What does 'enqueue' mean in the context of a queue data structure?
Enqueue means adding an element to the end (rear) of the queue.
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beginner
In a linked list implementation of a queue, where is the new node added during enqueue?
The new node is added at the rear (tail) of the linked list.
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intermediate
Why do we keep a reference to the rear node in a linked list queue?
To quickly add new nodes at the end without traversing the whole list.
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beginner
What happens if the queue is empty when we enqueue a new element using a linked list?
Both front and rear pointers are set to the new node because it is the only element.
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intermediate
Show the basic steps to enqueue an element in a linked list queue.
1. Create a new node with the data. 2. If queue is empty, set front and rear to new node. 3. Else, set rear.next to new node and update rear to new node.
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What pointer is updated when you enqueue a new element in a linked list queue?
ARear pointer
BFront pointer
CBoth front and rear pointers
DNeither front nor rear pointers
✗ Incorrect
When enqueuing, the rear pointer moves to the new node at the end.
If the queue is empty, what happens when you enqueue the first element?
AOnly rear pointer is updated
BBoth front and rear pointers point to the new node
CNo pointers are updated
DOnly front pointer is updated
✗ Incorrect
For the first element, front and rear both point to the new node.
What is the time complexity of enqueue operation in a linked list queue?
AO(n^2)
BO(n)
CO(log n)
DO(1)
✗ Incorrect
Enqueue is O(1) because we add at the rear directly using the rear pointer.
Which of these is NOT needed to enqueue in a linked list queue?
ATraverse the entire list
BCreate a new node
CUpdate rear.next
DUpdate rear pointer
✗ Incorrect
Traversal is not needed because rear pointer gives direct access to the end.
What happens to the rear pointer after enqueueing a new node?
AIt stays the same
BIt moves to the front node
CIt moves to the new node
DIt becomes null
✗ Incorrect
Rear pointer moves to the newly added node at the end.
Explain how to enqueue an element in a queue implemented using a linked list.
Think about what happens when the queue is empty versus when it has elements.
You got /5 concepts.
Why is it efficient to keep a rear pointer in a linked list queue for enqueue operations?
Consider what would happen if you only had a front pointer.
You got /4 concepts.
Practice
(1/5)
1. What does the enqueue operation do in a linked list implementation of a queue?
easy
A. Adds an element at the end (rear) of the linked list
B. Removes an element from the front of the linked list
C. Deletes the entire linked list
D. Adds an element at the front (head) of the linked list
Solution
Step 1: Understand enqueue operation in queue
Enqueue means adding an element to the queue, which is done at the rear end.
Step 2: Linked list enqueue adds at the rear
In linked list, adding at the rear means inserting the new node at the end of the list.
Final Answer:
Adds an element at the end (rear) of the linked list -> Option A
Quick Check:
Enqueue = add at rear [OK]
Hint: Enqueue always adds at the rear of the queue [OK]
Common Mistakes:
Confusing enqueue with dequeue operation
Thinking enqueue adds at the front
Mixing linked list head and tail roles
2. Which of the following is the correct way to create a new node for enqueue in Java linked list?
easy
A. Node newNode = new Node(); newNode.data = value; newNode.next = null;
B. Node newNode = Node(value); newNode.next = null;
C. Node newNode = new Node(value); newNode.next = null;
D. Node newNode = new Node; newNode.data = value;
Solution
Step 1: Understand Java object creation syntax
In Java, to create an object with a constructor that takes a value, use new Node(value).
Step 2: Check next pointer initialization
After creating the node, set next to null to mark end of list.
Final Answer:
Node newNode = new Node(value); newNode.next = null; -> Option C
Quick Check:
Java new object with constructor = new Node(value) [OK]
Hint: Use 'new' keyword with constructor for object creation [OK]
Common Mistakes:
Missing 'new' keyword when creating object
Incorrect constructor call syntax
Not setting next pointer to null
3. What will be the state of the queue after the following enqueue operations on an empty linked list queue?
enqueue(10); enqueue(20); enqueue(30);
medium
A. 10 -> 20 -> 30 -> null
B. 30 -> 20 -> 10 -> null
C. null -> 10 -> 20 -> 30
D. 20 -> 10 -> 30 -> null
Solution
Step 1: Enqueue 10 on empty queue
Queue becomes: 10 -> null
Step 2: Enqueue 20 and 30 sequentially
After enqueue(20): 10 -> 20 -> null After enqueue(30): 10 -> 20 -> 30 -> null
Final Answer:
10 -> 20 -> 30 -> null -> Option A
Quick Check:
Enqueue adds at rear, order preserved [OK]
Hint: Enqueue adds at rear, so order is insertion order [OK]
Common Mistakes:
Reversing order of elements after enqueue
Confusing enqueue with push (stack)
Assuming new elements added at front
4. Identify the error in the following enqueue method for a linked list queue:
void enqueue(int value) {
Node newNode = new Node(value);
if (rear == null) {
front = newNode;
} else {
rear.next = newNode;
}
}
medium
A. Should set front.next to newNode instead of rear.next
B. Missing update of rear pointer to newNode
C. New node should be created with next pointing to front
D. Should check if front is null instead of rear
Solution
Step 1: Analyze enqueue logic
When queue is empty, front is set to newNode but rear is not updated.
Step 2: Check rear pointer update
After adding newNode, rear should point to newNode to keep track of last element.
Final Answer:
Missing update of rear pointer to newNode -> Option B
Quick Check:
Rear must always point to last node [OK]
Hint: Always update rear to new node after enqueue [OK]
Common Mistakes:
Forgetting to update rear pointer
Updating front.next instead of rear.next
Not handling empty queue case properly
5. Given a linked list queue with elements 5 -> 15 -> 25 -> null, what will be the queue state after enqueueing 35 and then dequeueing one element?
hard
A. 35 -> 15 -> 25 -> null
B. 5 -> 15 -> 25 -> 35 -> null
C. 25 -> 35 -> null
D. 15 -> 25 -> 35 -> null
Solution
Step 1: Enqueue 35 at rear
Queue becomes: 5 -> 15 -> 25 -> 35 -> null
Step 2: Dequeue removes front element 5
After dequeue: 15 -> 25 -> 35 -> null
Final Answer:
15 -> 25 -> 35 -> null -> Option D
Quick Check:
Enqueue adds rear, dequeue removes front [OK]
Hint: Enqueue rear, dequeue front; order shifts accordingly [OK]
Common Mistakes:
Removing wrong element on dequeue
Adding new element at front instead of rear
Not updating front pointer after dequeue
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