What if you could manage your tasks like a neat stack of plates, adding and removing without any confusion or mistakes?
Why Stack Implementation Using Array in DSA C?
Imagine you have a stack of plates in your kitchen. You add plates on top and take plates from the top only. Now, if you try to manage this stack by writing down every plate's position manually on paper, it becomes confusing and slow.
Writing down each plate's position manually is slow and prone to mistakes. You might forget the order or lose track of the top plate. This makes it hard to add or remove plates quickly and correctly.
Using an array to implement a stack lets you keep track of plates easily. You always add or remove plates from the top, and the array index helps you know exactly where the top is. This makes adding and removing fast and error-free.
int plates[100]; int count = 0; // To add a plate plates[count] = new_plate; count++; // To remove a plate count--; int top_plate = plates[count];
typedef struct {
int items[100];
int top;
} Stack;
void push(Stack* stack, int item) {
stack->items[++stack->top] = item;
}
int pop(Stack* stack) {
return stack->items[stack->top--];
}This lets you manage data in a last-in, first-out way quickly and safely, perfect for undo actions, expression evaluation, and more.
Think of a web browser's back button. It remembers pages you visited last and lets you go back step-by-step. This is a stack in action, managing your browsing history efficiently.
Manual tracking of stack order is slow and error-prone.
Array-based stack uses an index to track the top element easily.
Stack operations become fast, simple, and reliable.
Practice
Solution
Step 1: Understand stack storage
A stack stores elements in a linear order where the last added element is accessed first.Step 2: Role of array in stack
An array provides a fixed-size linear structure to hold stack elements in order.Final Answer:
To store elements in a fixed-size linear structure -> Option AQuick Check:
Array = fixed-size linear storage [OK]
- Thinking array allows automatic resizing
- Confusing stack with random access structures
- Assuming array sorts elements automatically
Solution
Step 1: Recall C array declaration syntax
In C, arrays are declared as: type name[size];Step 2: Match syntax with options
int stack[5]; matches correct syntax: int stack[5];Final Answer:
int stack[5]; -> Option BQuick Check:
C array declaration = int stack[5]; [OK]
- Placing type after variable name
- Using incorrect keywords like 'array'
- Misplacing brackets in declaration
int stack[3];
int top = -1;
// Push 10
stack[++top] = 10;
// Push 20
stack[++top] = 20;
// Pop
int x = stack[top--];
printf("%d", stack[top]);Solution
Step 1: Trace push operations
Initially top = -1.
Push 10: top becomes 0, stack[0] = 10.
Push 20: top becomes 1, stack[1] = 20.Step 2: Trace pop and print
Pop: x = stack[1] = 20, then top becomes 0.
Print stack[top] = stack[0] = 10.Final Answer:
10 -> Option CQuick Check:
After pop, top points to 10 [OK]
- Printing popped element instead of current top
- Confusing pre-increment and post-decrement
- Assuming top points beyond last element
void push(int stack[], int *top, int size, int value) {
if (*top == size) {
printf("Stack Overflow\n");
return;
}
stack[++(*top)] = value;
}Solution
Step 1: Understand top indexing in stack
Top starts at -1, max index is size - 1.
When top == size - 1, stack is full.Step 2: Analyze overflow condition
Condition *top == size is wrong; it should be *top == size - 1 to detect full stack.Final Answer:
Change condition to *top == size - 1 -> Option DQuick Check:
Overflow when top reaches size-1 [OK]
- Checking top == size instead of size-1
- Misusing increment operators in array indexing
- Ignoring zero-based indexing
push(5); push(10); pop(); push(15); push(20); pop(); push(25);
Assume top starts at -1 and push/pop update top accordingly. Choose the correct final stack content from bottom to top.
Solution
Step 1: Trace each operation step-by-step
Start: top = -1, stack empty.
push(5): top=0, stack[0]=5
push(10): top=1, stack[1]=10
pop(): removes 10, top=0
push(15): top=1, stack[1]=15
push(20): top=2, stack[2]=20
pop(): removes 20, top=1
push(25): top=2, stack[2]=25Step 2: Final stack content
Stack from bottom (index 0) to top (index 2): 5, 15, 25Final Answer:
5 -> 15 -> 25 -> null -> Option AQuick Check:
Push/pop update top correctly [OK]
- Forgetting to update top after pop
- Assuming pop removes bottom element
- Mixing order of elements after operations
Ready to prove it?
Pass the test and this pattern moves unknown
