Kadane's Algorithm Maximum Subarray in DSA C# - Cheat Sheet & Quick Revision

Recall & Review

beginner

What problem does Kadane's Algorithm solve?

Kadane's Algorithm finds the maximum sum of a contiguous subarray within a one-dimensional array of numbers.

beginner

What is the main idea behind Kadane's Algorithm?

It keeps track of the current subarray sum and resets it to zero if it becomes negative, while updating the maximum sum found so far.

beginner

In Kadane's Algorithm, what do you do when the current sum becomes negative?

You reset the current sum to zero because continuing with a negative sum will reduce the total sum of any future subarray.

intermediate

What is the time complexity of Kadane's Algorithm?

Kadane's Algorithm runs in O(n) time, where n is the number of elements in the array, because it processes each element once.

intermediate

Show the C# code snippet for Kadane's Algorithm to find the maximum subarray sum.

int MaxSubArray(int[] nums) { int maxSum = nums[0]; int currentSum = 0; foreach (int num in nums) { currentSum += num; if (currentSum > maxSum) maxSum = currentSum; if (currentSum < 0) currentSum = 0; } return maxSum; }

What does Kadane's Algorithm return for the array [-2,1,-3,4,-1,2,1,-5,4]?

A 4

B 7

C 6

D 5

The maximum sum contiguous subarray is [4,-1,2,1] which sums to 6.

What is the initial value of maxSum in Kadane's Algorithm?

A The first element of the array

B Integer.MaxValue

C 0

D Integer.MinValue

maxSum is initialized to the first element to handle arrays with all negative numbers.

Why do we reset currentSum to zero when it becomes negative?

A To avoid overflow

B To find the minimum subarray

C To restart the algorithm

D Because negative sums reduce the total sum of future subarrays

A negative currentSum will only decrease the sum of any subarray that includes it, so resetting helps find a better sum.

What is the space complexity of Kadane's Algorithm?

A O(1)

B O(log n)

C O(n)

D O(n^2)

Kadane's Algorithm uses only a few variables, so it runs in constant space.

Which of these is NOT true about Kadane's Algorithm?

A It finds the maximum sum of a contiguous subarray

B It works only for positive numbers

C It runs in linear time

D It resets current sum when negative

Kadane's Algorithm works for arrays with negative numbers as well.

Explain how Kadane's Algorithm finds the maximum sum of a contiguous subarray.

Think about how the algorithm decides to keep or discard parts of the array.

Write the steps to implement Kadane's Algorithm in C#.

Focus on the variables and the conditions inside the loop.

Practice

1. What does Kadane's Algorithm primarily help to find in an array of integers?

easy

A. The minimum element in the array

B. The maximum sum of a contiguous subarray

C. The total sum of all elements

D. The number of positive elements

Solution

1. Step 1: Understand the problem Kadane's Algorithm solves

   Kadane's Algorithm is designed to find the maximum sum of any contiguous subarray within a given array.

2. Step 2: Differentiate from other array operations

   It does not find minimum elements, total sums, or count positives, but specifically the largest sum of a continuous segment.

3. Final Answer:

   The maximum sum of a contiguous subarray -> Option B

4. Quick Check:

   Maximum subarray sum = The maximum sum of a contiguous subarray [OK]

Hint: Kadane's finds max sum in continuous subarray fast [OK]

Common Mistakes:

• Confusing maximum subarray sum with total array sum
• Thinking it finds minimum or count of elements
• Assuming it works on non-contiguous elements

2. Which of the following is the correct initialization for Kadane's Algorithm variables in C#?

easy

A. int maxSoFar = 0, maxEndingHere = 0;

B. int maxSoFar = int.MaxValue, maxEndingHere = int.MaxValue;

C. int maxSoFar = int.MinValue, maxEndingHere = 0;

D. int maxSoFar = 0, maxEndingHere = int.MinValue;

Solution

1. Step 1: Understand variable roles in Kadane's Algorithm

   maxSoFar stores the maximum sum found so far, so it should start very low (int.MinValue) to handle negative arrays. maxEndingHere tracks current subarray sum and starts at 0.

2. Step 2: Check each initialization

   int maxSoFar = int.MinValue, maxEndingHere = 0; correctly initializes maxSoFar to int.MinValue and maxEndingHere to 0, allowing correct updates during iteration.

3. Final Answer:

   int maxSoFar = int.MinValue, maxEndingHere = 0; -> Option C

4. Quick Check:

   Initialize maxSoFar low, maxEndingHere zero [OK]

Hint: Start maxSoFar at int.MinValue to handle negatives [OK]

Common Mistakes:

• Initializing maxSoFar to 0 causes wrong results with all negatives
• Setting maxEndingHere to int.MinValue breaks sum calculation
• Using int.MaxValue causes logic errors

3. What is the output of the following C# code using Kadane's Algorithm?

int[] arr = { -2, 1, -3, 4, -1, 2, 1, -5, 4 };
int maxSoFar = int.MinValue, maxEndingHere = 0;
foreach (int x in arr) {
    maxEndingHere = Math.Max(x, maxEndingHere + x);
    maxSoFar = Math.Max(maxSoFar, maxEndingHere);
}
Console.WriteLine(maxSoFar);

medium

A. 6

B. 7

C. 5

D. 4

Solution

1. Step 1: Trace Kadane's Algorithm on the array

   Iterate and update maxEndingHere and maxSoFar:
   - Start maxSoFar = -∞, maxEndingHere = 0
   - x=-2: maxEndingHere=max(-2,0-2)=-2; maxSoFar=max(-∞,-2)=-2
   - x=1: maxEndingHere=max(1,-2+1)=1; maxSoFar=max(-2,1)=1
   - x=-3: maxEndingHere=max(-3,1-3)=-2; maxSoFar=1
   - x=4: maxEndingHere=max(4,-2+4)=4; maxSoFar=4
   - x=-1: maxEndingHere=max(-1,4-1)=3; maxSoFar=4
   - x=2: maxEndingHere=max(2,3+2)=5; maxSoFar=5
   - x=1: maxEndingHere=max(1,5+1)=6; maxSoFar=6
   - x=-5: maxEndingHere=max(-5,6-5)=1; maxSoFar=6
   - x=4: maxEndingHere=max(4,1+4)=5; maxSoFar=6

2. Step 2: Identify the maximum sum found

   The maximum sum found is 6, which corresponds to the subarray [4, -1, 2, 1].

3. Final Answer:

   6 -> Option A

4. Quick Check:

   Max subarray sum = 6 [OK]

Hint: Track maxEndingHere and maxSoFar stepwise [OK]

Common Mistakes:

• Adding all positive numbers incorrectly
• Not resetting maxEndingHere properly
• Confusing maxSoFar with last maxEndingHere

4. Identify the bug in this Kadane's Algorithm implementation and select the fix:

int maxSoFar = 0, maxEndingHere = 0;
foreach (int x in arr) {
    maxEndingHere += x;
    if (maxSoFar < maxEndingHere) maxSoFar = maxEndingHere;
    if (maxEndingHere < 0) maxEndingHere = 0;
}
return maxSoFar;

medium

A. Add a check to skip negative numbers in the loop

B. Remove resetting maxEndingHere to 0 when negative

C. Change maxEndingHere += x to maxEndingHere = x

D. Initialize maxSoFar to int.MinValue instead of 0

Solution

1. Step 1: Analyze initialization impact

   Initializing maxSoFar to 0 causes wrong results if all numbers are negative, as maxSoFar will never be less than 0.

2. Step 2: Correct initialization to handle negatives

   Setting maxSoFar to int.MinValue allows the algorithm to correctly track maximum sums even if all elements are negative.

3. Final Answer:

   Initialize maxSoFar to int.MinValue instead of 0 -> Option D

4. Quick Check:

   Use int.MinValue for maxSoFar to handle negatives [OK]

Hint: Use int.MinValue for maxSoFar to handle all negatives [OK]

Common Mistakes:

• Leaving maxSoFar at 0 causes wrong max for negative arrays
• Removing reset breaks Kadane's logic
• Changing addition to assignment loses cumulative sum

5. Given an array of integers, how would you modify Kadane's Algorithm to also return the start and end indices of the maximum sum subarray?

hard

A. Track temporary start index when maxEndingHere resets and update final start/end when maxSoFar changes

B. Store all subarrays and pick the max sum one at the end

C. Use two nested loops to find all subarrays and their sums

D. Return the first positive element's index as start and end

Solution

1. Step 1: Understand Kadane's Algorithm extension

   When maxEndingHere resets to current element, record that index as temporary start. When maxSoFar updates, update final start and end indices accordingly.

2. Step 2: Avoid brute force methods

   Storing all subarrays and using two nested loops are brute force and inefficient. Returning the first positive element's index as start and end is incorrect as max subarray may not start at first positive element.

3. Final Answer:

   Track temporary start index when maxEndingHere resets and update final start/end when maxSoFar changes -> Option A

4. Quick Check:

   Track indices on resets and max updates [OK]

Hint: Update start index when resetting maxEndingHere [OK]

Common Mistakes:

• Using nested loops instead of Kadane's linear approach
• Ignoring index tracking during sum updates
• Assuming max subarray always starts at first positive