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DSA C#programming~5 mins

Merge Overlapping Intervals in DSA C# - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is the main goal of the Merge Overlapping Intervals algorithm?
To combine all intervals that overlap into a single continuous interval, so that no intervals in the result overlap.
Click to reveal answer
beginner
Why do we sort intervals by their start time before merging?
Sorting by start time helps us easily find overlapping intervals by comparing each interval only with the previous merged interval.
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beginner
In the Merge Overlapping Intervals algorithm, what do you do when the current interval does not overlap with the last merged interval?
You add the current interval as a new interval to the merged list because it does not overlap with any previous intervals.
Click to reveal answer
beginner
How do you merge two overlapping intervals [start1, end1] and [start2, end2]?
Create a new interval with start = start1 and end = max(end1, end2) to cover both intervals.
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intermediate
What is the time complexity of the Merge Overlapping Intervals algorithm and why?
O(n log n) because sorting the intervals takes O(n log n) time, and merging them in one pass takes O(n) time.
Click to reveal answer
What is the first step in merging overlapping intervals?
ARemove all intervals
BSort intervals by their end time
CReverse the intervals
DSort intervals by their start time
If two intervals [1, 5] and [4, 8] overlap, what is the merged interval?
A[1, 8]
B[4, 8]
C[1, 4]
D[5, 8]
What do you do if the current interval starts after the end of the last merged interval?
AMerge them
BAdd current interval as new merged interval
CDiscard current interval
DExtend last merged interval end to current interval end
What data structure is commonly used to store merged intervals during the process?
AStack
BQueue
CList or Array
DDictionary
What is the overall time complexity of the Merge Overlapping Intervals algorithm?
AO(n log n)
BO(log n)
CO(n)
DO(n^2)
Explain step-by-step how to merge overlapping intervals given a list of intervals.
Think about sorting first and then comparing intervals one by one.
You got /6 concepts.
    Describe how sorting helps in simplifying the merging of overlapping intervals.
    Consider how sorted order reduces comparisons.
    You got /4 concepts.

      Practice

      (1/5)
      1. What is the main purpose of the Merge Overlapping Intervals algorithm?
      easy
      A. To find the maximum number of intervals
      B. To sort intervals by their length
      C. To combine all intervals that overlap into a single continuous interval
      D. To split intervals into smaller parts

      Solution

      1. Step 1: Understand the problem goal

        The algorithm aims to merge intervals that share common parts so they become one continuous interval.
      2. Step 2: Identify the correct purpose

        Among the options, only combining overlapping intervals matches the goal.
      3. Final Answer:

        To combine all intervals that overlap into a single continuous interval -> Option C
      4. Quick Check:

        Merge overlapping intervals = combine overlaps [OK]
      Hint: Think of joining overlapping time slots into one [OK]
      Common Mistakes:
      • Confusing merging with sorting
      • Thinking it splits intervals instead of combining
      • Assuming it counts intervals
      2. Which of the following C# code snippets correctly sorts a list of intervals by their start time before merging?
      easy
      A. intervals.OrderBy(x => x.Length);
      B. intervals.OrderByDescending(x => x.End);
      C. intervals.Sort((a, b) => b.Start.CompareTo(a.Start));
      D. intervals.Sort((a, b) => a.Start.CompareTo(b.Start));

      Solution

      1. Step 1: Identify sorting by start time

        We need to sort intervals by their start property in ascending order.
      2. Step 2: Check each option

        intervals.Sort((a, b) => a.Start.CompareTo(b.Start)); uses Sort with CompareTo on Start ascending, which is correct. Others sort by end descending, start descending, or length, which are incorrect for merging.
      3. Final Answer:

        intervals.Sort((a, b) => a.Start.CompareTo(b.Start)); -> Option D
      4. Quick Check:

        Sort by start ascending = intervals.Sort((a, b) => a.Start.CompareTo(b.Start)); [OK]
      Hint: Sort intervals by start ascending before merging [OK]
      Common Mistakes:
      • Sorting by end time instead of start
      • Sorting descending instead of ascending
      • Sorting by interval length
      3. What is the output of the following C# code that merges overlapping intervals?
      var intervals = new List<(int Start, int End)>{ (1,3), (2,6), (8,10), (15,18) };
      intervals.Sort((a,b) => a.Start.CompareTo(b.Start));
      var merged = new List<(int, int)>();
      foreach(var interval in intervals) {
        if(merged.Count == 0 || merged[^1].End < interval.Start) {
          merged.Add(interval);
        } else {
          var last = merged[^1];
          merged[^1] = (last.Start, Math.Max(last.End, interval.End));
        }
      }
      foreach(var i in merged) Console.Write($"({i.Start},{i.End}) ");
      medium
      A. (1,6) (8,10) (15,18)
      B. (1,3) (2,6) (8,10) (15,18)
      C. (1,10) (15,18)
      D. (1,6) (2,10) (15,18)

      Solution

      1. Step 1: Sort intervals by start

        Sorted intervals: (1,3), (2,6), (8,10), (15,18)
      2. Step 2: Merge overlapping intervals

        (1,3) and (2,6) overlap, merged to (1,6). Others do not overlap, so final merged list is (1,6), (8,10), (15,18).
      3. Final Answer:

        (1,6) (8,10) (15,18) -> Option A
      4. Quick Check:

        Merged intervals = (1,6) (8,10) (15,18) [OK]
      Hint: Merge intervals by comparing current start with last merged end [OK]
      Common Mistakes:
      • Not merging overlapping intervals
      • Merging intervals incorrectly by extending start
      • Printing original intervals without merging
      4. The following code attempts to merge overlapping intervals but has a bug. What is the bug?
      var intervals = new List<(int Start, int End)>{ (1,4), (4,5) };
      intervals.Sort((a,b) => a.Start.CompareTo(b.Start));
      var merged = new List<(int, int)>();
      foreach(var interval in intervals) {
        if(merged.Count == 0 || merged[^1].End <= interval.Start) {
          merged.Add(interval);
        } else {
          var last = merged[^1];
          merged[^1] = (last.Start, Math.Max(last.End, interval.End));
        }
      }
      foreach(var i in merged) Console.Write($"({i.Start},{i.End}) ");
      medium
      A. The condition should use < instead of <= to merge touching intervals
      B. The intervals are not sorted before merging
      C. The merged list is not initialized
      D. The code does not handle empty input

      Solution

      1. Step 1: Analyze the merge condition

        The condition uses merged[^1].End <= interval.Start, which treats touching intervals as non-overlapping.
      2. Step 2: Identify correct condition for merging

        To merge intervals that touch (like (1,4) and (4,5)), use < instead of <= so they merge into (1,5).
      3. Final Answer:

        The condition should use < instead of <= to merge touching intervals -> Option A
      4. Quick Check:

        Use < to merge touching intervals [OK]
      Hint: Use strict less than to merge intervals that touch [OK]
      Common Mistakes:
      • Using <= causes touching intervals to not merge
      • Forgetting to sort intervals
      • Ignoring empty input cases
      5. Given a list of intervals [(1,5), (2,3), (4,8), (10,12), (9,10)], what is the merged list after applying the merge overlapping intervals algorithm?
      hard
      A. [(1,5), (2,3), (4,8), (9,10), (10,12)]
      B. [(1,8), (9,12)]
      C. [(1,3), (4,8), (9,12)]
      D. [(1,8), (10,12)]

      Solution

      1. Step 1: Sort intervals by start

        Sorted intervals: (1,5), (2,3), (4,8), (9,10), (10,12)
      2. Step 2: Merge overlapping intervals step-by-step

        Merge (1,5) and (2,3) -> (1,5); merge (1,5) and (4,8) -> (1,8); merge (9,10) and (10,12) -> (9,12). Final merged intervals: (1,8), (9,12).
      3. Final Answer:

        [(1,8), (9,12)] -> Option B
      4. Quick Check:

        Merged intervals = [(1,8), (9,12)] [OK]
      Hint: Sort then merge overlapping or touching intervals stepwise [OK]
      Common Mistakes:
      • Not merging intervals that overlap inside others
      • Missing to merge touching intervals
      • Returning original intervals without merging
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