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DSA Goprogramming~10 mins

Fibonacci Using DP in DSA Go - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize the memoization slice for Fibonacci calculation.

DSA Go
memo := make([]int, [1])
Drag options to blanks, or click blank then click option'
An+1
Bn
Cn-1
D2*n
Attempts:
3 left
💡 Hint
Common Mistakes
Using size n causes index out of range errors.
Using size n-1 misses the last Fibonacci number.
2fill in blank
medium

Complete the code to check if Fibonacci value is already computed.

DSA Go
if memo[[1]] != 0 {
    return memo[n]
}
Drag options to blanks, or click blank then click option'
A0
Bn-1
Cn+1
Dn
Attempts:
3 left
💡 Hint
Common Mistakes
Checking memo[n-1] or memo[n+1] causes wrong caching.
Checking memo[0] ignores the current n.
3fill in blank
hard

Fix the error in the recursive Fibonacci call to use memoization correctly.

DSA Go
memo[n] = fibMemo(n-1, memo) [1] fibMemo(n-2, memo)
Drag options to blanks, or click blank then click option'
A+
B-
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using minus or multiplication changes the sequence.
Using division causes runtime errors.
4fill in blank
hard

Fill both blanks to complete the base case check for Fibonacci.

DSA Go
if n [1] 0 || n [2] 1 {
    return n
}
Drag options to blanks, or click blank then click option'
A<=
B==
C>=
D!=
Attempts:
3 left
💡 Hint
Common Mistakes
Using inequalities causes wrong base case handling.
Using != leads to incorrect returns.
5fill in blank
hard

Fill all three blanks to complete the memoized Fibonacci function.

DSA Go
func fibMemo(n int, memo []int) int {
    if n [1] 0 || n [2] 1 {
        return n
    }
    if memo[[3]] != 0 {
        return memo[n]
    }
    memo[n] = fibMemo(n-1, memo) + fibMemo(n-2, memo)
    return memo[n]
}
Drag options to blanks, or click blank then click option'
A==
B<=
Cn
D!=
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong operators for base cases.
Checking memo at wrong index.

Practice

(1/5)
1. What is the main advantage of using Dynamic Programming (DP) to calculate Fibonacci numbers compared to a simple recursive approach?
easy
A. It avoids repeated calculations by storing intermediate results.
B. It uses less memory by not storing any results.
C. It calculates Fibonacci numbers randomly.
D. It uses recursion without any optimization.

Solution

  1. Step 1: Understand recursion inefficiency

    Simple recursion recalculates the same Fibonacci values multiple times, causing exponential time complexity.
  2. Step 2: Role of DP in optimization

    DP stores previously computed Fibonacci numbers in a table (memoization or tabulation), avoiding repeated work and improving efficiency.
  3. Final Answer:

    It avoids repeated calculations by storing intermediate results. -> Option A
  4. Quick Check:

    DP stores results = avoids repeats [OK]
Hint: DP saves past results to speed up Fibonacci calculation [OK]
Common Mistakes:
  • Thinking DP uses less memory than recursion
  • Believing DP calculates values randomly
  • Confusing DP with plain recursion
2. Which of the following Go code snippets correctly initializes a slice to store Fibonacci numbers for DP with size n?
easy
A. fib := new(int)
B. fib := make([]int, n+1)
C. fib := []int{n}
D. fib := [n]int{}

Solution

  1. Step 1: Understand slice initialization

    To store Fibonacci numbers up to n, we need a slice of length n+1 to hold indices 0 through n.
  2. Step 2: Check each option

    fib := make([]int, n+1) uses make with length n+1, correctly creating a slice. fib := []int{n} creates a slice with one element n, not size n+1. fib := new(int) creates a pointer to int, not a slice. fib := [n]int{} is invalid syntax for slice.
  3. Final Answer:

    fib := make([]int, n+1) -> Option B
  4. Quick Check:

    make slice with n+1 length = correct [OK]
Hint: Use make([]int, n+1) to create DP slice for Fibonacci [OK]
Common Mistakes:
  • Using array syntax instead of slice
  • Creating pointer instead of slice
  • Initializing slice with wrong length
3. What is the output of the following Go code snippet?
func fibDP(n int) int {
    fib := make([]int, n+1)
    fib[0], fib[1] = 0, 1
    for i := 2; i <= n; i++ {
        fib[i] = fib[i-1] + fib[i-2]
    }
    return fib[n]
}

fmt.Println(fibDP(5))
medium
A. 13
B. 8
C. 3
D. 5

Solution

  1. Step 1: Trace Fibonacci values in slice

    fib[0]=0, fib[1]=1; then fib[2]=1, fib[3]=2, fib[4]=3, fib[5]=5.
  2. Step 2: Return fib[5]

    The function returns fib[5], which is 5.
  3. Final Answer:

    5 -> Option D
  4. Quick Check:

    Fibonacci(5) = 5 [OK]
Hint: Trace fib array from 0 to n to find fib[n] [OK]
Common Mistakes:
  • Confusing index with Fibonacci value
  • Returning fib[n-1] instead of fib[n]
  • Off-by-one errors in loop
4. Identify the error in this Go function for Fibonacci using DP and select the fix:
func fibDP(n int) int {
    fib := make([]int, n)
    fib[0], fib[1] = 0, 1
    for i := 2; i <= n; i++ {
        fib[i] = fib[i-1] + fib[i-2]
    }
    return fib[n]
}
medium
A. Return fib[n-1] instead of fib[n].
B. Initialize fib[0] and fib[1] to 1 and 1.
C. Change slice size to n+1 to avoid index out of range.
D. Change loop to for i := 1; i < n; i++.

Solution

  1. Step 1: Check slice size and indexing

    Slice fib is created with length n, but loop and return access fib[n], which is out of range.
  2. Step 2: Fix slice size

    Increase slice size to n+1 so fib[n] is valid and no runtime error occurs.
  3. Final Answer:

    Change slice size to n+1 to avoid index out of range. -> Option C
  4. Quick Check:

    Slice size must cover all indices accessed [OK]
Hint: Slice length must be at least n+1 for fib[n] access [OK]
Common Mistakes:
  • Not increasing slice size causes runtime panic
  • Changing initial values incorrectly
  • Modifying loop incorrectly causing wrong results
5. You want to compute the 10th Fibonacci number using DP but with constant space (only two variables). Which Go code snippet correctly implements this optimization?
hard
A. func fib(n int) int { a, b := 0, 1 for i := 2; i <= n; i++ { a, b = b, a+b } return b }
B. func fib(n int) int { fib := make([]int, n+1) fib[0], fib[1] = 0, 1 for i := 2; i <= n; i++ { fib[i] = fib[i-1] + fib[i-2] } return fib[n] }
C. func fib(n int) int { if n <= 1 { return n } return fib(n-1) + fib(n-2) }
D. func fib(n int) int { a, b := 0, 1 for i := 1; i < n; i++ { a = b b = a + b } return a }

Solution

  1. Step 1: Understand constant space DP

    We only keep last two Fibonacci numbers and update them iteratively to save space.
  2. Step 2: Analyze options

    func fib(n int) int { a, b := 0, 1 for i := 2; i <= n; i++ { a, b = b, a+b } return b } correctly updates a and b simultaneously and returns b as fib(n). func fib(n int) int { fib := make([]int, n+1) fib[0], fib[1] = 0, 1 for i := 2; i <= n; i++ { fib[i] = fib[i-1] + fib[i-2] } return fib[n] } uses slice (not constant space). func fib(n int) int { if n <= 1 { return n } return fib(n-1) + fib(n-2) } is simple recursion (inefficient). func fib(n int) int { a, b := 0, 1 for i := 1; i < n; i++ { a = b b = a + b } return a } updates variables incorrectly causing wrong result.
  3. Final Answer:

    func fib(n int) int { a, b := 0, 1 for i := 2; i <= n; i++ { a, b = b, a+b } return b } -> Option A
  4. Quick Check:

    Update two vars simultaneously for constant space [OK]
Hint: Update two vars together to save space in Fibonacci DP [OK]
Common Mistakes:
  • Using slice instead of variables for DP
  • Incorrect variable update order causing wrong sums
  • Using recursion without memoization
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