Why Shortest Path in Unweighted Graph Using BFS in DSA Go?

The Big Idea

What if you could always find the quickest way without guessing or getting lost?

The Scenario

Imagine you are in a city with many streets and intersections. You want to find the shortest way to walk from your home to a friend's house without knowing the map well.

If you try to remember every street and guess the way manually, it can be confusing and take a long time.

The Problem

Trying to find the shortest path by guessing or checking every possible route by hand is slow and easy to get wrong.

You might miss a shorter street or go in circles, wasting time and energy.

The Solution

Using Breadth-First Search (BFS) on the city map (graph) helps you explore all nearby streets first, then gradually move farther.

This way, you find the shortest path quickly and without missing any better routes.

Before vs After

✗ Before

func findPath(graph map[int][]int, start, end int) []int {
    // Try all paths manually - very complex and slow
    return nil
}

✓ After

func findShortestPath(graph map[int][]int, start, end int) []int {
    // Use BFS to find shortest path efficiently
    return bfsShortestPath(graph, start, end)
}

What It Enables

You can quickly find the shortest route in any network without guessing or missing better options.

Real Life Example

Navigation apps use BFS-like methods to find the shortest walking or driving route on city maps.

Key Takeaways

Manual path finding is slow and error-prone.

BFS explores neighbors level by level to find shortest paths.

This method works well for unweighted graphs like city streets.

Practice

1. What does BFS (Breadth-First Search) help find in an unweighted graph?

easy

A. The node with the highest degree

B. The longest path in the graph

C. The shortest path from a start node to all other nodes

D. The minimum spanning tree

Solution

1. Step 1: Understand BFS traversal

   BFS explores nodes level by level starting from the source node, visiting all neighbors before moving deeper.

2. Step 2: BFS finds shortest paths in unweighted graphs

   Because BFS visits nodes in order of increasing distance, the first time it reaches a node is via the shortest path.

3. Final Answer:

   The shortest path from a start node to all other nodes -> Option C

4. Quick Check:

   BFS = Shortest path in unweighted graph [OK]

Hint: BFS visits nodes by distance layers to find shortest paths [OK]

Common Mistakes:

• Confusing BFS with DFS for shortest path
• Thinking BFS finds longest paths
• Mixing BFS with minimum spanning tree algorithms

2. Which Go data structure is best to implement the queue needed for BFS?

easy

A. map

B. channel

C. struct

D. slice

Solution

1. Step 1: Identify queue requirements in BFS

   BFS requires a FIFO (first-in, first-out) structure to process nodes in order.

2. Step 2: Use slice as queue in Go

   Slices can be used to append at the end and remove from the front, effectively acting as a queue.

3. Final Answer:

   slice -> Option D

4. Quick Check:

   Queue for BFS = slice [OK]

Hint: Use slice with append and slicing for queue in Go [OK]

Common Mistakes:

• Using map which is unordered
• Using struct without queue logic
• Using channel without concurrency context

3. What is the output distance array after running BFS from node 0 on this graph?

graph := [][]int{
  {1, 2},
  {0, 3},
  {0, 3},
  {1, 2, 4},
  {3},
}

medium

A. [0, 1, 1, 2, 3]

B. [0, 1, 2, 3, 4]

C. [0, 1, 1, 1, 2]

D. [0, 2, 2, 3, 4]

Solution

1. Step 1: Initialize distances and start BFS from node 0

   Distance[0] = 0, others = -1 (unvisited). Queue starts with 0.

2. Step 2: Visit neighbors level by level

   From 0: neighbors 1 and 2 get distance 1. From 1 and 2: neighbor 3 gets distance 2. From 3: neighbor 4 gets distance 3.

3. Final Answer:

   [0, 1, 1, 2, 3] -> Option A

4. Quick Check:

   Distances = [0,1,1,2,3] [OK]

Hint: Track BFS layers to assign distances incrementally [OK]

Common Mistakes:

• Assigning wrong distances to neighbors
• Confusing node indices
• Not initializing distances properly

4. Identify the bug in this BFS code snippet for shortest path:

func BFS(graph [][]int, start int) []int {
  dist := make([]int, len(graph))
  for i := range dist {
    dist[i] = -1
  }
  dist[start] = 0
  queue := []int{start}
  for len(queue) > 0 {
    node := queue[0]
    queue = queue[1:]
    for _, neighbor := range graph[node] {
      if dist[neighbor] == 0 {
        dist[neighbor] = dist[node] + 1
        queue = append(queue, neighbor)
      }
    }
  }
  return dist
}

medium

A. dist[neighbor] == 0 should be dist[neighbor] == -1

B. queue initialization is wrong

C. dist[start] should be -1

D. for loop over neighbors is incorrect

Solution

1. Step 1: Check distance initialization and visit condition

   Distances start at -1 for unvisited nodes. The condition to visit neighbors should check for -1, not 0.

2. Step 2: Fix condition to correctly detect unvisited neighbors

   Change if dist[neighbor] == 0 to if dist[neighbor] == -1 to avoid skipping nodes.

3. Final Answer:

   dist[neighbor] == 0 should be dist[neighbor] == -1 -> Option A

4. Quick Check:

   Check unvisited with -1, not 0 [OK]

Hint: Use -1 to mark unvisited nodes in BFS distance array [OK]

Common Mistakes:

• Checking visited nodes incorrectly
• Initializing distances with zero
• Modifying queue incorrectly

5. Given a graph with nodes 0 to 5 and edges:

0-1, 0-2, 1-3, 2-3, 3-4, 4-5

What is the shortest path from node 0 to node 5 using BFS?

hard

A. [0, 2, 3, 4, 5]

B. [0, 1, 3, 4, 5]

C. [0, 1, 2, 3, 4, 5]

D. [0, 2, 4, 5]

Solution

1. Step 1: Explore neighbors from node 0

   From 0, neighbors are 1 and 2. Both at distance 1.

2. Step 2: Explore neighbors from 1 and 2

   From 1: neighbor 3; from 2: neighbor 3. Node 3 is at distance 2.

3. Step 3: Explore neighbors from 3, then 4, then 5

   From 3: neighbor 4 (distance 3). From 4: neighbor 5 (distance 4). Path is 0->1->3->4->5 or 0->2->3->4->5.

4. Step 4: Choose shortest path with earliest discovery

   BFS discovers 1 before 2, so path is [0,1,3,4,5].

5. Final Answer:

   [0, 1, 3, 4, 5] -> Option B

6. Quick Check:

   Shortest path BFS = [0,1,3,4,5] [OK]

Hint: BFS finds shortest path by earliest node discovery [OK]

Common Mistakes:

• Choosing longer paths ignoring BFS order
• Skipping nodes in path reconstruction
• Confusing path with distance array