Roman to Integer Conversion in DSA C# - Time & Space Complexity

Time Complexity: Roman to Integer Conversion

O(n)

Understanding Time Complexity

We want to know how the time to convert a Roman numeral to an integer changes as the input gets longer.

How does the number of steps grow when the Roman numeral string grows?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

public int RomanToInt(string s) {
    int total = 0;
    for (int i = 0; i < s.Length; i++) {
        int value = GetValue(s[i]);
        if (i + 1 < s.Length && value < GetValue(s[i + 1])) {
            total -= value;
        } else {
            total += value;
        }
    }
    return total;
}

private int GetValue(char c) {
    return c switch {
        'I' => 1,
        'V' => 5,
        'X' => 10,
        'L' => 50,
        'C' => 100,
        'D' => 500,
        'M' => 1000,
        _ => 0
    };
}
    

This code converts a Roman numeral string to its integer value by checking each character and deciding to add or subtract its value.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: A single loop that goes through each character of the input string once.
• How many times: Exactly once for each character in the string (n times, where n is string length).

How Execution Grows With Input

As the Roman numeral string gets longer, the number of steps grows directly with its length.

Input Size (n)	Approx. Operations
10	About 10 checks and additions/subtractions
100	About 100 checks and additions/subtractions
1000	About 1000 checks and additions/subtractions

Pattern observation: The work grows evenly and directly with the input size.

Final Time Complexity

Time Complexity: O(n)

This means the time to convert grows in a straight line with the length of the Roman numeral string.

Common Mistake

[X] Wrong: "Because of the subtraction checks, the code does extra loops or nested checks making it slower than linear."

[OK] Correct: The subtraction check is done inside the same single loop, so it does not add extra loops or multiply the work.

Interview Connect

Understanding this linear time complexity helps you explain how your solution scales and why it is efficient for converting Roman numerals.

Self-Check

"What if we used recursion to process each character instead of a loop? How would the time complexity change?"

Practice

1. What is the main rule to convert Roman numerals to integers?

easy

A. Subtract all values from the largest symbol

B. Multiply values of all symbols

C. Add values of symbols, subtract if a smaller symbol is before a larger one

D. Add values only if symbols are in alphabetical order

Solution

1. Step 1: Understand Roman numeral rules

   Roman numerals add values unless a smaller symbol is before a larger one, then subtract.

2. Step 2: Apply rule to conversion

   When converting, add values normally but subtract when a smaller symbol precedes a larger one.

3. Final Answer:

   Add values of symbols, subtract if a smaller symbol is before a larger one -> Option C

4. Quick Check:

   Roman numeral conversion rule = Add values of symbols, subtract if a smaller symbol is before a larger one [OK]

Hint: Subtract only when smaller symbol is before larger one [OK]

Common Mistakes:

• Multiplying values instead of adding/subtracting
• Ignoring subtraction rule
• Adding all values without checking order

2. Which C# code snippet correctly initializes a dictionary for Roman numeral values?

easy

A. var map = new Dictionary { {'I', 1}, {'V', 5} };

B. var map = new Dictionary { {1, 'I'}, {5, 'V'} };

C. var map = new Dictionary { {'I', 1}, {'V', 5} };

D. var map = new Dictionary { {'I', "1"}, {'V', "5"} };

Solution

1. Step 1: Identify correct dictionary types

   Roman numerals are characters mapped to integer values, so Dictionary is correct.

2. Step 2: Check initialization syntax

   Initialization with curly braces and pairs like {'I', 1} is correct syntax in C#.

3. Final Answer:

   var map = new Dictionary { {'I', 1}, {'V', 5} }; -> Option A

4. Quick Check:

   Dictionary with correct pairs = var map = new Dictionary { {'I', 1}, {'V', 5} }; [OK]

Hint: Use Dictionary for Roman numeral mapping [OK]

Common Mistakes:

• Swapping key and value types
• Using string keys instead of char
• Incorrect initialization syntax

3. What is the output of this C# code snippet?

string s = "IX";
var map = new Dictionary { {'I', 1}, {'V', 5}, {'X', 10} };
int result = 0;
for (int i = 0; i < s.Length; i++) {
  if (i + 1 < s.Length && map[s[i]] < map[s[i + 1]]) {
    result -= map[s[i]];
  } else {
    result += map[s[i]];
  }
}
Console.WriteLine(result);

medium

A. 9

B. 11

C. 6

D. 1

Solution

1. Step 1: Analyze loop and conditions

   For 'IX', at i=0: 'I' < 'X' so subtract 1; at i=1: add 10.

2. Step 2: Calculate result

   result = -1 + 10 = 9.

3. Final Answer:

   9 -> Option A

4. Quick Check:

   IX = 9 [OK]

Hint: Subtract when current < next symbol, else add [OK]

Common Mistakes:

• Adding all values without subtraction
• Off-by-one errors in loop
• Incorrect dictionary values

4. Find the error in this C# code for Roman to integer conversion:

var map = new Dictionary { {'I', 1}, {'V', 5}, {'X', 10} };
int result = 0;
for (int i = 0; i < s.Length - 1; i++) {
  if (map[s[i]] < map[s[i + 1]]) {
    result -= map[s[i]];
  } else {
    result += map[s[i]];
  }
}
result += map[s[s.Length - 1]];
Console.WriteLine(result);

medium

A. No error, code works correctly

B. Missing initialization of string s

C. Loop should run till i < s.Length, not s.Length - 1

D. Dictionary keys should be strings, not chars

Solution

1. Step 1: Check variable declarations

   The variable 's' is used but not declared or initialized, causing a compile error.

2. Step 2: Verify loop and dictionary usage

   Loop and dictionary usage are correct; only 's' is missing.

3. Final Answer:

   Missing initialization of string s -> Option B

4. Quick Check:

   Undefined variable s causes error = Missing initialization of string s [OK]

Hint: Always declare and initialize variables before use [OK]

Common Mistakes:

• Forgetting to declare input string
• Incorrect loop range causing index errors
• Wrong dictionary key types

5. Given the Roman numeral string "MCMXCIV", what integer does the following C# code output?

string s = "MCMXCIV";
var map = new Dictionary {
  {'I', 1}, {'V', 5}, {'X', 10}, {'L', 50}, {'C', 100}, {'D', 500}, {'M', 1000}
};
int result = 0;
for (int i = 0; i < s.Length; i++) {
  if (i + 1 < s.Length && map[s[i]] < map[s[i + 1]]) {
    result -= map[s[i]];
  } else {
    result += map[s[i]];
  }
}
Console.WriteLine(result);

hard

A. 1494

B. 1904

C. 2000

D. 1994

Solution

1. Step 1: Break down the Roman numeral "MCMXCIV"

   M=1000, CM=900, XC=90, IV=4; sum = 1000 + 900 + 90 + 4.

2. Step 2: Calculate total value using code logic

   Code subtracts smaller before larger and adds others: 1000 - 100 + 1000 - 10 + 100 - 1 + 5 = 1994.

3. Final Answer:

   1994 -> Option D

4. Quick Check:

   MCMXCIV = 1994 [OK]

Hint: Sum values, subtract when smaller precedes larger [OK]

Common Mistakes:

• Adding all values without subtraction
• Misreading compound numerals like CM or XC
• Incorrect dictionary values