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DSA C#programming~10 mins

Shortest Path in Unweighted Graph Using BFS in DSA C# - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize the queue for BFS traversal.

DSA C#
Queue<int> queue = new Queue<int>();
queue.[1](start);
Drag options to blanks, or click blank then click option'
AEnqueue
BPush
CAdd
DInsert
Attempts:
3 left
💡 Hint
Common Mistakes
Using Add or Push instead of Enqueue causes compilation errors.
2fill in blank
medium

Complete the code to mark the start node as visited.

DSA C#
bool[] visited = new bool[n];
visited[[1]] = true;
Drag options to blanks, or click blank then click option'
A1
Bn
Cstart
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Using 0 or 1 directly instead of the start variable can cause wrong behavior.
3fill in blank
hard

Fix the error in the BFS loop condition to continue while the queue is not empty.

DSA C#
while (queue.[1] > 0)
{
    int current = queue.Dequeue();
    // process neighbors
}
Drag options to blanks, or click blank then click option'
ASize
BCount
CLength
DCapacity
Attempts:
3 left
💡 Hint
Common Mistakes
Using Length or Size causes compilation errors.
4fill in blank
hard

Fill both blanks to update the distance and enqueue the neighbor node.

DSA C#
if (!visited[neighbor])
{
    visited[neighbor] = true;
    distance[neighbor] = distance[[1]] + 1;
    queue.[2](neighbor);
}
Drag options to blanks, or click blank then click option'
Acurrent
Bstart
CEnqueue
DAdd
Attempts:
3 left
💡 Hint
Common Mistakes
Using start instead of current for distance update.
Using Add instead of Enqueue for queue.
5fill in blank
hard

Fill all three blanks to reconstruct the shortest path from end to start.

DSA C#
List<int> path = new List<int>();
int node = end;
while (node != [1])
{
    path.[2](node);
    node = parent[[3]];
}
path.Add(start);
path.Reverse();
Drag options to blanks, or click blank then click option'
Astart
BAdd
Cnode
Dend
Attempts:
3 left
💡 Hint
Common Mistakes
Using end instead of start in loop condition.
Using wrong method instead of Add for list.
Using parent[end] instead of parent[node].

Practice

(1/5)
1. What does BFS (Breadth-First Search) help find in an unweighted graph?
easy
A. The total number of edges in the graph
B. The node with the highest degree
C. The longest path in the graph
D. The shortest path from a start node to all other nodes

Solution

  1. Step 1: Understand BFS traversal

    BFS explores nodes level by level starting from the source node.
  2. Step 2: BFS finds shortest paths in unweighted graphs

    Because BFS visits nodes in order of increasing distance, it finds shortest paths.
  3. Final Answer:

    The shortest path from a start node to all other nodes -> Option D
  4. Quick Check:

    BFS = Shortest path in unweighted graph [OK]
Hint: BFS explores neighbors level-wise to find shortest paths [OK]
Common Mistakes:
  • Confusing BFS with DFS for shortest path
  • Thinking BFS finds longest path
  • Assuming BFS counts edges incorrectly
2. Which C# data structure is best to use as a queue for BFS implementation?
easy
A. Queue<T>
B. List<T>
C. Stack<T>
D. Dictionary

Solution

  1. Step 1: Identify BFS traversal order

    BFS uses FIFO order to explore nodes level by level.
  2. Step 2: Choose data structure matching FIFO

    Queue<T> provides FIFO behavior, perfect for BFS.
  3. Final Answer:

    Queue<T> -> Option A
  4. Quick Check:

    Queue = FIFO for BFS [OK]
Hint: Use Queue<T> for BFS to maintain correct node order [OK]
Common Mistakes:
  • Using Stack<T> which is LIFO, wrong for BFS
  • Using List<T> without queue behavior
  • Confusing Dictionary with queue
3. What is the output distance array after running BFS from node 0 on this graph?
Graph edges:
0 - 1
0 - 2
1 - 3
2 - 3
3 - 4
Assume distance to start node 0 is 0 and unreachable nodes have distance -1.
medium
A. [0, 1, 1, 2, 3]
B. [0, 1, 2, 3, 4]
C. [0, 1, 1, 1, 2]
D. [0, -1, -1, -1, -1]

Solution

  1. Step 1: Initialize distances and start BFS from node 0

    Distance[0] = 0; others = -1 initially.
  2. Step 2: Visit neighbors level-wise

    From 0: nodes 1 and 2 get distance 1. From 1 and 2: node 3 gets distance 2. From 3: node 4 gets distance 3.
  3. Final Answer:

    [0, 1, 1, 2, 3] -> Option A
  4. Quick Check:

    Distances = [0,1,1,2,3] [OK]
Hint: Track distances level by level from start node [OK]
Common Mistakes:
  • Assigning wrong distances to nodes
  • Confusing BFS with DFS distances
  • Not initializing unreachable nodes as -1
4. Identify the bug in this BFS shortest path code snippet in C#:
int[] dist = new int[n];
for (int i = 0; i < n; i++) dist[i] = -1;
Queue<int> q = new Queue<int>();
dist[start] = 0;
q.Enqueue(start);
while (q.Count > 0) {
  int u = q.Dequeue();
  foreach (int v in graph[u]) {
    if (dist[v] == 0) {
      dist[v] = dist[u] + 1;
      q.Enqueue(v);
    }
  }
}
medium
A. Enqueue should be done before setting dist[v]
B. Queue should be Stack for BFS
C. dist[v] == 0 should be dist[v] == -1 to check unvisited nodes
D. dist[start] should be -1 initially

Solution

  1. Step 1: Understand distance initialization and visit check

    Distances start at -1 for unvisited nodes; 0 means visited or start node.
  2. Step 2: Check condition for visiting neighbors

    Condition 'dist[v] == 0' wrongly treats unvisited nodes as visited; should be 'dist[v] == -1'.
  3. Final Answer:

    dist[v] == -1 to check unvisited nodes -> Option C
  4. Quick Check:

    Check unvisited with -1, not 0 [OK]
Hint: Use -1 to mark unvisited nodes in BFS distance array [OK]
Common Mistakes:
  • Checking dist[v] == 0 instead of -1
  • Using Stack instead of Queue for BFS
  • Incorrect initial distance for start node
5. Given an unweighted graph with nodes 0 to 5 and edges:
0-1, 0-2, 1-3, 3-4, 4-5
What is the shortest path from node 0 to node 5 using BFS?
hard
A. [0, 2, 3, 4, 5]
B. [0, 1, 3, 4, 5]
C. [0, 1, 2, 3, 4, 5]
D. [0, 2, 4, 5]

Solution

  1. Step 1: Run BFS from node 0 to find shortest distances

    Distances: 0(0), 1(1), 2(1), 3(2), 4(3), 5(4).
  2. Step 2: Trace shortest path back from node 5

    From 5 to 4, 4 to 3, 3 to 1, 1 to 0: 0->1->3->4->5.
  3. Final Answer:

    [0, 1, 3, 4, 5] -> Option B
  4. Quick Check:

    Shortest path = [0,1,3,4,5] [OK]
Hint: Trace BFS parents backward to find shortest path [OK]
Common Mistakes:
  • Attempting path via node 2 (no 2-3 edge)
  • Skipping nodes in path
  • Confusing BFS with DFS path
Recommended

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10 questions~5 mineasy hard