What if you could instantly find any continuous period that adds up to your target without checking every possibility?
Why Subarray Sum Equals K Using Hash Map in DSA C#?
Imagine you have a long list of daily expenses, and you want to find if there is a continuous period where the total spending equals exactly $k. Doing this by checking every possible period manually would take forever.
Manually adding sums for every possible sub-list means repeating many calculations, which is slow and tiring. It's easy to make mistakes and miss some periods, especially when the list is long.
Using a hash map, we can remember sums we have seen before. This helps us quickly find if a previous sum allows the current sum to form a subarray that equals k, making the search fast and reliable.
int count = 0; for (int start = 0; start < nums.Length; start++) { int sum = 0; for (int end = start; end < nums.Length; end++) { sum += nums[end]; if (sum == k) count++; } }
Dictionary<int, int> sumCounts = new Dictionary<int, int>(); sumCounts[0] = 1; int sum = 0, count = 0; for (int i = 0; i < nums.Length; i++) { sum += nums[i]; if (sumCounts.ContainsKey(sum - k)) count += sumCounts[sum - k]; if (sumCounts.ContainsKey(sum)) { sumCounts[sum] += 1; } else { sumCounts[sum] = 1; } }
This method lets you find all continuous periods summing to k in a long list instantly, even if the list is huge.
Tracking your calorie intake daily, you want to find if there was any continuous stretch of days where your total calories matched your target exactly.
Manual checking is slow and repeats work.
Hash map remembers sums to find matches quickly.
Efficiently counts all subarrays summing to k in one pass.
Practice
Subarray Sum Equals K problem?Solution
Step 1: Understand the problem goal
The problem wants to find subarrays whose sums equal a target value k.Step 2: Role of hash map in solution
The hash map stores cumulative sums seen so far and how many times they occurred, enabling quick checks for needed sums.Final Answer:
To store cumulative sums and their frequencies for quick lookup -> Option AQuick Check:
Hash map stores sums = A [OK]
- Thinking hash map stores array elements directly
- Assuming sorting is needed
- Using hash map to reverse array
Solution
Step 1: Identify correct C# dictionary syntax
C# usesDictionary<TKey, TValue>withnew Dictionary<TKey, TValue>()to declare hash maps.Step 2: Check each option
Dictionary sumCounts = new Dictionary(); uses correct generic syntax. Options B and C use Java-like syntax. Dictionary sumCounts = new Dictionary(); misses generic types.Final Answer:
Dictionary sumCounts = new Dictionary(); -> Option AQuick Check:
C# Dictionary syntax = A [OK]
- Using Java HashMap syntax in C#
- Omitting generic type parameters
- Using non-existent Map type in C#
int[] nums = {1, 2, 3};
int k = 3;
int count = 0;
Dictionary sumCounts = new Dictionary();
sumCounts[0] = 1;
int sum = 0;
foreach (int num in nums) {
sum += num;
if (sumCounts.ContainsKey(sum - k)) {
count += sumCounts[sum - k];
}
if (sumCounts.ContainsKey(sum)) {
sumCounts[sum]++;
} else {
sumCounts[sum] = 1;
}
}
Console.WriteLine(count);Solution
Step 1: Calculate cumulative sums and check counts
nums = [1,2,3], k=3. sumCounts starts with {0:1}. - sum=1: sum-k= -2 (not in sumCounts), count=0, sumCounts={0:1,1:1} - sum=3: sum-k=0 (in sumCounts=1), count=1, sumCounts={0:1,1:1,3:1} - sum=6: sum-k=3 (in sumCounts=1), count=2, sumCounts={0:1,1:1,3:1,6:1}Step 2: Final count of subarrays with sum k
Count is 2 because subarrays [1,2] and [3] sum to 3.Final Answer:
2 -> Option DQuick Check:
Subarrays count = 2 [OK]
- Not initializing sumCounts with {0:1}
- Forgetting to update count correctly
- Misunderstanding sum-k lookup
int[] nums = {1, 1, 1};
int k = 2;
int count = 0;
Dictionary sumCounts = new Dictionary();
int sum = 0;
foreach (int num in nums) {
sum += num;
if (sumCounts.ContainsKey(sum - k)) {
count += sumCounts[sum - k];
}
sumCounts[sum] = 1;
}
Console.WriteLine(count);Solution
Step 1: Check initialization of sumCounts
sumCounts should start with {0:1} to count subarrays starting at index 0, but here it is empty.Step 2: Check updating sumCounts inside loop
sumCounts[sum] = 1 overwrites counts instead of incrementing, but main bug is missing initial {0:1}.Final Answer:
sumCounts is not initialized with sum 0 count 1 -> Option BQuick Check:
Initialize sumCounts[0] = 1 [OK]
- Not initializing sumCounts with {0:1}
- Overwriting counts instead of incrementing
- Ignoring sum-k lookup logic
nums = {3, 4, 7, 2, -3, 1, 4, 2} and k = 7, how many subarrays sum to k using the hash map approach?Solution
Step 1: Calculate cumulative sums and track counts
Initialize sumCounts = {0:1}, sum=0, count=0. - i=0: sum=3, sum-k=-4(not found), count=0, sumCounts={0:1,3:1} - i=1: sum=7, sum-k=0(found=1), count=1, sumCounts={0:1,3:1,7:1} - i=2: sum=14, sum-k=7(found=1), count=2, sumCounts={0:1,3:1,7:1,14:1} - i=3: sum=16, sum-k=9(not found), count=2, sumCounts={0:1,3:1,7:1,14:1,16:1} - i=4: sum=13, sum-k=6(not found), count=2, sumCounts={0:1,3:1,7:1,14:1,16:1,13:1} - i=5: sum=14, sum-k=7(found=1), count=3, sumCounts[14]=2 - i=6: sum=18, sum-k=11(not found), count=3, sumCounts={0:1,3:1,7:1,14:2,16:1,13:1,18:1} - i=7: sum=20, sum-k=13(found=1), count=4, sumCounts={0:1,3:1,7:1,14:2,16:1,13:1,18:1,20:1}Step 2: Verify the counted subarrays
Subarrays summing to 7 are: - [3,4] - [7] - [7,2,-3,1] - [1,4,2] Count is 4 total.Final Answer:
4 -> Option CQuick Check:
Count subarrays with sum k = 4 [OK]
- Missing subarrays with negative numbers
- Not updating counts when sum repeats
- Forgetting to initialize sumCounts with {0:1}
Ready to prove it?
Pass the test and this pattern moves unknown
