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DSA C#programming~10 mins

Insert at Specific Position in Doubly Linked List in DSA C# - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a new node with the given data.

DSA C#
Node newNode = new Node([1]);
Drag options to blanks, or click blank then click option'
Avalue
Bdata
Citem
DnodeData
Attempts:
3 left
💡 Hint
Common Mistakes
Using a variable name that is not defined in the method.
Confusing the node variable with the data variable.
2fill in blank
medium

Complete the code to check if the position is 1 (insert at head).

DSA C#
if (position == [1]) { InsertAtHead(newNode); return; }
Drag options to blanks, or click blank then click option'
A1
B0
C-1
Dposition
Attempts:
3 left
💡 Hint
Common Mistakes
Checking if position equals 0 instead of 1.
Using assignment operator '=' instead of comparison '=='.
3fill in blank
hard

Fix the error in the loop that moves to the node before the insertion point.

DSA C#
for (int i = 1; i < [1] - 1; i++) { current = current.Next; }
Drag options to blanks, or click blank then click option'
Aposition
Bpos
Cindex
Dcount
Attempts:
3 left
💡 Hint
Common Mistakes
Using an undefined variable like pos or index.
Looping too many or too few times causing null reference.
4fill in blank
hard

Fill both blanks to correctly link the new node between nodes.

DSA C#
newNode.Next = current.[1];
newNode.Prev = current;
current.[2] = newNode;
Drag options to blanks, or click blank then click option'
ANext
BPrev
CNextNode
DPrevious
Attempts:
3 left
💡 Hint
Common Mistakes
Using Prev instead of Next for forward links.
Mixing up the order of assignments causing broken links.
5fill in blank
hard

Fill all three blanks to update the previous pointer of the next node if it exists.

DSA C#
if (newNode.[1] != null) {
    newNode.[2].[3] = newNode;
}
Drag options to blanks, or click blank then click option'
ANext
BPrev
Attempts:
3 left
💡 Hint
Common Mistakes
Using Prev instead of Next in the if condition.
Not updating the previous pointer of the next node.

Practice

(1/5)
1. What happens when you insert a new node at position 1 in a doubly linked list?
easy
A. The new node is ignored because position 1 is invalid.
B. The new node is added at the end of the list.
C. The new node becomes the new head of the list.
D. The list is reversed before insertion.

Solution

  1. Step 1: Understand position 1 in doubly linked list

    Position 1 means the start of the list, so the new node should be the first element.
  2. Step 2: Insert new node at head

    The new node's next pointer points to the old head, and the old head's previous pointer points back to the new node.
  3. Final Answer:

    The new node becomes the new head of the list. -> Option C
  4. Quick Check:

    Insert at position 1 = new head [OK]
Hint: Position 1 means new head insertion [OK]
Common Mistakes:
  • Thinking position 1 means end of list
  • Ignoring previous pointer update
  • Assuming position 1 is invalid
2. Which of the following is the correct syntax to insert a new node at position 3 in a doubly linked list in C#?
easy
A. InsertAtPosition(newNode, 3);
B. InsertAtPosition(3, newNode);
C. InsertNodeAt(3, newNode);
D. AddNodeAtPosition(newNode, 3);

Solution

  1. Step 1: Check method parameter order

    The common pattern is to pass the node first, then the position.
  2. Step 2: Match method name and parameters

    InsertAtPosition(newNode, 3) matches the expected syntax for inserting at position 3.
  3. Final Answer:

    InsertAtPosition(newNode, 3); -> Option A
  4. Quick Check:

    Node first, position second = InsertAtPosition(newNode, 3); [OK]
Hint: Node comes before position in method call [OK]
Common Mistakes:
  • Swapping parameter order
  • Using incorrect method names
  • Passing position before node
3. Given the doubly linked list: 10 <-> 20 <-> 30 <-> null, what is the list after inserting 15 at position 2?
medium
A. 10 <-> 15 <-> 20 <-> 30 <-> null
B. 15 <-> 10 <-> 20 <-> 30 <-> null
C. 10 <-> 20 <-> 15 <-> 30 <-> null
D. 10 <-> 20 <-> 30 <-> 15 <-> null

Solution

  1. Step 1: Identify position 2 in the list

    Position 2 means after the first node (10), so new node goes between 10 and 20.
  2. Step 2: Insert 15 between 10 and 20

    Update pointers: 10's next to 15, 15's previous to 10, 15's next to 20, 20's previous to 15.
  3. Final Answer:

    10 <-> 15 <-> 20 <-> 30 <-> null -> Option A
  4. Quick Check:

    Insert at position 2 = between first and second nodes [OK]
Hint: Position 2 means insert after first node [OK]
Common Mistakes:
  • Inserting before first node
  • Inserting at wrong position
  • Not updating previous pointers
4. What is the error in the following code snippet for inserting at position 3 in a doubly linked list?
Node newNode = new Node(25);
Node temp = head;
for (int i = 1; i < 2; i++) {
    temp = temp.next;
}
newNode.next = temp.next;
newNode.prev = temp;
temp.next.prev = newNode;
temp.next = newNode;
medium
A. The loop should run until i < 2, not i < 3.
B. temp.next.prev = newNode; causes null reference if temp.next is null.
C. newNode.prev should be set to temp.prev instead of temp.
D. The newNode.next assignment is missing.

Solution

  1. Step 1: Analyze loop and temp position

    The loop moves temp to the node at position 2, so temp.next might be null if list ends there.
  2. Step 2: Check pointer updates for null safety

    Accessing temp.next.prev without checking if temp.next is null can cause a runtime error.
  3. Final Answer:

    temp.next.prev = newNode; causes null reference if temp.next is null. -> Option B
  4. Quick Check:

    Check for null before accessing temp.next.prev [OK]
Hint: Always check temp.next for null before accessing prev [OK]
Common Mistakes:
  • Ignoring null pointer checks
  • Wrong loop range causing off-by-one
  • Incorrect pointer assignments
5. You have a doubly linked list: 5 <-> 10 <-> 15 <-> 20 <-> null. You want to insert a node with value 12 at position 3. After insertion, what will be the correct order of nodes?
medium
A. 5 <-> 10 <-> 15 <-> 20 <-> 12 <-> null
B. 5 <-> 12 <-> 10 <-> 15 <-> 20 <-> null
C. 12 <-> 5 <-> 10 <-> 15 <-> 20 <-> null
D. 5 <-> 10 <-> 12 <-> 15 <-> 20 <-> null

Solution

  1. Step 1: Identify position 3 in the list

    Position 3 means the new node should be placed after the second node (10) and before the third node (15).
  2. Step 2: Insert node with value 12 between 10 and 15

    Update pointers: 10's next to 12, 12's previous to 10, 12's next to 15, 15's previous to 12.
  3. Final Answer:

    5 <-> 10 <-> 12 <-> 15 <-> 20 <-> null -> Option D
  4. Quick Check:

    Insert at position 3 places node between second and third nodes [OK]
Hint: Insert at position n means between nodes n-1 and n [OK]
Common Mistakes:
  • Inserting at wrong position
  • Not updating both next and prev pointers
  • Confusing position numbering
Recommended

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10 questions~5 mineasy hard