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DSA C#programming~20 mins

Memoization to Optimize Recursion in DSA C# - Practice Problems & Challenges

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Challenge - 5 Problems
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Memoization Mastery
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❓ Predict Output
intermediate
2:00remaining
Output of Fibonacci with Memoization
What is the output of the following C# code that calculates Fibonacci numbers using memoization?
DSA C#
using System;
using System.Collections.Generic;

class Program {
    static Dictionary<int, int> memo = new Dictionary<int, int>();

    static int Fib(int n) {
        if (n <= 1) return n;
        if (memo.ContainsKey(n)) return memo[n];
        int result = Fib(n - 1) + Fib(n - 2);
        memo[n] = result;
        return result;
    }

    static void Main() {
        Console.WriteLine(Fib(6));
    }
}
A13
B15
C21
D8
Attempts:
2 left
💡 Hint
Remember that Fibonacci sequence starts with 0, 1, 1, 2, 3, 5, 8, 13...
❓ Predict Output
intermediate
2:00remaining
Memoization Cache State After Calls
After calling Fib(5) using the memoized Fibonacci function below, what is the content of the memo dictionary?
DSA C#
using System;
using System.Collections.Generic;

class Program {
    static Dictionary<int, int> memo = new Dictionary<int, int>();

    static int Fib(int n) {
        if (n <= 1) return n;
        if (memo.ContainsKey(n)) return memo[n];
        int result = Fib(n - 1) + Fib(n - 2);
        memo[n] = result;
        return result;
    }

    static void Main() {
        Fib(5);
        foreach(var kvp in memo) {
            Console.WriteLine($"{kvp.Key}:{kvp.Value}");
        }
    }
}
A
2:1
3:2
4:3
5:5
B
2:1
3:2
4:3
5:8
C
1:1
2:1
3:2
4:3
5:5
D
1:1
2:2
3:3
4:5
5:8
Attempts:
2 left
💡 Hint
Memo stores results only for n > 1 after calculation.
🔧 Debug
advanced
2:00remaining
Identify the Bug in Memoized Factorial
What error will the following C# code produce when calling Factorial(5)?
DSA C#
using System;
using System.Collections.Generic;

class Program {
    static Dictionary<int, int> memo = new Dictionary<int, int>();

    static int Factorial(int n) {
        if (n == 0) return 1;
        if (memo.ContainsKey(n)) return memo[n];
        int result = n * Factorial(n - 1);
        // Missing memoization store here
        return result;
    }

    static void Main() {
        Console.WriteLine(Factorial(5));
    }
}
AStackOverflowException
BOutput: 120
CKeyNotFoundException
DOutput: 0
Attempts:
2 left
💡 Hint
Check if memo dictionary is updated after calculation.
❓ Predict Output
advanced
2:00remaining
Output of Memoized Climbing Stairs Problem
What is the output of the following C# code that uses memoization to count ways to climb stairs?
DSA C#
using System;
using System.Collections.Generic;

class Program {
    static Dictionary<int, int> memo = new Dictionary<int, int>();

    static int ClimbStairs(int n) {
        if (n <= 1) return 1;
        if (memo.ContainsKey(n)) return memo[n];
        int ways = ClimbStairs(n - 1) + ClimbStairs(n - 2);
        memo[n] = ways;
        return ways;
    }

    static void Main() {
        Console.WriteLine(ClimbStairs(4));
    }
}
A8
B7
C5
D6
Attempts:
2 left
💡 Hint
Number of ways to climb 4 steps with 1 or 2 steps at a time.
🧠 Conceptual
expert
2:00remaining
Memoization Impact on Recursive Tree Size
Consider a naive recursive function without memoization that computes Fibonacci numbers. How does adding memoization affect the number of recursive calls?
AChanges calls from linear to exponential due to caching
BIncreases calls because memo dictionary adds overhead
CHas no effect on number of calls, only on memory usage
DReduces exponential calls to linear calls by storing intermediate results
Attempts:
2 left
💡 Hint
Think about repeated calculations in recursion.

Practice

(1/5)
1. What is the main purpose of using memoization in recursive functions?
easy
A. To make the function run slower by adding extra steps
B. To avoid using any variables inside the function
C. To convert recursion into iteration automatically
D. To store results of expensive function calls and reuse them

Solution

  1. Step 1: Understand recursion inefficiency

    Recursive functions often repeat the same calculations multiple times, which wastes time.
  2. Step 2: Role of memoization

    Memoization saves the results of these repeated calculations so they can be reused instead of recalculated.
  3. Final Answer:

    To store results of expensive function calls and reuse them -> Option D
  4. Quick Check:

    Memoization = Store and reuse results [OK]
Hint: Memoization saves repeated results to speed recursion [OK]
Common Mistakes:
  • Thinking memoization slows down recursion
  • Confusing memoization with iteration
  • Believing memoization removes recursion
2. Which of the following is the correct way to declare a memo dictionary for integer keys and values in C#?
easy
A. HashSet memo = new HashSet();
B. List memo = new List();
C. Dictionary memo = new Dictionary();
D. Dictionary memo = new Dictionary();

Solution

  1. Step 1: Identify correct generic dictionary syntax

    In C#, a dictionary with integer keys and values is declared as Dictionary.
  2. Step 2: Check options for correct syntax

    Dictionary memo = new Dictionary(); uses Dictionary with proper initialization, others use wrong types or missing generics.
  3. Final Answer:

    Dictionary memo = new Dictionary(); -> Option C
  4. Quick Check:

    Dictionary = Correct memo declaration [OK]
Hint: Use Dictionary for integer key-value memo [OK]
Common Mistakes:
  • Using List or HashSet instead of Dictionary
  • Missing generic type parameters
  • Using untyped Dictionary without generics
3. What will be the output of the following C# code?
using System;
using System.Collections.Generic;

class Program {
    static Dictionary memo = new Dictionary();

    static int Fib(int n) {
        if (n <= 1) return n;
        if (memo.ContainsKey(n)) return memo[n];
        memo[n] = Fib(n - 1) + Fib(n - 2);
        return memo[n];
    }

    static void Main() {
        Console.WriteLine(Fib(5));
    }
}
medium
A. 5
B. 8
C. 3
D. 13

Solution

  1. Step 1: Understand Fibonacci calculation

    Fib(5) = Fib(4) + Fib(3). Calculating recursively with memoization avoids repeated work.
  2. Step 2: Calculate Fib(5) step-by-step

    Fib(0)=0, Fib(1)=1, Fib(2)=1, Fib(3)=2, Fib(4)=3, Fib(5)=5.
  3. Final Answer:

    5 -> Option A
  4. Quick Check:

    Fib(5) = 5 [OK]
Hint: Recall Fibonacci sequence values or trace memoized calls [OK]
Common Mistakes:
  • Confusing Fib(5) with Fib(6)
  • Ignoring memoization effect
  • Miscounting base cases
4. Identify the error in this memoized factorial function and select the fix:
static Dictionary memo = new Dictionary();

static int Factorial(int n) {
    if (n == 0) return 1;
    if (memo.ContainsKey(n)) return memo[n];
    memo[n] = n * Factorial(n - 1);
    return n;
}
medium
A. Use memo[n] = Factorial(n - 1) * (n - 1);
B. Return memo[n] instead of n after recursive call
C. Remove memo dictionary completely
D. Change base case to if (n == 1) return 1;

Solution

  1. Step 1: Analyze return statement after recursion

    The function returns 'n' instead of the computed factorial stored in memo[n], which is incorrect.
  2. Step 2: Correct return value

    Return memo[n] to return the calculated factorial value after storing it.
  3. Final Answer:

    Return memo[n] instead of n after recursive call -> Option B
  4. Quick Check:

    Return memo[n] fixes incorrect output [OK]
Hint: Return stored memo value, not input parameter [OK]
Common Mistakes:
  • Returning input parameter instead of memoized result
  • Changing base case unnecessarily
  • Misusing memo dictionary keys
5. You want to optimize a recursive function that calculates the number of ways to climb n stairs taking 1 or 2 steps at a time. Which memoization approach below correctly implements this in C#?
hard
A. Use a Dictionary to store results; base cases for 0 and 1 stairs return 1; recursive call sums ways(n-1) and ways(n-2).
B. Use a List<int> to store results; base case returns 0 for 0 stairs; recursive call multiplies ways(n-1) and ways(n-2).
C. Use a Dictionary but no base cases; recursive call sums ways(n-1) and ways(n-2).
D. Use an array of size n; base cases return n; recursive call subtracts ways(n-1) from ways(n-2).

Solution

  1. Step 1: Understand problem and base cases

    Number of ways to climb stairs with 1 or 2 steps: ways(0)=1 (one way to stand still), ways(1)=1.
  2. Step 2: Correct memoization approach

    Use Dictionary to store results; recursive call sums ways(n-1) and ways(n-2) to count all paths.
  3. Final Answer:

    Use a Dictionary to store results; base cases for 0 and 1 stairs return 1; recursive call sums ways(n-1) and ways(n-2). -> Option A
  4. Quick Check:

    Memo + base cases + sum recursion = Use a Dictionary to store results; base cases for 0 and 1 stairs return 1; recursive call sums ways(n-1) and ways(n-2). [OK]
Hint: Base cases 0,1 = 1; sum ways(n-1) + ways(n-2) with memo [OK]
Common Mistakes:
  • Wrong base cases values
  • Using multiplication instead of addition
  • Missing base cases causing infinite recursion
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