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DSA C#programming~10 mins

Array Insertion at Beginning in DSA C# - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to insert a new element at the beginning of the array.

DSA C#
int[] arr = {1, 2, 3, 4};
int newElement = 0;
int[] newArr = new int[arr.Length + 1];
newArr[0] = [1];
for (int i = 0; i < arr.Length; i++) {
    newArr[i + 1] = arr[i];
}
Drag options to blanks, or click blank then click option'
Aarr.Length
Barr[0]
C0
DnewElement
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning arr[0] instead of the new element.
Using an index out of range.
Not increasing the array size.
2fill in blank
medium

Complete the code to shift elements right to make space at the beginning.

DSA C#
int[] arr = {5, 6, 7};
int[] newArr = new int[arr.Length + 1];
for (int i = arr.Length - 1; i >= 0; i--) {
    newArr[i + 1] = [1];
}
Drag options to blanks, or click blank then click option'
Aarr[i]
BnewArr[i]
Carr[i + 1]
Di
Attempts:
3 left
💡 Hint
Common Mistakes
Using newArr[i] instead of arr[i].
Using wrong index like i+1 on arr.
Looping in wrong direction.
3fill in blank
hard

Fix the error in the code to correctly insert at the beginning.

DSA C#
int[] arr = {10, 20, 30};
int newElement = 5;
int[] newArr = new int[arr.Length + 1];
for (int i = 0; i < arr.Length; i++) {
    newArr[i + 1] = arr[i];
}
newArr[0] = [1];
Drag options to blanks, or click blank then click option'
Aarr[0]
BnewElement
Carr[arr.Length]
DnewArr[1]
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning arr[0] instead of newElement.
Using an invalid index like arr[arr.Length].
Assigning to newArr[1] instead of newArr[0].
4fill in blank
hard

Fill both blanks to create a new array with the element inserted at the beginning.

DSA C#
int[] arr = {3, 4, 5};
int newElement = 2;
int[] newArr = new int[arr.Length + 1];
newArr[[1]] = newElement;
for (int i = 0; i < arr.Length; i++) {
    newArr[[2]] = arr[i];
}
Drag options to blanks, or click blank then click option'
A0
Bi + 1
Ci
Darr.Length
Attempts:
3 left
💡 Hint
Common Mistakes
Putting new element at wrong index.
Not shifting elements correctly.
Using i instead of i+1 for newArr index.
5fill in blank
hard

Fill all three blanks to insert a new element at the beginning and print the new array.

DSA C#
int[] arr = {7, 8, 9};
int newElement = 6;
int[] newArr = new int[arr.Length + 1];
newArr[[1]] = newElement;
for (int i = 0; i < arr.Length; i++) {
    newArr[[2]] = arr[i];
}
for (int i = 0; i < newArr.Length; i++) {
    Console.Write(newArr[[3]] + " ");
}
Drag options to blanks, or click blank then click option'
A0
Bi + 1
Ci
DnewElement
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong indices for insertion or shifting.
Printing newElement instead of array elements.
Off-by-one errors in loops.

Practice

(1/5)
1. What happens when you insert an element at the beginning of a fixed-size array in C#?
easy
A. The last element is removed and the new element is added at the start.
B. The new element replaces the first element without shifting others.
C. The array size automatically increases to fit the new element.
D. All existing elements shift one position to the right to make space.

Solution

  1. Step 1: Understand fixed-size array behavior

    In C#, arrays have fixed size, so to insert at the beginning, elements must shift right.
  2. Step 2: Effect of insertion at index 0

    The element at index 0 is replaced by the new element, and all others move one index higher.
  3. Final Answer:

    All existing elements shift one position to the right to make space. -> Option D
  4. Quick Check:

    Insert at start = shift right [OK]
Hint: Insert at start means shift all elements right [OK]
Common Mistakes:
  • Thinking array size grows automatically
  • Replacing first element without shifting
  • Removing last element silently
2. Which of the following C# code snippets correctly inserts an integer 5 at the beginning of an array arr of size 5, shifting elements right?
easy
A. for (int i = arr.Length - 1; i > 0; i--) { arr[i] = arr[i - 1]; } arr[0] = 5;
B. for (int i = 0; i < arr.Length - 1; i++) { arr[i] = arr[i + 1]; } arr[arr.Length - 1] = 5;
C. arr[0] = 5; // No shifting needed
D. arr[arr.Length] = 5; // Add at end

Solution

  1. Step 1: Identify correct loop for shifting right

    Loop must start from the end and move elements one step right to avoid overwriting.
  2. Step 2: Assign new value at index 0

    After shifting, assign 5 to arr[0].
  3. Final Answer:

    for (int i = arr.Length - 1; i > 0; i--) { arr[i] = arr[i - 1]; } arr[0] = 5; -> Option A
  4. Quick Check:

    Shift right from end, then insert [OK]
Hint: Shift from end to start to avoid overwrite [OK]
Common Mistakes:
  • Shifting left instead of right
  • Assigning without shifting
  • Using invalid index arr.Length
3. What is the output of the following C# code?
int[] arr = {10, 20, 30, 40, 50};
for (int i = arr.Length - 1; i > 0; i--) {
    arr[i] = arr[i - 1];
}
arr[0] = 5;
foreach (int num in arr) {
    Console.Write(num + " ");
}
medium
A. 5 10 20 30 50
B. 5 10 20 30 40
C. 5 20 30 40 50
D. 10 5 20 30 40

Solution

  1. Step 1: Shift elements right

    Elements move right: arr[4]=arr[3]=40, arr[3]=arr[2]=30, arr[2]=arr[1]=20, arr[1]=arr[0]=10
  2. Step 2: Insert 5 at index 0

    arr[0] = 5
  3. Final Answer:

    5 10 20 30 40 -> Option B
  4. Quick Check:

    Shift right + insert 5 at start = 5 10 20 30 40 [OK]
Hint: Trace shifts from end, then insert new value [OK]
Common Mistakes:
  • Not shifting elements correctly
  • Overwriting elements before shifting
  • Incorrect final array print
4. The following code attempts to insert 99 at the beginning of an array arr but produces incorrect output. What is the error?
int[] arr = {1, 2, 3, 4, 5};
for (int i = 0; i < arr.Length - 1; i++) {
    arr[i + 1] = arr[i];
}
arr[0] = 99;
medium
A. The loop shifts elements left instead of right, overwriting data.
B. The assignment to arr[0] should be inside the loop.
C. The loop index range is incorrect; it should start from the end.
D. The array size is too small to insert a new element.

Solution

  1. Step 1: Analyze loop direction and range

    The loop starts from 0 and moves forward, causing overwriting of elements.
  2. Step 2: Correct loop should start from end

    To shift right safely, loop must start from last index and move backward.
  3. Final Answer:

    The loop index range is incorrect; it should start from the end. -> Option C
  4. Quick Check:

    Shift right requires backward loop [OK]
Hint: Shift right needs backward loop from end [OK]
Common Mistakes:
  • Looping forward overwrites elements
  • Assigning new value inside loop
  • Ignoring fixed array size
5. You have an array arr = new int[6] {0, 1, 2, 3, 4, 5} and want to insert a new element 99 at the beginning without losing any data. Which approach correctly handles this?
hard
A. Create a new array of size 7, set arr2[0] = 99, then copy all elements of arr to arr2 starting at index 1.
B. Shift all elements right by one and assign 99 to arr[0], but last element is lost.
C. Replace arr[0] with 99 directly without shifting elements.
D. Use a List<int> instead of array to insert at beginning easily.

Solution

  1. Step 1: Understand fixed array size limitation

    Original array size is 6, so inserting without losing data requires a bigger array.
  2. Step 2: Create new larger array and copy elements

    Create new array size 7, assign 99 at index 0, then copy original elements starting at index 1.
  3. Final Answer:

    Create a new array of size 7, set arr2[0] = 99, then copy all elements of arr to arr2 starting at index 1. -> Option A
  4. Quick Check:

    New bigger array + copy elements = safe insertion [OK]
Hint: Use bigger array and copy to insert without loss [OK]
Common Mistakes:
  • Trying to insert in fixed-size array losing last element
  • Replacing without shifting
  • Ignoring better data structures like List
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