force for large strings
      • Sorting characters loses substring order
      Recommended

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      10 questions~5 mineasy hard