Challenge - 5 Problems
Bitwise Mastery
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Test your skills under time pressure!
❓ Predict Output
intermediate2:00remaining
Output of Bitwise Shift vs Arithmetic Multiplication
What is the output of the following C code snippet?
DSA C
int x = 5; int y = x << 1; int z = x * 2; printf("%d %d\n", y, z);
Attempts:
2 left
💡 Hint
Left shift by 1 bit is equivalent to multiplying by 2 for positive integers.
✗ Incorrect
Left shifting an integer by 1 bit multiplies it by 2. So both y and z become 10.
🧠 Conceptual
intermediate1:30remaining
Why Use Bit Manipulation Instead of Arithmetic?
Which of the following is a key reason to use bit manipulation over arithmetic operations in programming?
Attempts:
2 left
💡 Hint
Think about performance and hardware level operations.
✗ Incorrect
Bit manipulation often runs faster and uses less memory because it works directly on bits, which is efficient for low-level tasks.
❓ Predict Output
advanced2:00remaining
Output of Bitwise AND vs Modulo
What is the output of this C code snippet?
DSA C
int x = 29; int y = x & 7; int z = x % 8; printf("%d %d\n", y, z);
Attempts:
2 left
💡 Hint
Bitwise AND with 7 extracts the last 3 bits, similar to modulo 8.
✗ Incorrect
Bitwise AND with 7 (binary 111) gives the remainder when dividing by 8, so both y and z are 5.
🔧 Debug
advanced2:00remaining
Identify the Bug in Bitwise Shift Usage
What error will this C code produce when compiled and run?
DSA C
int x = -4; int y = x >> 1; printf("%d\n", y);
Attempts:
2 left
💡 Hint
Right shift on negative signed integers is implementation-defined but usually arithmetic shift.
✗ Incorrect
Right shifting a negative signed integer usually performs arithmetic shift, preserving the sign bit, so -4 >> 1 is -2.
🚀 Application
expert2:30remaining
When Bit Manipulation Beats Arithmetic in Performance
In which scenario does bit manipulation typically outperform arithmetic operations?
Attempts:
2 left
💡 Hint
Think about simple multiplications or divisions by 2, 4, 8, etc.
✗ Incorrect
Bit shifts are faster than multiplication or division by powers of two because they directly manipulate bits without complex arithmetic.
