Delete a Node from Circular Linked List in DSA C# - Time & Space Complexity

Time Complexity: Delete a Node from Circular Linked List

O(n)

Understanding Time Complexity

When deleting a node from a circular linked list, we want to know how the time needed changes as the list grows.

We ask: How many steps does it take to find and remove the node?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

public void DeleteNode(int key) {
    if (head == null) return;
    Node current = head, prev = null;
    do {
        if (current.data == key) {
            if (prev != null) prev.next = current.next;
            else {
                // If the list has only one node
                if (current.next == head) {
                    head = null;
                } else {
                    // Find the last node to update its next pointer
                    Node last = head;
                    while (last.next != head) {
                        last = last.next;
                    }
                    head = current.next;
                    last.next = head;
                }
            }
            return;
        }
        prev = current;
        current = current.next;
    } while (current != head);
}
    

This code searches the circular linked list for a node with the given key and deletes it if found.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: Looping through nodes to find the target node.
• How many times: Up to n times, where n is the number of nodes in the list.

How Execution Grows With Input

As the list grows, the number of steps to find the node grows roughly the same.

Input Size (n)	Approx. Operations
10	Up to 10 checks
100	Up to 100 checks
1000	Up to 1000 checks

Pattern observation: The steps grow linearly with the number of nodes.

Final Time Complexity

Time Complexity: O(n)

This means the time to delete a node grows directly with the list size.

Common Mistake

[X] Wrong: "Deleting a node is always constant time because we just change pointers."

[OK] Correct: We must first find the node, which can take time proportional to the list size.

Interview Connect

Understanding this helps you explain how linked lists work and how operations depend on list size, a key skill in interviews.

Self-Check

"What if the list kept a direct reference to the node to delete? How would the time complexity change?"

Practice

1. What happens when you delete the only node in a circular linked list?

easy

A. The list becomes a linear linked list.

B. The list still contains one node pointing to itself.

C. The list becomes empty (null).

D. The list throws an error.

Solution

1. Step 1: Understand the structure of a single-node circular linked list

   In a circular linked list with one node, the node points to itself.

2. Step 2: Delete the only node

   Removing this node leaves no nodes, so the list becomes empty (null).

3. Final Answer:

   The list becomes empty (null). -> Option C

4. Quick Check:

   Deleting the only node empties the list [OK]

Hint: Deleting last node empties the list, no nodes remain [OK]

Common Mistakes:

• Assuming list still has one node after deletion
• Thinking list becomes linear instead of empty
• Expecting an error on deletion

2. Which of the following is the correct way to update the head pointer when deleting the head node in a circular linked list?

easy

A. head = head.next;

B. head = null;

C. head = head.prev;

D. head = head.next.next;

Solution

1. Step 1: Identify the new head after deleting the current head

   When deleting the head node, the new head should be the next node in the list.

2. Step 2: Update the head pointer

   Assign head to head.next to point to the next node.

3. Final Answer:

   head = head.next; -> Option A

4. Quick Check:

   New head is next node after deletion [OK]

Hint: After deleting head, move head pointer to next node [OK]

Common Mistakes:

• Setting head to null incorrectly
• Using head.prev which is invalid in singly circular list
• Skipping updating head pointer

3. What will be the output after deleting node with value 3 from the circular linked list: 1 -> 2 -> 3 -> 4 -> (back to 1)?

Node head = new Node(1);
head.next = new Node(2);
head.next.next = new Node(3);
head.next.next.next = new Node(4);
head.next.next.next.next = head;
// Delete node with value 3
// After deletion, print list starting from head

medium

A. 2 -> 3 -> 4 -> (back to 2)

B. 1 -> 2 -> 3 -> 4 -> (back to 1)

C. 1 -> 2 -> (back to 1)

D. 1 -> 2 -> 4 -> (back to 1)

Solution

1. Step 1: Identify node to delete and its previous node

   Node with value 3 is after node with value 2.

2. Step 2: Update previous node's next pointer

   Set node 2's next to node 4, skipping node 3.

3. Final Answer:

   1 -> 2 -> 4 -> (back to 1) -> Option D

4. Quick Check:

   Node 3 removed, list links 2 to 4 [OK]

Hint: Link previous node to next of deleted node [OK]

Common Mistakes:

• Not updating previous node's next pointer
• Deleting wrong node
• Breaking circular link

4. Given this code snippet to delete a node from a circular linked list, what is the bug?

Node current = head;
while (current.next != head && current.next.data != key) {
    current = current.next;
}
if (current.next.data == key) {
    current.next = current.next.next;
}

medium

A. Does not handle deleting the head node correctly.

B. Does not update head pointer after deletion.

C. Deletes multiple nodes instead of one.

D. Infinite loop if key not found.

Solution

1. Step 1: Analyze deletion logic

   The code finds the node before the target and skips the target node.

2. Step 2: Check head pointer update

   If the deleted node is head, head pointer is not updated, causing inconsistency.

3. Final Answer:

   Does not update head pointer after deletion. -> Option B

4. Quick Check:

   Head pointer must update if head node deleted [OK]

Hint: Always update head if deleted node is head [OK]

Common Mistakes:

• Ignoring head pointer update
• Assuming deletion always non-head
• Not checking if key exists

5. You have a circular linked list with nodes: 10 -> 20 -> 30 -> 40 -> (back to 10). You want to delete the node with value 10 (head node). Which steps correctly delete the head and maintain the circular structure?

hard

A. Find last node, set its next to head.next, update head to head.next.

B. Set head to null directly.

C. Set head to head.next without changing last node's next.

D. Remove head and leave last node pointing to null.

Solution

1. Step 1: Find the last node in the circular list

   Traverse nodes until node.next == head to find last node (node with value 40).

2. Step 2: Update last node's next pointer and head

   Set last node's next to head.next (node 20), then update head to head.next.

3. Final Answer:

   Find last node, set its next to head.next, update head to head.next. -> Option A

4. Quick Check:

   Last node points to new head, list remains circular [OK]

Hint: Update last node's next and move head to next node [OK]

Common Mistakes:

• Not updating last node's next pointer
• Setting head to null incorrectly
• Breaking circular link by pointing to null