Majority Element Moore's Voting Algorithm in DSA C# - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the Majority Element in an array?

The Majority Element is the element that appears more than half the size of the array (n/2 times).

beginner

What is the main idea behind Moore's Voting Algorithm?

It finds a candidate for majority element by canceling out different elements and then verifies if it is actually the majority.

intermediate

In Moore's Voting Algorithm, what happens when the count reaches zero?

When count reaches zero, the algorithm picks the current element as a new candidate for majority element.

intermediate

Why do we need a second pass in Moore's Voting Algorithm?

The second pass verifies if the candidate found actually appears more than n/2 times in the array.

beginner

What is the time complexity of Moore's Voting Algorithm?

The time complexity is O(n) because it makes at most two passes over the array.

What does Moore's Voting Algorithm primarily do?

A Counts frequency of all elements using a hash map

B Sorts the array to find the majority element

C Removes duplicates from the array

D Finds the majority element candidate by canceling out different elements

Moore's Voting Algorithm finds a candidate by canceling out different elements, not by sorting or counting all frequencies.

When does Moore's Voting Algorithm change its candidate element?

A At the start of the array only

B When count is positive

C When count becomes zero

D When count is negative

The candidate changes when the count reaches zero, meaning previous candidate is canceled out.

What is the minimum number of times the majority element appears in the array?

A More than n/2 times

B Exactly n/2 times

C Less than n/2 times

D At least once

By definition, majority element appears more than half the size of the array.

Why is a second pass needed after finding the candidate in Moore's Voting Algorithm?

A To sort the array

B To verify the candidate is actually the majority element

C To count all elements again

D No second pass is needed

The second pass confirms the candidate appears more than n/2 times.

What is the space complexity of Moore's Voting Algorithm?

A O(1)

B O(n)

C O(log n)

D O(n^2)

Moore's Voting Algorithm uses constant extra space, only a few variables.

Explain how Moore's Voting Algorithm finds the majority element in an array.

Think about how the algorithm cancels out pairs of different elements.

Describe why Moore's Voting Algorithm is efficient compared to counting frequencies of all elements.

Focus on time and space usage differences.

Practice

1. What is the main purpose of Moore's Voting Algorithm in an array of integers?

easy

A. To find the element that appears more than half the time

B. To sort the array in ascending order

C. To find the smallest element in the array

D. To count the total number of unique elements

Solution

1. Step 1: Understand the problem Moore's Voting Algorithm solves

   The algorithm is designed to find the majority element, which is the element that appears more than half the time in the array.

2. Step 2: Compare with other options

   Sorting, finding smallest element, or counting unique elements are not the goals of this algorithm.

3. Final Answer:

   To find the element that appears more than half the time -> Option A

4. Quick Check:

   Majority element = element with >50% frequency [OK]

Hint: Majority element appears more than half times [OK]

Common Mistakes:

• Thinking it sorts the array
• Confusing majority with most frequent element without >50%
• Assuming it finds smallest or unique counts

2. Which of the following is the correct way to initialize the candidate and count variables in C# for Moore's Voting Algorithm?

easy

A. int candidate = -1; int count = 0;

B. int candidate; int count = 1;

C. int candidate = 0; int count = 0;

D. int candidate = 0; int count = 1;

Solution

1. Step 1: Understand initialization requirements

   Candidate should start with a default value (like 0) and count should start at 0 before processing the array.

2. Step 2: Check each option

   int candidate = 0; int count = 0; initializes candidate to 0 and count to 0, which is standard. int candidate; int count = 1; leaves candidate uninitialized. int candidate = -1; int count = 0; uses -1 which may be valid but less common. int candidate = 0; int count = 1; starts count at 1 which is incorrect before any element is processed.

3. Final Answer:

   int candidate = 0; int count = 0; -> Option C

4. Quick Check:

   Initialize candidate=0 and count=0 before loop [OK]

Hint: Start count at zero before scanning array [OK]

Common Mistakes:

• Leaving candidate uninitialized
• Starting count at 1 before processing
• Using invalid default candidate values

3. What will be the output of the following C# code snippet using Moore's Voting Algorithm?

int[] nums = {2, 2, 1, 1, 1, 2, 2};
int candidate = 0, count = 0;
foreach (int num in nums) {
  if (count == 0) candidate = num;
  count += (num == candidate) ? 1 : -1;
}
Console.WriteLine(candidate);

medium

A. 1

B. 2

C. 0

D. Error

Solution

1. Step 1: Trace the candidate and count updates

   Start with candidate=0, count=0. Iterate nums:
   - num=2: count=0, candidate=2, count=1
   - num=2: same candidate, count=2
   - num=1: different, count=1
   - num=1: different, count=0
   - num=1: count=0, candidate=1, count=1
   - num=2: different, count=0
   - num=2: count=0, candidate=2, count=1

2. Step 2: Final candidate after loop

   The final candidate is 2 after processing all elements.

3. Final Answer:

   2 -> Option B

4. Quick Check:

   Final candidate = 2 [OK]

Hint: Track count changes; candidate updates when count hits zero [OK]

Common Mistakes:

• Not updating candidate when count is zero
• Confusing candidate with last element
• Ignoring count increments and decrements

4. Identify the error in the following C# implementation of Moore's Voting Algorithm:

int[] nums = {3, 3, 4, 2, 4, 4, 2, 4, 4};
int candidate = 0, count = 0;
foreach (int num in nums) {
  if (count == 0) candidate = num;
  if (num == candidate) count++;
  else count++;
}
Console.WriteLine(candidate);

medium

A. Count is incremented in both if and else, should decrement in else

B. Candidate is not updated when count is zero

C. Candidate should be initialized to -1

D. The array nums is empty

Solution

1. Step 1: Analyze count updates in loop

   Count is incremented in both if and else branches, so count never decreases. This breaks the algorithm logic.

2. Step 2: Correct the else branch

   In Moore's Voting Algorithm, count should decrement when current number is not the candidate.

3. Final Answer:

   Count is incremented in both if and else, should decrement in else -> Option A

4. Quick Check:

   Count must decrease when num != candidate [OK]

Hint: Count decreases when element differs from candidate [OK]

Common Mistakes:

• Incrementing count in else instead of decrementing
• Not updating candidate when count is zero
• Assuming candidate initialization causes error

5. Given an array int[] nums = {1, 2, 3, 2, 2, 2, 5, 2, 2}, how can you verify after Moore's Voting Algorithm that the candidate is actually the majority element?

hard

A. Sort the array and pick the middle element

B. Assume candidate is majority without verification

C. Check if candidate is the first element in the array

D. Count the occurrences of candidate in the array and check if it is more than half the array length

Solution

1. Step 1: Understand Moore's Voting Algorithm limitation

   The algorithm finds a candidate but does not guarantee it is majority if none exists.

2. Step 2: Verify candidate by counting occurrences

   Count how many times candidate appears and compare with half the array length to confirm majority.

3. Final Answer:

   Count the occurrences of candidate in the array and check if it is more than half the array length -> Option D

4. Quick Check:

   Verify candidate count > n/2 after algorithm [OK]

Hint: Always verify candidate count > half array length [OK]

Common Mistakes:

• Skipping verification step
• Assuming candidate is always majority
• Using sorting instead of counting