N Queens Problem in DSA C# - Time & Space Complexity
We want to understand how the time needed to solve the N Queens problem grows as the board size increases.
Specifically, how does the number of steps change when we try to place queens on larger boards?
Analyze the time complexity of the following code snippet.
bool SolveNQueens(int row, int n, bool[][] board) {
if (row == n) return true;
for (int col = 0; col < n; col++) {
if (IsSafe(row, col, board)) {
board[row][col] = true;
if (SolveNQueens(row + 1, n, board)) return true;
board[row][col] = false;
}
}
return false;
}
This code tries to place queens row by row, checking if each position is safe, and uses backtracking to find a solution.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: The recursive calls that try placing a queen in each column of the current row.
- How many times: For each row, it tries up to n columns, and for each valid placement, it recurses to the next row.
As the board size n grows, the number of ways to place queens grows very fast because each row tries n columns, and this repeats for n rows.
| Input Size (n) | Approx. Operations |
|---|---|
| 4 | Hundreds of checks |
| 8 | Thousands to tens of thousands of checks |
| 12 | Millions of checks |
Pattern observation: The operations grow very quickly, much faster than just doubling or squaring; it grows exponentially with n.
Time Complexity: O(n!)
This means the time needed grows roughly like the factorial of n, which is very fast growth making large boards much harder to solve.
[X] Wrong: "The time grows like n squared because there are n rows and n columns."
[OK] Correct: The algorithm tries many combinations by placing queens row by row, and each placement leads to multiple recursive calls, causing factorial growth, not just n squared.
Understanding this problem's time complexity helps you explain how backtracking explores many possibilities and why some problems become very slow as input grows.
"What if we added memoization to remember safe positions? How would the time complexity change?"
Practice
N Queens Problem in chess?Solution
Step 1: Understand the problem statement
The N Queens Problem requires placing N queens on an NxN chessboard so that no two queens threaten each other.Step 2: Identify the correct goal
This means no two queens share the same row, column, or diagonal.Final Answer:
Place N queens on an NxN board so that no two queens attack each other -> Option AQuick Check:
Goal = No two queens attack each other [OK]
- Thinking queens can share rows or columns
- Ignoring diagonal attacks
- Confusing with placing queens in one line
Solution
Step 1: Identify correct 2D array declaration in C#
In C#, a 2D array is declared asint[,] board = new int[8,8];.Step 2: Check other options for syntax errors
int[][] board = new int[8]; declares a jagged array but misses initialization of inner arrays. int board[8][8]; is invalid syntax in C#. int board = new int[8,8]; tries to assign an array to an int variable.Final Answer:
int[,] board = new int[8,8]; -> Option AQuick Check:
Correct 2D array syntax = int[,] board = new int[8,8]; [OK]
- Using jagged arrays without initializing inner arrays
- Using C++ style array declarations
- Assigning arrays to single int variables
bool IsSafe(int[,] board, int row, int col) {
for (int i = 0; i < col; i++) {
if (board[row, i] == 1) return false;
}
for (int i = row, j = col; i >= 0 && j >= 0; i--, j--) {
if (board[i, j] == 1) return false;
}
for (int i = row, j = col; i < 4 && j >= 0; i++, j--) {
if (board[i, j] == 1) return false;
}
return true;
}
int[,] board = new int[4,4];
board[0, 1] = 1;
bool result = IsSafe(board, 1, 2);
Console.WriteLine(result);What will be the output?Solution
Step 1: Analyze the board state and IsSafe checks
The board has a queen at (0,1). We check if placing at (1,2) is safe. The function checks left row, upper-left diagonal, and lower-left diagonal.Step 2: Check conflicts for position (1,2)
Left row check: no queen at (1,0) or (1,1). Upper-left diagonal: (0,1) has a queen, so returns false.Final Answer:
false -> Option CQuick Check:
Queen at (0,1) blocks (1,2) = false [OK]
- Ignoring diagonal checks
- Assuming no conflict if row is clear
- Misreading array indices
bool SolveNQueens(int[,] board, int col) {
if (col >= board.GetLength(0)) return true;
for (int i = 0; i < board.GetLength(0); i++) {
if (IsSafe(board, i, col)) {
board[i, col] = 1;
if (SolveNQueens(board, col + 1)) return true;
board[i, col] = 0;
}
}
return false;
}
// IsSafe method is correctSolution
Step 1: Review the recursive backtracking logic
The function tries to place a queen in each row of the current column, checks safety, places queen, and recurses to next column.Step 2: Verify base case and backtracking
Base case returns true when all columns are processed. Backtracking resets board[i, col] to 0 if recursion fails. This is correct.Final Answer:
No bug; code works correctly -> Option BQuick Check:
Backtracking logic and base case are correct [OK]
- Confusing row and column in base case
- Forgetting to reset board on backtrack
- Assuming uninitialized board causes error
Solution
Step 1: Understand current behavior
The current solver returns true on finding the first solution, stopping further search.Step 2: Modify to count all solutions
Change return type to int, accumulate counts from recursive calls, and do not return early. This counts all valid placements.Final Answer:
Replace the return type with int and sum all recursive calls instead of returning on first true -> Option DQuick Check:
Counting solutions = sum recursive counts [OK]
- Stopping at first solution
- Changing board size unnecessarily
- Removing safety checks causing wrong counts
Ready to prove it?
Pass the test and this pattern moves unknown
