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DSA C#programming~5 mins

String to Integer atoi in DSA C# - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does the atoi function do?
It converts a string representing a number into its integer value, ignoring leading spaces and handling optional signs.
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beginner
How does atoi handle leading spaces in the input string?
It skips all leading whitespace characters before processing the number.
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intermediate
What should atoi do if the string contains non-digit characters after the number?
It stops parsing at the first non-digit character and returns the integer parsed so far.
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intermediate
How does atoi handle integer overflow?
It clamps the result to the maximum or minimum integer value if overflow occurs.
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beginner
What is the significance of handling '+' and '-' signs in atoi?
They determine whether the resulting integer is positive or negative.
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What does atoi return when given the string " -42abc"?
A0
B42
C-42
DError
If the input string is "4193 with words", what integer does atoi return?
A4193
B0
C4193 with words
DError
What should atoi return for the input string "words and 987"?
A0
Bwords
C987
DError
How does atoi handle the input string "-91283472332" if the integer range is 32-bit?
A-91283472332
B-2147483648
C0
D2147483647
Which of these is NOT a step in implementing atoi?
ASkip leading spaces
BParse digits until non-digit character
CParse optional '+' or '-' sign
DConvert all characters to uppercase
Explain step-by-step how to convert a string like " -123abc" to an integer using atoi.
Think about how you read the string from left to right.
You got /5 concepts.
    Describe how to handle integer overflow when converting a string to an integer.
    Remember the limits of 32-bit integers.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does the atoi function do when given a string input?
      easy
      A. Reverses the string characters
      B. Converts the string to a floating-point number
      C. Converts the string to an integer number
      D. Counts the number of characters in the string

      Solution

      1. Step 1: Understand the purpose of atoi

        The atoi function is designed to convert a string that represents a number into an integer type.
      2. Step 2: Differentiate from other string operations

        It does not reverse or count characters, nor convert to floating-point; it specifically converts to integer.
      3. Final Answer:

        Converts the string to an integer number -> Option C
      4. Quick Check:

        atoi converts string to integer [OK]
      Hint: atoi always converts string digits to integer number [OK]
      Common Mistakes:
      • Thinking atoi converts to float
      • Confusing atoi with string reversal
      • Assuming atoi counts characters
      2. Which of the following C# code snippets correctly converts a string "1234" to an integer using atoi logic?
      easy
      A. int num = Convert.ToString(1234);
      B. int num = "1234".ToInt();
      C. int num = int.ToString("1234");
      D. int num = int.Parse("1234");

      Solution

      1. Step 1: Identify correct C# method for string to int

        int.Parse(string) converts a numeric string to an integer correctly.
      2. Step 2: Check other options for syntax errors

        "1234".ToInt() and int.ToString("1234") are invalid methods; Convert.ToString(1234) converts int to string, not string to int.
      3. Final Answer:

        int num = int.Parse("1234"); -> Option D
      4. Quick Check:

        int.Parse converts string to int [OK]
      Hint: Use int.Parse to convert string digits to int in C# [OK]
      Common Mistakes:
      • Using invalid method names like ToInt()
      • Confusing Convert.ToString with conversion to int
      • Trying to call ToString on string input
      3. What is the output of the following C# code?
      string s = "  -42abc";
      int result = MyAtoi(s);
      Console.WriteLine(result);
      
      int MyAtoi(string str) {
          int i = 0, sign = 1, num = 0;
          while (i < str.Length && str[i] == ' ') i++;
          if (i < str.Length && (str[i] == '+' || str[i] == '-')) {
              sign = (str[i] == '-') ? -1 : 1;
              i++;
          }
          while (i < str.Length && char.IsDigit(str[i])) {
              num = num * 10 + (str[i] - '0');
              i++;
          }
          return sign * num;
      }
      medium
      A. Exception thrown
      B. -42
      C. 42
      D. 0

      Solution

      1. Step 1: Skip leading spaces and detect sign

        The code skips spaces, finds '-', sets sign to -1, then moves to digits.
      2. Step 2: Parse digits until non-digit

        It reads '4' and '2', stops at 'a', so number is 42, multiplied by sign -1 gives -42.
      3. Final Answer:

        -42 -> Option B
      4. Quick Check:

        Parsed number with sign = -42 [OK]
      Hint: Skip spaces, check sign, parse digits until non-digit [OK]
      Common Mistakes:
      • Not skipping spaces before sign
      • Parsing non-digit characters
      • Ignoring sign character
      4. Identify the bug in this MyAtoi function and select the fix:
      int MyAtoi(string str) {
          int i = 0, sign = 1, num = 0;
          while (str[i] == ' ') i++;
          if (str[i] == '+' || str[i] == '-') {
              sign = (str[i] == '-') ? -1 : 1;
              i++;
          }
          while (char.IsDigit(str[i])) {
              num = num * 10 + (str[i] - '0');
              i++;
          }
          return sign * num;
      }
      medium
      A. Add boundary checks for index i before accessing str[i]
      B. Remove the sign check to simplify code
      C. Change char.IsDigit to char.IsLetter
      D. Initialize num to -1 instead of 0

      Solution

      1. Step 1: Check for index out of range errors

        The code accesses str[i] without checking if i < str.Length, risking runtime error.
      2. Step 2: Fix by adding boundary checks in all loops

        Adding conditions like i < str.Length in while loops prevents out-of-range exceptions.
      3. Final Answer:

        Add boundary checks for index i before accessing str[i] -> Option A
      4. Quick Check:

        Always check index bounds before accessing string [OK]
      Hint: Always check string length before accessing characters [OK]
      Common Mistakes:
      • Ignoring string length checks causing exceptions
      • Removing sign check breaks negative numbers
      • Using char.IsLetter instead of char.IsDigit
      5. Given the input string "+-12", what should a robust atoi implementation return according to standard rules?
      hard
      A. 0
      B. -12
      C. 12
      D. Exception thrown

      Solution

      1. Step 1: Analyze sign characters in input

        The string starts with '+' followed immediately by '-', which is invalid for atoi parsing.
      2. Step 2: According to atoi rules, invalid sign sequence returns 0

        Parsing stops at invalid sequence, so result is 0.
      3. Final Answer:

        0 -> Option A
      4. Quick Check:

        Invalid sign sequence returns 0 [OK]
      Hint: Invalid sign sequences return 0 in atoi [OK]
      Common Mistakes:
      • Parsing multiple signs as valid
      • Returning partial number ignoring invalid signs
      • Throwing exceptions instead of returning 0
      Recommended

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