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DSA C#programming~10 mins

Memory Layout Comparison Array vs Linked List in DSA C# - Interactive Comparison Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to declare an array of integers with 5 elements.

DSA C#
int[] numbers = new int[[1]];
Drag options to blanks, or click blank then click option'
A5
B(5)
C{5}
D<5>
Attempts:
3 left
💡 Hint
Common Mistakes
Using parentheses instead of square brackets.
Using curly braces which are for initialization, not size.
2fill in blank
medium

Complete the code to create a new node for a singly linked list in C#.

DSA C#
Node newNode = new Node([1]);
Drag options to blanks, or click blank then click option'
Anull
B5
C"data"
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Passing null instead of data.
Passing a string when expecting an integer.
3fill in blank
hard

Fix the error in the linked list traversal code by completing the blank.

DSA C#
while (current != [1]) {
    Console.WriteLine(current.Data);
    current = current.Next;
}
Drag options to blanks, or click blank then click option'
Anull
B0
Chead
Dfalse
Attempts:
3 left
💡 Hint
Common Mistakes
Checking against 0 or false which are not valid for reference types.
Checking against head which is the start, not the end.
4fill in blank
hard

Fill both blanks to create a dictionary that maps array indices to linked list nodes.

DSA C#
Dictionary<int, Node> map = new Dictionary<int, Node>();
for (int i = 0; i [1] array.Length; i++) {
    map.Add(i, [2]);
}
Drag options to blanks, or click blank then click option'
A<
BlinkedList.Head
Carray[i]
DlinkedList.GetNodeAt(i)
Attempts:
3 left
💡 Hint
Common Mistakes
Using > or >= in the loop condition causing no iterations.
Adding array elements instead of linked list nodes.
5fill in blank
hard

Fill all three blanks to create a method that compares memory layout sizes of an array and a linked list.

DSA C#
public void CompareMemory(int[] arr, Node head) {
    int arraySize = sizeof(int) * [1];
    int nodeSize = (sizeof(int) + sizeof(IntPtr)) * [2];
    Console.WriteLine("Array size: " + arraySize + ", Linked list size: " + [3]);
}
Drag options to blanks, or click blank then click option'
Aarr.Length
BCountNodes(head)
CnodeSize
Darr.Length + 1
Attempts:
3 left
💡 Hint
Common Mistakes
Using incorrect length or count values.
Printing wrong variables in the output.

Practice

(1/5)
1. Which of the following best describes the memory layout of an array in C#?
easy
A. Elements are stored in contiguous memory locations.
B. Elements are scattered randomly in memory with pointers linking them.
C. Elements are stored in a tree-like structure in memory.
D. Elements are stored in separate memory blocks with no order.

Solution

  1. Step 1: Understand array memory layout

    Arrays store elements one after another in a continuous block of memory.
  2. Step 2: Compare with other structures

    Unlike linked lists, arrays do not use pointers between elements; they rely on index positions.
  3. Final Answer:

    Elements are stored in contiguous memory locations. -> Option A
  4. Quick Check:

    Array = contiguous memory [OK]
Hint: Arrays use continuous memory blocks, unlike linked lists [OK]
Common Mistakes:
  • Thinking arrays use pointers between elements
  • Confusing linked list layout with array layout
  • Assuming arrays store elements randomly
2. Which C# syntax correctly declares a linked list of integers using the built-in LinkedList<int> class?
easy
A. LinkedList<int> list = LinkedList<int>();
B. LinkedList list = new LinkedList<int>();
C. LinkedList<int> list = new LinkedList<int>();
D. LinkedList<int> list = new LinkedList();

Solution

  1. Step 1: Check correct generic syntax

    In C#, generic collections require specifying the type in angle brackets on both sides when creating an instance.
  2. Step 2: Validate each option

    LinkedList<int> list = new LinkedList<int>(); correctly uses new LinkedList<int>(). Others miss type or use wrong syntax.
  3. Final Answer:

    LinkedList<int> list = new LinkedList<int>(); -> Option C
  4. Quick Check:

    Generic type must be specified on both sides [OK]
Hint: Use new LinkedList<int>() to create linked list [OK]
Common Mistakes:
  • Omitting generic type on constructor
  • Using non-generic LinkedList without type
  • Missing 'new' keyword
3. Consider the following C# code snippet:
int[] arr = new int[3] {10, 20, 30};
LinkedList<int> list = new LinkedList<int>();
list.AddLast(10);
list.AddLast(20);
list.AddLast(30);

Console.WriteLine(arr[1]);
Console.WriteLine(list.First.Next.Value);
What will be the output?
medium
A. 10\n20
B. 20\n20
C. 20\n10
D. 30\n20

Solution

  1. Step 1: Analyze array access

    arr[1] accesses the second element in the array, which is 20.
  2. Step 2: Analyze linked list traversal

    list.First is 10, list.First.Next is 20, so list.First.Next.Value is 20.
  3. Final Answer:

    20\n20 -> Option B
  4. Quick Check:

    Array index 1 and linked list second node both 20 [OK]
Hint: Array index and linked list next node give same value [OK]
Common Mistakes:
  • Confusing linked list first and next nodes
  • Using wrong array index
  • Assuming linked list nodes are zero-indexed
4. The following code attempts to traverse a linked list and print all values:
LinkedList<int> list = new LinkedList<int>();
list.AddLast(1);
list.AddLast(2);
list.AddLast(3);

var node = list.First;
while (node != null)
{
    Console.WriteLine(node.Value);
    node = node.Next.Next;
}
What is the problem with this code?
medium
A. It skips every other node and may cause a NullReferenceException.
B. It will print all nodes correctly without issues.
C. It causes an infinite loop because node never becomes null.
D. It prints nodes in reverse order.

Solution

  1. Step 1: Understand node traversal logic

    The code moves node by two steps each iteration using node = node.Next.Next;.
  2. Step 2: Identify potential error

    If node.Next is null, accessing node.Next.Next causes NullReferenceException. Also, it skips nodes.
  3. Final Answer:

    It skips every other node and may cause a NullReferenceException. -> Option A
  4. Quick Check:

    Skipping nodes and null access cause error [OK]
Hint: Advance node by one, not two, to avoid errors [OK]
Common Mistakes:
  • Assuming node.Next.Next is always valid
  • Not checking for null before accessing Next
  • Thinking it prints all nodes
5. You need to store a large collection of integers where insertions and deletions happen frequently at random positions. Considering memory layout and performance, which data structure is more suitable and why?
hard
A. Array, because contiguous memory improves insertion speed.
B. Array, because it uses pointers to link elements for fast insertion.
C. Linked list, because it stores elements contiguously for better cache performance.
D. Linked list, because nodes can be inserted or removed without shifting elements.

Solution

  1. Step 1: Analyze insertion and deletion costs

    Arrays require shifting elements for insertions/deletions at random positions, which is costly.
  2. Step 2: Understand linked list advantages

    Linked lists store elements in nodes linked by pointers, allowing insertions/deletions by changing pointers without shifting.
  3. Final Answer:

    Linked list, because nodes can be inserted or removed without shifting elements. -> Option D
  4. Quick Check:

    Linked list = efficient random insert/delete [OK]
Hint: Use linked list for frequent random insertions/deletions [OK]
Common Mistakes:
  • Assuming arrays insert/delete faster due to contiguous memory
  • Confusing pointer use in arrays
  • Ignoring shifting cost in arrays
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10 questions~5 mineasy hard