What does it mean for a sorting algorithm to be stable?
A stable sorting algorithm keeps the original order of equal elements the same after sorting.
Click to reveal answer
beginner
Name a common stable sorting algorithm.
Merge Sort is a common stable sorting algorithm.
Click to reveal answer
intermediate
Why might you choose an unstable sort like Quick Sort over a stable one?
Quick Sort is often faster and uses less memory, so it is chosen when stability is not important.
Click to reveal answer
beginner
Which sorting algorithm is best for sorting small arrays and why?
Insertion Sort is best for small arrays because it is simple and efficient for nearly sorted or small data.
Click to reveal answer
intermediate
What is a key advantage of Merge Sort compared to Quick Sort?
Merge Sort guarantees stable sorting and consistent O(n log n) time, while Quick Sort can degrade to O(n²).
Click to reveal answer
Which sorting algorithm is stable by default?
AQuick Sort
BMerge Sort
CHeap Sort
DSelection Sort
✗ Incorrect
Merge Sort keeps equal elements in their original order, making it stable.
When is it best to use Insertion Sort?
AFor small or nearly sorted arrays
BFor large random arrays
CWhen stability is not needed
DFor sorting linked lists only
✗ Incorrect
Insertion Sort is efficient for small or nearly sorted arrays.
Which sorting algorithm can degrade to O(n²) time in the worst case?
ABubble Sort
BMerge Sort
CHeap Sort
DQuick Sort
✗ Incorrect
Quick Sort can degrade to O(n²) if the pivot choices are poor.
Why might you avoid using Heap Sort if you need stable sorting?
AHeap Sort only works on linked lists
BHeap Sort is slow
CHeap Sort is unstable
DHeap Sort uses too much memory
✗ Incorrect
Heap Sort does not preserve the order of equal elements, so it is unstable.
Which sorting algorithm guarantees O(n log n) time in all cases?
AMerge Sort
BInsertion Sort
CQuick Sort
DSelection Sort
✗ Incorrect
Merge Sort always runs in O(n log n) time regardless of input.
Explain what sorting stability means and give an example of when it matters.
Think about how equal items keep their order after sorting.
You got /3 concepts.
Describe when you would choose Quick Sort over Merge Sort and why.
Consider speed and memory versus keeping order of equal elements.
You got /3 concepts.
Practice
(1/5)
1. What does it mean when a sorting algorithm is called stable?
easy
A. It sorts elements in descending order
B. It uses less memory than unstable sorts
C. It keeps the original order of equal elements after sorting
D. It always sorts in linear time
Solution
Step 1: Understand stability in sorting
A stable sort keeps the relative order of elements that compare equal unchanged.
Step 2: Compare options with definition
Only It keeps the original order of equal elements after sorting matches this definition exactly.
Final Answer:
It keeps the original order of equal elements after sorting -> Option C
Quick Check:
Stable sort = keeps order of equal elements [OK]
Hint: Stable means equal items keep their original order [OK]
Common Mistakes:
Confusing stability with sorting order
Thinking stability means faster sorting
Assuming stability relates to memory use
2. Which of the following is the correct syntax to call the qsort function in C for sorting an array arr of integers with n elements?
easy
A. qsort(arr, n, compare, sizeof(int));
B. qsort(arr, n, sizeof(int), compare);
C. qsort(arr, sizeof(int), n, compare);
D. qsort(arr, compare, n, sizeof(int));
Solution
Step 1: Recall qsort parameter order
The qsort function parameters are: pointer to array, number of elements, size of each element, and comparison function pointer.
Step 2: Match parameters with options
qsort(arr, n, sizeof(int), compare); matches this order exactly: arr, n, sizeof(int), compare.
Final Answer:
qsort(arr, n, sizeof(int), compare); -> Option B
Quick Check:
qsort syntax = arr, n, size, compare [OK]
Hint: Remember qsort: array, count, size, compare function [OK]
Common Mistakes:
Mixing up size and count parameters
Placing compare function in wrong position
Using wrong order of arguments
3. Consider the following C code snippet using bubble sort on an array of structs with an integer key and a character value. Which output shows the array after sorting by key, preserving stability?
typedef struct {
int key;
char value;
} Item;
void bubbleSort(Item arr[], int n) {
for (int i = 0; i < n-1; i++) {
for (int j = 0; j < n-i-1; j++) {
if (arr[j].key > arr[j+1].key) {
Item temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;
}
}
}
}
int main() {
Item arr[5] = {{2, 'a'}, {3, 'b'}, {2, 'c'}, {1, 'd'}, {3, 'e'}};
bubbleSort(arr, 5);
for (int i = 0; i < 5; i++) {
printf("%d%c ", arr[i].key, arr[i].value);
}
return 0;
}
medium
A. 1d 2a 2c 3b 3e
B. 1d 2c 2a 3e 3b
C. 1d 2c 2a 3b 3e
D. 1d 2a 2c 3e 3b
Solution
Step 1: Understand bubble sort stability
Bubble sort is stable, so equal keys keep their original order.
Step 2: Trace sorting of array
Original order for key=2 is 'a' then 'c', for key=3 is 'b' then 'e'. After sorting by key, order is 1d, 2a, 2c, 3b, 3e.
Final Answer:
1d 2a 2c 3b 3e -> Option A
Quick Check:
Bubble sort stable = keeps order of equal keys [OK]
Hint: Stable sort keeps original order of equal keys [OK]
Common Mistakes:
Assuming bubble sort is unstable
Swapping equal keys and changing order
Mixing up output order of equal keys
4. The following code attempts to sort an array using selection sort but does not preserve stability. What change fixes this to make it stable?
void selectionSort(int arr[], int n) {
for (int i = 0; i < n-1; i++) {
int min_idx = i;
for (int j = i+1; j < n; j++) {
if (arr[j] < arr[min_idx]) {
min_idx = j;
}
}
int temp = arr[min_idx];
arr[min_idx] = arr[i];
arr[i] = temp;
}
}
medium
A. Sort array in descending order
B. Use bubble sort instead of selection sort
C. Change comparison to <= instead of <
D. Replace swap with shifting elements to insert min element
Solution
Step 1: Identify why selection sort is unstable
Selection sort swaps min element directly, which can reorder equal elements and break stability.
Step 2: Fix by shifting elements
Instead of swapping, shift elements right and insert min element at correct position to keep order.
Final Answer:
Replace swap with shifting elements to insert min element -> Option D
Quick Check:
Stable selection sort = shift, not swap [OK]
Hint: Shift elements instead of swap for stable selection sort [OK]
Common Mistakes:
Just changing comparison operator
Switching to bubble sort without reason
Sorting in wrong order
5. You have a large dataset with many duplicate keys and need to sort it by key while preserving the order of duplicates. The dataset is too large to fit in memory, so you must use external sorting. Which sorting algorithm is best suited for this task?
hard
A. External merge sort because it is stable and handles large data
B. Quick sort because it is fastest in average case
C. Heap sort because it uses constant memory
D. Selection sort because it is simple to implement
Solution
Step 1: Understand requirements for large data and stability
Large data needs external sorting; stability is required to keep duplicate order.
Step 2: Match algorithm features
External merge sort is stable and designed for large data using disk; quicksort and heapsort are unstable and in-memory; selection sort is inefficient.
Final Answer:
External merge sort because it is stable and handles large data -> Option A
Quick Check:
Large stable sort = external merge sort [OK]
Hint: Use external merge sort for large stable sorting [OK]
Common Mistakes:
Choosing quicksort ignoring stability
Picking heapsort without external support
Using simple sorts for large data
Recommended
Ready to prove it?
Pass the test and this pattern moves unknownstrongwhile earning +1 Grip toward your certificate.