Insert at End of Doubly Linked List in DSA Java - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is a doubly linked list?

A doubly linked list is a chain of nodes where each node has three parts: data, a link to the next node, and a link to the previous node. This allows moving forward and backward through the list.

beginner

What steps are needed to insert a new node at the end of a doubly linked list?

1. Create a new node with the given data.
2. If the list is empty, make the new node the head.
3. Otherwise, traverse to the last node.
4. Set the last node's next to the new node.
5. Set the new node's previous to the last node.
6. Set the new node's next to null.

beginner

Why do we need to update the previous pointer of the new node when inserting at the end?

Because the new node must know which node comes before it to maintain the doubly linked structure, allowing backward traversal.

intermediate

What happens if you forget to set the new node's next pointer to null when inserting at the end?

The list may have incorrect links, causing traversal errors or infinite loops because the new node might point to an unexpected node.

beginner

Show the Java code snippet to insert a node at the end of a doubly linked list.

public void insertAtEnd(int data) { Node newNode = new Node(data); if (head == null) { head = newNode; return; } Node temp = head; while (temp.next != null) { temp = temp.next; } temp.next = newNode; newNode.prev = temp; newNode.next = null; }

What pointer of the new node must be set to the last node when inserting at the end of a doubly linked list?

A next

B prev

C head

D tail

The new node's prev pointer must point to the last node to maintain backward links.

If the doubly linked list is empty, what should the new node become after insertion at the end?

A The head node

B The tail node only

C A middle node

D It should not be inserted

When the list is empty, the new node becomes the head (and tail) of the list.

Which of these is NOT a correct step when inserting at the end of a doubly linked list?

A Set last node's next to new node

B Set new node's next to null

C Traverse to the last node

D Set new node's prev to null

The new node's prev should point to the last node, not null.

What is the time complexity of inserting at the end of a doubly linked list if you do not maintain a tail pointer?

A O(log n)

B O(1)

C O(n)

D O(n^2)

Without a tail pointer, you must traverse the list to find the last node, which takes O(n) time.

What will happen if you forget to update the last node's next pointer when inserting at the end?

A The new node will be unreachable from the list

B The list will become circular

C The new node will become the head

D The list will be sorted

If last node's next is not updated, the new node is not linked and unreachable.

Explain step-by-step how to insert a new node at the end of a doubly linked list.

Think about how the links between nodes must change.

Describe why doubly linked lists need both next and prev pointers when inserting nodes.

Consider how you move through the list in both directions.

Practice

1. What is the main purpose of inserting a node at the end of a doubly linked list?

easy

A. To reverse the list

B. To remove the first node

C. To add a new element after the last node

D. To find the middle node

Solution

1. Step 1: Understand the structure of a doubly linked list

   A doubly linked list has nodes connected both forward and backward, allowing traversal in both directions.

2. Step 2: Purpose of insertion at the end

   Inserting at the end means adding a new node after the current last node, updating pointers accordingly.

3. Final Answer:

   To add a new element after the last node -> Option C

4. Quick Check:

   Insert at end = Add after last node [OK]

Hint: Insert at end means add after last node [OK]

Common Mistakes:

• Confusing insertion at end with deletion
• Thinking insertion at end reverses the list
• Assuming insertion at end finds middle node

2. Which of the following is the correct way to update the 'next' pointer of the last node when inserting a new node at the end in Java?

easy

A. last.next = newNode;

B. newNode.next = last;

C. last.prev = newNode;

D. newNode.prev = null;

Solution

1. Step 1: Identify the last node's next pointer

   The last node's 'next' pointer should point to the new node being inserted.

2. Step 2: Correct assignment for insertion

   Assigning 'last.next = newNode;' correctly links the last node to the new node.

3. Final Answer:

   last.next = newNode; -> Option A

4. Quick Check:

   Last node's next points to new node [OK]

Hint: Last node's next must point to new node [OK]

Common Mistakes:

• Assigning newNode.next to last instead of last.next to newNode
• Changing last.prev instead of last.next
• Setting newNode.prev to null incorrectly

3. What will be the output of the following code snippet after inserting 40 at the end of the doubly linked list?

class Node {
  int data;
  Node next, prev;
  Node(int d) { data = d; next = prev = null; }
}

class DoublyLinkedList {
  Node head;
  void insertEnd(int data) {
    Node newNode = new Node(data);
    if (head == null) {
      head = newNode;
      return;
    }
    Node last = head;
    while (last.next != null) last = last.next;
    last.next = newNode;
    newNode.prev = last;
  }
  void printList() {
    Node temp = head;
    while (temp != null) {
      System.out.print(temp.data + " <-> ");
      temp = temp.next;
    }
    System.out.println("null");
  }
}

public class Main {
  public static void main(String[] args) {
    DoublyLinkedList dll = new DoublyLinkedList();
    dll.insertEnd(10);
    dll.insertEnd(20);
    dll.insertEnd(30);
    dll.insertEnd(40);
    dll.printList();
  }
}

medium

A. 10 <-> 20 <-> 30 <-> 40 <-> null

B. 40 <-> 10 <-> 20 <-> 30 <-> null

C. 10 <-> 20 <-> 30 <-> null

D. null

Solution

1. Step 1: Trace insertions in order

   Nodes 10, 20, 30, then 40 are inserted at the end, so list grows as 10 <-> 20 <-> 30 <-> 40.

2. Step 2: Print list traversal

   Print starts at head (10) and moves forward printing each node's data followed by ' <-> ', ending with 'null'.

3. Final Answer:

   10 <-> 20 <-> 30 <-> 40 <-> null -> Option A

4. Quick Check:

   Insertion at end appends nodes in order [OK]

Hint: Insertion order matches printed list [OK]

Common Mistakes:

• Assuming new node is added at start
• Forgetting to update newNode.prev
• Printing list incorrectly or missing null

4. Identify the error in the following insertEnd method for a doubly linked list:

void insertEnd(int data) {
  Node newNode = new Node(data);
  if (head == null) {
    head = newNode;
  } else {
    Node last = head;
    while (last.next != null) {
      last = last.next;
    }
    last.next = newNode;
    newNode.next = last;
  }
}

medium

A. last.next should be set to head

B. The while loop condition should be last.prev != null

C. head should be updated to newNode when list is empty

D. newNode.next should be set to null, not last

Solution

1. Step 1: Analyze pointer assignments after loop

   After finding last node, last.next is set to newNode correctly, but newNode.next is wrongly set to last (previous node).

2. Step 2: Correct pointer for newNode.next

   Since newNode is last, its next should be null, and newNode.prev should point to last.

3. Final Answer:

   newNode.next should be set to null, not last -> Option D

4. Quick Check:

   Last node's next = newNode; newNode.next = null [OK]

Hint: Last node's next points newNode; newNode.next is null [OK]

Common Mistakes:

• Setting newNode.next to last instead of null
• Not updating newNode.prev to last
• Incorrect loop condition in while

5. Given a doubly linked list with nodes 5 <-> 15 <-> 25, write the sequence of pointer updates needed to insert a new node with value 35 at the end. Which of the following correctly describes the steps?

hard

A. Set newNode.prev and newNode.next to null, head to newNode

B. Set newNode.prev to last node, last.next to newNode, newNode.next to null

C. Set newNode.next to last node, last.prev to newNode, newNode.prev to null

D. Set last.next to null, newNode.prev to null, newNode.next to last

Solution

1. Step 1: Identify last node and new node pointers

   The last node is 25; newNode is 35. For insertion at end, newNode.prev must point to last node, and last.next must point to newNode.

2. Step 2: Set newNode.next to null

   Since newNode is now last, its next pointer must be null to mark list end.

3. Final Answer:

   Set newNode.prev to last node, last.next to newNode, newNode.next to null -> Option B

4. Quick Check:

   Insert at end updates prev and next pointers correctly [OK]

Hint: New node prev = last; last next = new node; new node next = null [OK]

Common Mistakes:

• Swapping prev and next pointers incorrectly
• Not setting newNode.next to null
• Changing head pointer unnecessarily