What if a simple program could instantly tell you the deepest level of any family or company tree?
Why Height of Binary Tree in DSA C?
Imagine you have a family tree drawn on paper. You want to know how many generations it has from the oldest ancestor to the youngest child. Counting each level by hand is tiring and easy to mess up.
Manually counting the height means you must check every branch and remember the longest path. This is slow and you can forget or miscount branches, especially if the tree is big or uneven.
Using the height of a binary tree concept, a simple program can check each branch automatically and find the longest path from the root to any leaf. It does this quickly and without mistakes.
int countHeight(Node* root) {
// Manually check each branch and count
// Very long and error-prone
}int height(Node* root) {
if (root == NULL) return 0;
int leftHeight = height(root->left);
int rightHeight = height(root->right);
return 1 + (leftHeight > rightHeight ? leftHeight : rightHeight);
}This lets you quickly find how deep a tree is, which helps in balancing trees, searching efficiently, and understanding data structure shape.
In a company's organizational chart, finding the height tells you how many management levels exist from the CEO down to the lowest employee.
Manual counting is slow and error-prone.
Height calculation uses recursion to find the longest path automatically.
Knowing height helps optimize and understand tree structures.
Practice
Solution
Step 1: Understand height definition
The height of a binary tree is the number of edges on the longest path from the root to a leaf.Step 2: Apply to single node tree
With only one node (root), the longest path has length 0 edges.Final Answer:
0 -> Option AQuick Check:
Height of single node tree = 0 [OK]
- Thinking height is 1 for single node
- Confusing height with number of nodes
- Assuming height is undefined for single node
Solution
Step 1: Check parameter type for tree node
In C, a tree node is usually passed as a pointer to struct Node.Step 2: Check return type and parameter correctness
The function returns an int (height) and takes a pointer to struct Node.Final Answer:
int height(struct Node* root); -> Option CQuick Check:
Correct signature uses pointer to struct Node [OK]
- Passing struct Node by value instead of pointer
- Using void return type instead of int
- Missing struct keyword in parameter
struct Node {
int data;
struct Node* left;
struct Node* right;
};
int height(struct Node* root) {
if (root == NULL) return 0;
int leftHeight = height(root->left);
int rightHeight = height(root->right);
return (leftHeight > rightHeight ? leftHeight : rightHeight) + 1;
}
// Tree:
// 10
// / \
// 5 15
// /
// 12
int main() {
struct Node n12 = {12, NULL, NULL};
struct Node n15 = {15, &n12, NULL};
struct Node n5 = {5, NULL, NULL};
struct Node n10 = {10, &n5, &n15};
printf("%d", height(&n10));
return 0;
}Solution
Step 1: Trace left subtree height
Left subtree of root (10) has node 5 only, height = 1.Step 2: Trace right subtree height
Right subtree has nodes 15 and 12. Height is 2 (15 -> 12).Step 3: Calculate total height
Height = max(1, 2) + 1 (for root) = 3.Final Answer:
3 -> Option DQuick Check:
Height = 3 [OK]
- Counting edges instead of nodes
- Ignoring one subtree height
- Off-by-one error in return statement
int height(struct Node* root) {
if (root == NULL) return -1;
int leftHeight = height(root->left);
int rightHeight = height(root->right);
return (leftHeight > rightHeight ? leftHeight : rightHeight) + 1;
}Solution
Step 1: Understand base case meaning
Base case returns height for empty tree. Returning -1 means height counts edges, not nodes.Step 2: Fix base case for node count height
To count nodes, base case should return 0 for NULL.Final Answer:
Change base case return from -1 to 0 -> Option BQuick Check:
Base case 0 for NULL node height [OK]
- Returning -1 causes off-by-one height
- Removing +1 leads to wrong height
- Swapping left and right recursive calls unnecessary
Solution
Step 1: Understand full binary tree properties
A full binary tree with all nodes having 0 or 2 children has nodes count = 2^h - 1, where h is height.Step 2: Calculate height from nodes count
Given nodes = 7, solve 2^h - 1 = 7 -> 2^h = 8 -> h = 3.Final Answer:
3 -> Option AQuick Check:
Full binary tree height for 7 nodes = 3 [OK]
- Confusing height with number of edges
- Using incomplete binary tree formula
- Miscounting nodes or height
Ready to prove it?
Pass the test and this pattern moves unknown
