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DSA C++programming~10 mins

Shortest Path in Unweighted Graph Using BFS in DSA C++ - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to declare the queue used in BFS.

DSA C++
std::queue<[1]> q;
Drag options to blanks, or click blank then click option'
Aint
Bstring
Cfloat
Dbool
Attempts:
3 left
💡 Hint
Common Mistakes
Using string or float instead of int for node representation.
Using stack instead of queue.
2fill in blank
medium

Complete the code to initialize the distance vector with -1.

DSA C++
std::vector<int> dist(n, [1]);
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AINT_MAX
B-1
C1
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Initializing distance with 0 which means visited.
Using INT_MAX which is not needed here.
3fill in blank
hard

Fix the error in the BFS loop condition to process nodes while queue is not empty.

DSA C++
while (!q.[1]()) {
Drag options to blanks, or click blank then click option'
Apop
Bfront
Cempty
Dpush
Attempts:
3 left
💡 Hint
Common Mistakes
Using q.front() as condition which returns element, not boolean.
Using q.pop() which removes element, not checks emptiness.
4fill in blank
hard

Fill both blanks to update distance and enqueue neighbor nodes correctly.

DSA C++
if (dist[neighbor] == [1]) {
    dist[neighbor] = dist[current] [2] 1;
    q.push(neighbor);
}
Drag options to blanks, or click blank then click option'
A-1
B+
C-
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Using 0 instead of -1 to check unvisited.
Subtracting 1 instead of adding 1 to distance.
5fill in blank
hard

Fill all three blanks to reconstruct the shortest path from target to source.

DSA C++
std::vector<int> path;
int node = target;
while (node != [1]) {
    path.push_back(node);
    node = [2][node];
}
path.push_back([3]);
std::reverse(path.begin(), path.end());
Drag options to blanks, or click blank then click option'
Asource
Bparent
Ddist
Attempts:
3 left
💡 Hint
Common Mistakes
Using dist array instead of parent to trace path.
Not adding source node to path before reversing.

Practice

(1/5)
1. What is the main purpose of using BFS (Breadth-First Search) in an unweighted graph?
easy
A. To sort the nodes in topological order
B. To find the maximum depth of the graph
C. To find the shortest path from a source node to all other nodes
D. To detect cycles in the graph

Solution

  1. Step 1: Understand BFS traversal

    BFS explores nodes level by level starting from the source node.
  2. Step 2: BFS finds shortest paths in unweighted graphs

    Because BFS visits nodes in order of increasing distance, it finds shortest paths from source to all nodes.
  3. Final Answer:

    To find the shortest path from a source node to all other nodes -> Option C
  4. Quick Check:

    BFS shortest path = D [OK]
Hint: BFS explores neighbors level-wise to find shortest paths [OK]
Common Mistakes:
  • Confusing BFS with DFS for shortest path
  • Thinking BFS finds maximum depth
  • Assuming BFS sorts nodes topologically
2. Which of the following is the correct way to initialize a queue for BFS in C++?
easy
A. queue<int> q; q.push(0);
B. stack<int> q; q.push(0);
C. queue<int> q; q.insert(0);
D. queue<int> q; q.add(0);

Solution

  1. Step 1: Identify correct queue declaration

    In C++, BFS uses std::queue with push() to add elements.
  2. Step 2: Check method names

    push() is correct for queue; insert() and add() are invalid; stack is wrong data structure.
  3. Final Answer:

    queue<int> q; q.push(0); -> Option A
  4. Quick Check:

    queue push() method = C [OK]
Hint: Use std::queue and push() to add elements in BFS [OK]
Common Mistakes:
  • Using stack instead of queue
  • Using insert() or add() instead of push()
  • Confusing queue methods with vector methods
3. Consider the following C++ code snippet for BFS shortest path in an unweighted graph:
int n = 4;
vector adj = {{1,2}, {0,2,3}, {0,1,3}, {1,2}};
vector<int> dist(n, -1);
queue<int> q;
dist[0] = 0;
q.push(0);
while(!q.empty()) {
  int u = q.front(); q.pop();
  for(int v : adj[u]) {
    if(dist[v] == -1) {
      dist[v] = dist[u] + 1;
      q.push(v);
    }
  }
}
for(int i=0; iWhat is the output?
medium
A. 0 1 1 2
B. 0 1 2 3
C. 0 2 1 1
D. 0 1 1 1

Solution

  1. Step 1: Initialize distances and start BFS

    dist[0]=0, others -1; start from node 0.
  2. Step 2: BFS visits neighbors and updates distances

    From 0: neighbors 1,2 get dist=1; from 1 and 2: neighbor 3 gets dist=2.
  3. Final Answer:

    0 1 1 2 -> Option A
  4. Quick Check:

    BFS distance array = 0 1 1 2 [OK]
Hint: BFS distance increments by 1 per level from source [OK]
Common Mistakes:
  • Mixing up node indices and distances
  • Not initializing distances to -1
  • Forgetting to check if node was visited
4. The following BFS code snippet is intended to find shortest paths in an unweighted graph. Identify the bug:
int n = 3;
vector adj = {{1}, {0,2}, {1}};
vector<int> dist(n, 0);
queue<int> q;
dist[0] = 0;
q.push(0);
while(!q.empty()) {
  int u = q.front(); q.pop();
  for(int v : adj[u]) {
    if(dist[v] == 0) {
      dist[v] = dist[u] + 1;
      q.push(v);
    }
  }
}
for(int i=0; i
medium
A. dist[u] is not updated inside the loop
B. Queue is not used properly
C. Adjacency list is incorrect
D. dist vector initialized with 0 instead of -1

Solution

  1. Step 1: Check distance initialization

    dist initialized with 0 means unvisited nodes are indistinguishable from source.
  2. Step 2: Identify impact on BFS logic

    Condition dist[v] == 0 fails to detect unvisited nodes correctly, causing wrong or no updates.
  3. Final Answer:

    dist vector initialized with 0 instead of -1 -> Option D
  4. Quick Check:

    dist init must be -1 to mark unvisited [OK]
Hint: Initialize distances with -1 to mark unvisited nodes [OK]
Common Mistakes:
  • Using 0 as unvisited marker
  • Not checking visited condition properly
  • Misusing queue operations
5. You have an unweighted graph with 5 nodes and edges: 0-1, 0-2, 1-3, 2-3, 3-4. Using BFS from node 0, what is the shortest path distance to node 4? Also, which nodes are on one shortest path from 0 to 4?
hard
A. Distance: 2; Path: 0 -> 1 -> 3 -> 4
B. Distance: 3; Path: 0 -> 2 -> 3 -> 4
C. Distance: 2; Path: 0 -> 3 -> 4
D. Distance: 4; Path: 0 -> 2 -> 3 -> 4

Solution

  1. Step 1: Build graph and run BFS from node 0

    Edges: 0-1,0-2; 1-3; 2-3; 3-4. BFS levels: 0(dist=0), 1 and 2(dist=1), 3(dist=2), 4(dist=3).
  2. Step 2: Identify shortest path to node 4

    Shortest distance to 4 is 3. Paths: 0->1->3->4 or 0->2->3->4. Distance: 3; Path: 0 -> 2 -> 3 -> 4 shows correct distance and one valid path.
  3. Final Answer:

    Distance: 3; Path: 0 -> 2 -> 3 -> 4 -> Option B
  4. Quick Check:

    Shortest path length = 3 via node 2 [OK]
Hint: Trace BFS levels to find shortest path and distance [OK]
Common Mistakes:
  • Assuming direct edge from 0 to 3
  • Confusing distance with number of edges
  • Ignoring multiple shortest paths
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10 questions~5 mineasy hard