Hint: Compare function must use const void pointers [OK]
Common Mistakes:
Using wrong parameter types in compare function
Assuming array size is wrong
Thinking qsort needs dynamic arrays
5. You have a large list of unsorted numbers and want to find if any two numbers sum to a target value efficiently. Which approach best uses sorting to unlock a faster solution?
hard
A. Sort the list, then use two pointers from start and end to find the sum
B. Sort the list and then check every pair with nested loops
C. Use sorting to remove duplicates first, then check sums
D. Sort the list and then perform binary search for each element's complement
Solution
Step 1: Understand the two-pointer technique after sorting
Sorting allows placing pointers at start and end to check sums efficiently without nested loops.
Step 2: Compare with other options
Sort the list and then check every pair with nested loops uses nested loops which is slower. Use sorting to remove duplicates first, then check sums is unrelated to sum search. Sort the list and then perform binary search for each element's complement is slower than two-pointer approach.
Final Answer:
Sort the list, then use two pointers from start and end to find the sum -> Option A
Quick Check:
Two-pointer after sorting = fastest sum search [OK]
Hint: Use two pointers on sorted list for sum search [OK]
Common Mistakes:
Using nested loops after sorting
Thinking removing duplicates helps sum search
Using binary search for each complement inefficiently
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