Bird
Raised Fist0
DSA Cprogramming~10 mins

Longest Word in Dictionary Using Trie in DSA C - Interactive Practice

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a new Trie node.

DSA C
struct TrieNode* getNode() {
    struct TrieNode* pNode = (struct TrieNode*)malloc(sizeof(struct TrieNode));
    pNode->isEndOfWord = [1];
    for (int i = 0; i < 26; i++)
        pNode->children[i] = NULL;
    return pNode;
}
Drag options to blanks, or click blank then click option'
A1
B0
C-1
DNULL
Attempts:
3 left
💡 Hint
Common Mistakes
Setting isEndOfWord to 1 by mistake.
Using NULL instead of 0 for a boolean flag.
2fill in blank
medium

Complete the code to insert a word into the Trie.

DSA C
void insert(struct TrieNode* root, const char* key) {
    struct TrieNode* pCrawl = root;
    for (int level = 0; key[level] != '\0'; level++) {
        int index = key[level] - 'a';
        if (!pCrawl->children[[1]])
            pCrawl->children[index] = getNode();
        pCrawl = pCrawl->children[index];
    }
    pCrawl->isEndOfWord = 1;
}
Drag options to blanks, or click blank then click option'
ApCrawl
Blevel
Ckey[level]
Dindex
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'level' instead of 'index' to access children.
Using the character directly as an index.
3fill in blank
hard

Fix the error in the function that checks if a word exists in the Trie.

DSA C
int search(struct TrieNode* root, const char* key) {
    struct TrieNode* pCrawl = root;
    for (int level = 0; key[level] != '\0'; level++) {
        int index = key[level] - 'a';
        if (!pCrawl->children[[1]])
            return 0;
        pCrawl = pCrawl->children[index];
    }
    return (pCrawl != NULL && pCrawl->isEndOfWord);
}
Drag options to blanks, or click blank then click option'
Aindex
Bkey[level]
Clevel
DpCrawl
Attempts:
3 left
💡 Hint
Common Mistakes
Checking children at 'level' instead of 'index'.
Using the character directly as an index.
4fill in blank
hard

Fill both blanks to implement the recursive function that finds the longest word in the Trie where all prefixes are valid words.

DSA C
void longestWordUtil(struct TrieNode* root, char* currentWord, int level, char* longestWord) {
    if (root->isEndOfWord) {
        currentWord[level] = '\0';
        if (strlen(currentWord) > strlen(longestWord)) {
            strcpy(longestWord, [1]);
        }
    }
    for (int i = 0; i < 26; i++) {
        if (root->children[i] && root->children[i]->isEndOfWord) {
            currentWord[level] = 'a' + [2];
            longestWordUtil(root->children[i], currentWord, level + 1, longestWord);
        }
    }
}
Drag options to blanks, or click blank then click option'
AcurrentWord
BlongestWord
Ci
Dlevel
Attempts:
3 left
💡 Hint
Common Mistakes
Copying longestWord to currentWord instead of the other way.
Using 'level' instead of 'i' to calculate the character.
5fill in blank
hard

Fill all three blanks to complete the function that finds the longest word in the dictionary using the Trie.

DSA C
char* longestWord(char** words, int wordsSize) {
    struct TrieNode* root = getNode();
    for (int i = 0; i < wordsSize; i++) {
        insert(root, [1]);
    }
    char currentWord[1000];
    char* longestWord = (char*)malloc(1000 * sizeof(char));
    longestWord[0] = '\0';
    longestWordUtil(root, currentWord, 0, [2]);
    return [3];
}
Drag options to blanks, or click blank then click option'
Awords[i]
BlongestWord
DcurrentWord
Attempts:
3 left
💡 Hint
Common Mistakes
Passing currentWord instead of longestWord to longestWordUtil.
Returning currentWord instead of longestWord.
Inserting wrong variable instead of words[i].

Practice

(1/5)
1. What is the main purpose of using a Trie data structure when finding the longest word in a dictionary?
easy
A. To sort words alphabetically
B. To count the total number of words
C. To efficiently store and search words by their prefixes
D. To reverse the words in the dictionary

Solution

  1. Step 1: Understand Trie usage

    A Trie stores words by breaking them into characters and linking nodes for prefixes.
  2. Step 2: Relate to longest word search

    This structure allows quick prefix checks, which helps find the longest word built from other words.
  3. Final Answer:

    To efficiently store and search words by their prefixes -> Option C
  4. Quick Check:

    Trie = prefix search [OK]
Hint: Trie is best for prefix-based word searches [OK]
Common Mistakes:
  • Thinking Trie sorts words alphabetically
  • Confusing Trie with simple arrays or lists
  • Assuming Trie counts words only
2. Which of the following is the correct way to declare a Trie node structure in C for lowercase English letters?
easy
A. typedef struct TrieNode { struct TrieNode* children[26]; int isEndOfWord; } TrieNode;
B. typedef struct TrieNode { struct TrieNode* children[52]; int isEndOfWord; } TrieNode;
C. typedef struct TrieNode { struct TrieNode* children[10]; int isEndOfWord; } TrieNode;
D. typedef struct TrieNode { struct TrieNode* children; int isEndOfWord; } TrieNode;

Solution

  1. Step 1: Identify children array size

    Lowercase English letters are 26, so children array size must be 26.
  2. Step 2: Check structure fields

    Each node has an array of pointers and a flag for word end, matching typedef struct TrieNode { struct TrieNode* children[26]; int isEndOfWord; } TrieNode;.
  3. Final Answer:

    typedef struct TrieNode { struct TrieNode* children[26]; int isEndOfWord; } TrieNode; -> Option A
  4. Quick Check:

    26 children for a-z [OK]
Hint: Use 26 children for lowercase letters [OK]
Common Mistakes:
  • Using 52 for uppercase + lowercase without need
  • Using 10 children for digits only
  • Not using array for children pointers
3. Given the following code snippet inserting words into a Trie and searching for the longest word built one character at a time, what will be the output?
char* words[] = {"a", "ap", "app", "appl", "apple", "apply"};
// Assume insert and search functions are correct
// Function finds longest word where all prefixes exist
printf("%s", longestWord(words, 6));
medium
A. apple
B. apply
C. appl
D. app

Solution

  1. Step 1: Check all prefixes for each word

    Words like "apple" and "apply" have all prefixes present: a, ap, app, appl.
  2. Step 2: Compare lengths of valid words

    "apple" and "apply" both have length 5, but "apple" comes first lexicographically.
  3. Final Answer:

    apple -> Option A
  4. Quick Check:

    Longest valid word = apple [OK]
Hint: Check all prefixes exist, pick longest lex order first [OK]
Common Mistakes:
  • Choosing 'apply' ignoring lex order
  • Picking shorter words like 'app'
  • Not verifying all prefixes exist
4. The following code tries to find the longest word in a dictionary using a Trie but always returns an empty string. What is the bug?
void insert(TrieNode* root, char* word) {
    TrieNode* node = root;
    for (int i = 0; word[i]; i++) {
        int index = word[i] - 'a';
        if (!node->children[index])
            node->children[index] = createNode();
        node = node->children[index];
    }
    node->isEndOfWord = 1;
}

char* longestWord(char** words, int n) {
    TrieNode* root = createNode();
    for (int i = 0; i < n; i++)
        insert(root, words[i]);
    // Missing code to find longest word
    return "";
}
medium
A. The children array size is incorrect
B. The longestWord function does not search the Trie for the longest word
C. The insert function does not mark end of word correctly
D. The root node is not initialized

Solution

  1. Step 1: Analyze insert function

    Insert correctly adds words and marks end of word, so no issue here.
  2. Step 2: Check longestWord function

    It inserts words but returns empty string without searching Trie for longest word.
  3. Final Answer:

    The longestWord function does not search the Trie for the longest word -> Option B
  4. Quick Check:

    Missing search logic causes empty output [OK]
Hint: Check if search logic exists after insertion [OK]
Common Mistakes:
  • Assuming insert alone finds longest word
  • Ignoring missing traversal in longestWord
  • Thinking root node is uninitialized
5. You want to find the longest word in a dictionary such that every prefix of the word is also a word in the dictionary. Which approach using a Trie is best to solve this efficiently?
hard
A. Use BFS on Trie without checking end of word flags
B. Sort words by length, then check each word's prefixes in a hash set
C. Insert words into Trie and count total nodes to find longest word
D. Insert all words into Trie, then do DFS checking only nodes marking end of words to build longest word

Solution

  1. Step 1: Insert all words into Trie

    Build Trie with all dictionary words, marking end of word nodes.
  2. Step 2: Use DFS to find longest word

    Traverse Trie depth-first, only continuing on nodes that mark end of words to ensure all prefixes exist.
  3. Step 3: Track longest word during traversal

    Keep updating longest word found by length and lex order during DFS.
  4. Final Answer:

    Insert all words into Trie, then do DFS checking only nodes marking end of words to build longest word -> Option D
  5. Quick Check:

    Trie + DFS + endOfWord check = longest word [OK]
Hint: Use DFS on Trie nodes with endOfWord true only [OK]
Common Mistakes:
  • Ignoring prefix checks during traversal
  • Using BFS without endOfWord validation
  • Relying on sorting without Trie
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard