Bird
Raised Fist0
DSA Cprogramming~10 mins

Why Stack Exists and What Problems It Solves in DSA C - Test Your Knowledge

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to push an element onto the stack.

DSA C
void push(int stack[], int *top, int value) {
    stack[++[1]] = value;
}
Drag options to blanks, or click blank then click option'
Avalue
Btop
C*top
Dstack
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'top' instead of '*top' causes incorrect pointer usage.
Assigning value before incrementing top.
2fill in blank
medium

Complete the code to pop an element from the stack.

DSA C
int pop(int stack[], int *top) {
    if (*top == -1) return -1; // stack empty
    return stack[[1]--];
}
Drag options to blanks, or click blank then click option'
A*top
Bstack
Ctop
Dvalue
Attempts:
3 left
💡 Hint
Common Mistakes
Using prefix decrement causes wrong element to be returned.
Using 'top' instead of '*top'.
3fill in blank
hard

Fix the error in the stack overflow check condition.

DSA C
int isFull(int top, int maxSize) {
    return [1] >= maxSize - 1;
}
Drag options to blanks, or click blank then click option'
A*top
Btop
Cstack
DmaxSize
Attempts:
3 left
💡 Hint
Common Mistakes
Using '*top' causes compilation error.
Comparing with maxSize instead of maxSize - 1.
4fill in blank
hard

Fill both blanks to check if the stack is empty and return the top element safely.

DSA C
int safePop(int stack[], int *top) {
    if (*top [1] -1) return -1;
    return stack[[2]--];
}
Drag options to blanks, or click blank then click option'
A<=
B==
C*top
Dtop
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<=' instead of '==' causes wrong empty check.
Using 'top' instead of '*top'.
5fill in blank
hard

Fill all three blanks to implement a function that returns the current top element without popping it.

DSA C
int peek(int stack[], int *top) {
    if (*top [1] -1) return -1;
    return stack[[2]];
    // top remains [3]
}
Drag options to blanks, or click blank then click option'
A==
B>
C*top
Attempts:
3 left
💡 Hint
Common Mistakes
Using '>' instead of '==' causes wrong empty check.
Modifying top in peek causes stack corruption.

Practice

(1/5)
1. Why do we use a stack data structure in programming?
easy
A. To store data in random order
B. To keep track of function calls and return addresses
C. To sort numbers quickly
D. To store large amounts of data permanently

Solution

  1. Step 1: Understand the purpose of a stack

    A stack stores data in a last-in, first-out order, which is perfect for tracking function calls and returns.
  2. Step 2: Identify common uses of stack

    Stacks are mainly used to keep track of function calls, especially in recursion, where the last called function must finish first.
  3. Final Answer:

    To keep track of function calls and return addresses -> Option B
  4. Quick Check:

    Stack = function call tracking [OK]
Hint: Stack = last-in, first-out for function calls [OK]
Common Mistakes:
  • Thinking stack stores data randomly
  • Confusing stack with queue
  • Assuming stack sorts data
2. Which of the following is the correct way to push an element onto a stack in C?
easy
A. stack[++top] = value;
B. stack[top] = value++;
C. stack[top++] = value;
D. stack[top--] = value;

Solution

  1. Step 1: Understand stack push operation

    To push, we first increase the top index, then assign the value at that position.
  2. Step 2: Check each option

    stack[++top] = value; increments top before assignment, which is correct. stack[top++] = value; assigns then increments, which may overwrite. stack[top] = value++; increments value, not top. stack[top--] = value; decrements top, which is wrong for push.
  3. Final Answer:

    stack[++top] = value; -> Option A
  4. Quick Check:

    Push = increment top then assign [OK]
Hint: Push means increment top first, then assign [OK]
Common Mistakes:
  • Incrementing after assignment causes overwrite
  • Decrementing top on push
  • Incrementing value instead of top
3. What will be the output of the following C code snippet?
int stack[3];
int top = -1;
stack[++top] = 10;
stack[++top] = 20;
stack[++top] = 30;
printf("%d", stack[top]);
medium
A. 10
B. 20
C. 30
D. Runtime error

Solution

  1. Step 1: Trace stack push operations

    Initially, top = -1. After first push, top=0, stack[0]=10. Second push: top=1, stack[1]=20. Third push: top=2, stack[2]=30.
  2. Step 2: Check printed value

    printf prints stack[top], which is stack[2] = 30.
  3. Final Answer:

    30 -> Option C
  4. Quick Check:

    Last pushed value = 30 [OK]
Hint: Last pushed value is at stack[top] [OK]
Common Mistakes:
  • Printing stack[0] instead of stack[top]
  • Confusing top index after pushes
  • Assuming runtime error without overflow
4. Identify the error in this stack pop function in C:
int pop(int stack[], int *top) {
    if (*top == -1) {
        printf("Stack Underflow\n");
        return -1;
    }
    return stack[*top--];
}
medium
A. Incorrect decrement of top pointer
B. Missing check for stack overflow
C. Returning wrong stack element
D. No error, function is correct

Solution

  1. Step 1: Understand pointer decrement in return statement

    The expression stack[*top--] uses post-decrement on *top, but *top-- decrements the pointer, not the value it points to.
  2. Step 2: Correct way to decrement top value

    It should be stack[(*top)--] to decrement the value pointed by top after accessing stack.
  3. Final Answer:

    Incorrect decrement of top pointer -> Option A
  4. Quick Check:

    Use (*top)-- to decrement value, not pointer [OK]
Hint: Use (*top)-- to decrement value, not pointer [OK]
Common Mistakes:
  • Using *top-- instead of (*top)--
  • Ignoring pointer vs value decrement
  • Not checking stack underflow
5. You want to reverse a string using a stack in C. Which approach correctly uses the stack to solve this problem?
hard
A. Use a queue instead of a stack to reverse the string
B. Push characters only if they are vowels, then pop to reverse
C. Pop characters first, then push them back to reverse
D. Push each character of the string onto the stack, then pop all characters to form the reversed string

Solution

  1. Step 1: Understand stack reversal logic

    Pushing all characters onto the stack stores them in order. Popping them reverses the order due to last-in, first-out behavior.
  2. Step 2: Evaluate options

    Push each character of the string onto the stack, then pop all characters to form the reversed string correctly pushes all characters then pops to reverse. Push characters only if they are vowels, then pop to reverse only pushes vowels, losing other characters. Pop characters first, then push them back to reverse pops before pushing, which is invalid. Use a queue instead of a stack to reverse the string suggests queue, which reverses order differently.
  3. Final Answer:

    Push each character of the string onto the stack, then pop all characters to form the reversed string -> Option D
  4. Quick Check:

    Stack reversal = push all, then pop all [OK]
Hint: Push all chars, then pop all to reverse [OK]
Common Mistakes:
  • Pushing only some characters
  • Popping before pushing
  • Using queue instead of stack for reversal
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard