What if you could carry the most valuable things by taking just the right parts of each item?
Why Fractional Knapsack Problem in DSA C#?
Imagine you are packing a bag for a trip. You have many items, each with a weight and value. You want to carry the most valuable items, but your bag can only hold a limited weight. If you try to pick items one by one without a plan, you might end up carrying less value.
Trying to pick items manually is slow and confusing. You might pick heavy items with low value first, leaving no space for lighter, more valuable items. This wastes your bag space and reduces the total value you carry.
The Fractional Knapsack Problem helps by allowing you to take parts of items, not just whole items. It sorts items by value per weight and picks the best parts first, filling your bag with the highest value possible.
double totalValue = 0; foreach (var item in items) { if (bagCanHold(item.weight)) { totalValue += item.value; bagAdd(item); } }
items.Sort((a, b) => b.valuePerWeight.CompareTo(a.valuePerWeight)); double totalValue = 0; double remainingWeight = bagCapacity; foreach (var item in items) { double weightToTake = Math.Min(item.weight, remainingWeight); totalValue += weightToTake * item.valuePerWeight; remainingWeight -= weightToTake; if (remainingWeight == 0) break; }
This method lets you maximize the total value you carry by smartly choosing whole or parts of items based on their value-to-weight ratio.
Think of filling a backpack with snacks for a hike. Some snacks are heavy but less tasty, others are light and delicious. Fractional Knapsack helps you pick the tastiest mix that fits your backpack weight limit.
Manual picking wastes space and value.
Fractional Knapsack sorts items by value per weight.
It allows taking parts of items to fill the bag optimally.
Practice
Fractional Knapsack Problem?Solution
Step 1: Understand the problem goal
The fractional knapsack problem allows taking parts of items to maximize total value within a weight limit.Step 2: Compare options
Only Maximize total value by taking fractions of items within weight limit correctly states maximizing total value by taking fractions within weight limit.Final Answer:
Maximize total value by taking fractions of items within weight limit -> Option BQuick Check:
Goal = Maximize value with fractions [OK]
- Thinking only whole items can be taken
- Confusing with minimizing weight
- Ignoring value-to-weight ratio
Item with public fields weight and value?Solution
Step 1: Check class declaration syntax
In C#, class fields must have type and access modifier for public fields.Step 2: Validate each option
class Item { public int weight; public int value; } correctly declares public int fields. class Item { int weight; int value; } lacks access modifier. public Item { int weight; int value; } misses class keyword. class Item { public weight; public value; } misses types.Final Answer:
class Item { public int weight; public int value; } -> Option AQuick Check:
Correct class syntax = class Item { public int weight; public int value; } [OK]
- Omitting access modifiers
- Missing data types
- Incorrect class keyword usage
var items = new[] {
new Item { weight = 10, value = 60 },
new Item { weight = 20, value = 100 },
new Item { weight = 30, value = 120 }
};
int capacity = 50;
double maxValue = 0;
Array.Sort(items, (a, b) => (b.value / (double)b.weight).CompareTo(a.value / (double)a.weight));
int remaining = capacity;
foreach (var item in items) {
if (item.weight <= remaining) {
maxValue += item.value;
remaining -= item.weight;
} else {
maxValue += item.value * (remaining / (double)item.weight);
break;
}
}
Console.WriteLine(Math.Round(maxValue, 2));Solution
Step 1: Sort items by value/weight ratio
Ratios: Item1=6, Item2=5, Item3=4. Sorted order: Item1, Item2, Item3.Step 2: Add items until capacity 50
Take Item1 fully (weight 10, value 60), remaining=40. Take Item2 fully (weight 20, value 100), remaining=20. Take 20/30 fraction of Item3: value = 120 * (20/30) = 80.Step 3: Calculate total value
Total = 60 + 100 + 80 = 240. Rounded to 240.00.Final Answer:
240.00 -> Option DQuick Check:
Sum values with fractions = 240.00 [OK]
- Not sorting by value/weight ratio
- Taking items without fraction
- Incorrect fraction calculation
int capacity = 50;
var items = new List<Item> {
new Item { weight = 10, value = 60 },
new Item { weight = 20, value = 100 },
new Item { weight = 30, value = 120 }
};
items.Sort((a, b) => (a.value / a.weight).CompareTo(b.value / b.weight));
double maxValue = 0;
int remaining = capacity;
foreach (var item in items) {
if (item.weight <= remaining) {
maxValue += item.value;
remaining -= item.weight;
} else {
maxValue += item.value * (remaining / item.weight);
break;
}
}
Console.WriteLine(maxValue);Solution
Step 1: Analyze sorting comparator
The comparator uses integer division (a.value / a.weight) which truncates decimals, causing wrong ratios.Step 2: Impact on sorting and calculation
Integer division leads to incorrect sorting order and wrong maxValue calculation.Final Answer:
Integer division causes incorrect ratio calculation -> Option CQuick Check:
Use double division for correct ratios [OK]
- Sorting ascending instead of descending
- Ignoring integer division truncation
- Assuming List causes error
Solution
Step 1: Calculate value/weight ratios and sort
Ratios: (5,30)=6, (10,40)=4, (15,45)=3. Sorted order: (5,30), (10,40), (15,45).Step 2: Fill knapsack capacity 20
Take full (5,30), remaining=15, value=30. Take full (10,40), remaining=5, value=70. Take fraction of (15,45): 5/15=1/3 fraction, value=45*(1/3)=15.Step 3: Calculate total value
Total value = 30 + 40 + 15 = 85.Final Answer:
85 -> Option AQuick Check:
Sum with fractions = 85 [OK]
- Not sorting by value/weight ratio
- Taking items without fraction
- Incorrect fraction calculation
Ready to prove it?
Pass the test and this pattern moves unknown
