What if you could always know the smallest item instantly without searching?
Why Min Stack Design in DSA C#?
Imagine you have a stack of books, and you want to quickly find the smallest book without taking all books out one by one.
Checking each book manually every time to find the smallest is slow and tiring. You might miss the smallest book or waste time flipping through all books repeatedly.
A Min Stack keeps track of the smallest book at every step, so you can instantly know the smallest without searching through all books.
int FindMin(Stack<int> stack) {
int min = int.MaxValue;
foreach (int item in stack) {
if (item < min) min = item;
}
return min;
}class MinStack { Stack<int> stack = new Stack<int>(); Stack<int> minStack = new Stack<int>(); public void Push(int val) { stack.Push(val); if (minStack.Count == 0 || val <= minStack.Peek()) { minStack.Push(val); } } public int GetMin() { return minStack.Peek(); } }
You can get the smallest item instantly at any time, making your program faster and smarter.
In a game, quickly knowing the lowest score so far helps decide who is winning without checking all scores every time.
Manual search for minimum is slow and error-prone.
Min Stack keeps track of minimum values efficiently.
Instant access to minimum improves performance in many applications.
Practice
Min Stack data structure?Solution
Step 1: Understand the Min Stack concept
A Min Stack is designed to keep track of the minimum element efficiently.Step 2: Identify the main feature
It allows retrieving the minimum element in constant time, unlike a normal stack.Final Answer:
To retrieve the minimum element in constant time -> Option AQuick Check:
Min Stack = fast minimum retrieval [OK]
- Confusing Min Stack with sorting
- Thinking it behaves like a queue
- Assuming it reverses elements
val onto a Min Stack?Solution
Step 1: Check method return type and parameters
Push method should not return a value, so return type is void, and it takes an int parameter.Step 2: Match the correct signature
public void Push(int val) matches: public void Push(int val)Final Answer:
public void Push(int val) -> Option DQuick Check:
Push method = void + int parameter [OK]
- Using wrong return type like int
- Missing parameter in method
- Using wrong parameter type like string
MinStack minStack = new MinStack(); minStack.Push(3); minStack.Push(5); minStack.Push(2); minStack.Push(1); minStack.Pop(); int min = minStack.GetMin(); Console.WriteLine(min);
What will be printed?
Solution
Step 1: Trace the stack after each operation
Push 3 -> stack: [3], min=3 Push 5 -> stack: [3,5], min=3 Push 2 -> stack: [3,5,2], min=2 Push 1 -> stack: [3,5,2,1], min=1 Pop -> removes 1, stack: [3,5,2], min=2Step 2: GetMin after pop
Minimum is now 2 after popping 1.Final Answer:
2 -> Option BQuick Check:
Min after pop = 2 [OK]
- Assuming min stays 1 after pop
- Confusing stack top with min
- Ignoring pop effect on min
public void Pop() {
if(stack.Count > 0) {
stack.Pop();
minStack.Pop();
}}What is the main issue with this implementation?
Solution
Step 1: Understand the role of minStack
minStack should only pop when the popped element equals the current minimum.Step 2: Identify the bug
This code pops minStack every time, even if the popped element is not minimum, causing incorrect min tracking.Final Answer:
It pops from minStack even when the popped element is not the minimum -> Option CQuick Check:
Pop minStack only if popped element == min [OK]
- Always popping minStack blindly
- Not checking stack emptiness (not in this code)
- Confusing push and pop operations
Push, Pop, Top, and GetMin all in O(1) time. Which approach is best?Solution
Step 1: Analyze time complexity requirements
All operations must be O(1), so sorting or scanning is too slow.Step 2: Identify suitable data structure
Using two stacks, one for elements and one for minimums, allows constant time min retrieval.Final Answer:
Use two stacks: one for all elements, one for current minimums -> Option AQuick Check:
Two stacks = O(1) min tracking [OK]
- Sorting stack after each push (slow)
- Using queue instead of stack
- Scanning list for min on each GetMin
Ready to prove it?
Pass the test and this pattern moves unknown
