Array Deletion at End in DSA Java - Build from Scratch

Array Deletion at End

📖 Scenario: You are managing a list of tasks to do today. Sometimes, you finish the last task and want to remove it from your list.

🎯 Goal: Build a simple Java program that stores tasks in an array and removes the last task when done.

📋 What You'll Learn

Create an array of tasks with exact values

Use a variable to track the current number of tasks

Write code to remove the last task by decreasing the count

Print the tasks remaining after deletion

💡 Why This Matters

🌍 Real World

Managing a list of tasks or items where you often remove the last item after completing it.

💼 Career

Understanding how to manage arrays and track their size is important for many programming jobs, especially when working with fixed-size data collections.

1

Create the tasks array

Create a String array called tasks with these exact values: "Laundry", "Dishes", "Homework", "Shopping", "Exercise".

DSA Java

// Your code here

Hint

Use String[] tasks = {"Laundry", "Dishes", "Homework", "Shopping", "Exercise"}; to create the array.

2

Add a variable to track task count

Add an integer variable called taskCount and set it to 5 to track how many tasks are currently in the array.

DSA Java

public class Main {
    public static void main(String[] args) {
        String[] tasks = {"Laundry", "Dishes", "Homework", "Shopping", "Exercise"};
        // Your code here
    }
}

Hint

Use int taskCount = 5; to keep track of tasks.

3

Remove the last task

Decrease the value of taskCount by 1 to remove the last task from the list.

DSA Java

public class Main {
    public static void main(String[] args) {
        String[] tasks = {"Laundry", "Dishes", "Homework", "Shopping", "Exercise"};
        int taskCount = 5;
        // Decrease taskCount by 1
    }
}

Hint

Use taskCount = taskCount - 1; to remove the last task.

4

Print remaining tasks

Use a for loop with variable i from 0 to less than taskCount to print each remaining task in tasks on its own line.

DSA Java

public class Main {
    public static void main(String[] args) {
        String[] tasks = {"Laundry", "Dishes", "Homework", "Shopping", "Exercise"};
        int taskCount = 5;
        taskCount = taskCount - 1;
        // Print tasks from 0 to taskCount - 1
    }
}

Hint

Use a for loop: for (int i = 0; i < taskCount; i++) and print tasks[i].

Practice

1. What happens when you delete an element from the end of a fixed-size array in Java?

easy

A. The last element is removed and the array size decreases by one

B. The last element is set to zero or null but the array size stays the same

C. All elements shift left by one position

D. The array is completely cleared

Solution

1. Step 1: Understand fixed-size array behavior

   Java arrays have a fixed size once created, so their length cannot change.

2. Step 2: Effect of deleting at end

   Deleting means logically ignoring the last element or setting it to default (0 or null), but the array length remains unchanged.

3. Final Answer:

   The last element is set to zero or null but the array size stays the same -> Option B

4. Quick Check:

   Fixed-size array length unchanged on deletion [OK]

Hint: Fixed arrays keep size; deletion just clears last element [OK]

Common Mistakes:

• Thinking array size shrinks automatically
• Assuming elements shift after deletion
• Believing array clears fully on one deletion

2. Which of the following is the correct syntax to delete the last element from an array named arr in Java by reducing its logical size stored in size?

easy

A. arr[size--] = 0;

B. arr[size] = 0; size--;

C. size--; arr[size] = 0;

D. arr[size] = null; size++;

Solution

1. Step 1: Understand logical deletion

   To delete last element, first reduce size by one, then clear that element.

2. Step 2: Check syntax correctness

   size--; arr[size] = 0; reduces size first (size--) then sets arr[size] to 0, correctly deleting last element.

3. Final Answer:

   size--; arr[size] = 0; -> Option C

4. Quick Check:

   Decrease size before clearing element [OK]

Hint: Decrease size first, then clear element [OK]

Common Mistakes:

• Clearing element before decreasing size
• Using post-decrement incorrectly
• Increasing size instead of decreasing

3. What will be the output of the following Java code?

int[] arr = {10, 20, 30, 40, 50};
int size = 5;
size--;
arr[size] = 0;
for(int i = 0; i < size; i++) {
    System.out.print(arr[i] + " ");
}

medium

A. 10 20 30 0 0

B. 10 20 30 40 0

C. 10 20 30 40 50

D. 10 20 30 40

Solution

1. Step 1: Understand size decrement and element clearing

   Size is reduced from 5 to 4, then arr[4] is set to 0, removing last element logically.

2. Step 2: Loop prints elements from index 0 to 3

   Loop runs i=0 to 3, printing arr[0]=10, arr[1]=20, arr[2]=30, arr[3]=40.

3. Final Answer:

   10 20 30 40 -> Option D

4. Quick Check:

   Last element removed, loop prints first 4 elements [OK]

Hint: Loop runs till size, last element skipped after decrement [OK]

Common Mistakes:

• Printing all 5 elements ignoring size
• Not updating last element to zero
• Confusing array index with size

4. Identify the error in this Java code snippet that tries to delete the last element from an array:

int[] arr = {1, 2, 3, 4};
int size = 4;
arr[size] = 0;
size--;

medium

A. Array index out of bounds error at arr[size] = 0;

B. Size variable is not decremented

C. Array elements are not shifted left

D. No error, code works fine

Solution

1. Step 1: Check array indexing

   Array indices go from 0 to size-1, so arr[size] is out of bounds.

2. Step 2: Identify correct order

   Must decrement size first, then access arr[size] to avoid error.

3. Final Answer:

   Array index out of bounds error at arr[size] = 0; -> Option A

4. Quick Check:

   Accessing arr[size] causes error [OK]

Hint: Decrement size before accessing arr[size] [OK]

Common Mistakes:

• Accessing arr[size] directly
• Not decrementing size before deletion
• Ignoring array index limits

5. You have an array int[] arr = {5, 10, 15, 20, 25} and a variable size = 5. You want to logically delete the last two elements without modifying the values in the array and print the remaining elements. Which code snippet correctly does this?

hard

A. size -= 2;
for(int i = 0; i < size; i++) System.out.print(arr[i] + " ");

B. arr[size-1] = 0; arr[size-2] = 0; size -= 2;
for(int i = 0; i < size; i++) System.out.print(arr[i] + " ");

C. size -= 2;
arr[size] = 0; arr[size+1] = 0;
for(int i = 0; i < size; i++) System.out.print(arr[i] + " ");

D. for(int i = 0; i < size-2; i++) System.out.print(arr[i] + " ");

Solution

1. Step 1: Reduce logical size by 2

   Decreasing size by 2 means last two elements are ignored logically.

2. Step 2: Print elements up to new size

   Loop from 0 to size-1 prints remaining elements correctly.

3. Final Answer:

   size -= 2; for(int i = 0; i < size; i++) System.out.print(arr[i] + " "); -> Option A

4. Quick Check:

   Logical size controls printed elements [OK]

Hint: Reduce size, then print up to size [OK]

Common Mistakes:

• Setting elements to zero before reducing size
• Printing without adjusting size
• Accessing invalid indices after deletion