Sliding Window on Arrays in DSA C - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the window sum with the first k elements.

DSA C

int window_sum = 0;
for (int i = 0; i < [1]; i++) {
    window_sum += arr[i];
}

Drag options to blanks, or click blank then click option'

Aarr

Bn

C0

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using n instead of k causes summing the whole array.

Using 0 as loop limit results in no iteration.

We sum the first k elements to initialize the sliding window sum.

2fill in blank

medium

Complete the code to slide the window by removing the left element and adding the right element.

DSA C

for (int i = [1]; i < n; i++) {
    window_sum = window_sum - arr[i - k] + arr[i];
    // process window_sum
}

Drag options to blanks, or click blank then click option'

Ak

B0

Cn

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Starting from 0 causes incorrect subtraction of elements.

Starting from 1 misses the first full window.

The loop starts from k to slide the window after the initial sum.

3fill in blank

hard

Fix the error in the loop condition to avoid out-of-bounds access.

DSA C

for (int i = k; i <= [1]; i++) {
    window_sum = window_sum - arr[i - k] + arr[i];
}

Drag options to blanks, or click blank then click option'

Ak

Bn

Cn - 1

Dn + 1

Attempts:

3 left

💡 Hint

Common Mistakes

Using i <= n causes out-of-bounds access.

Using i <= k limits the loop incorrectly.

Loop should run while i is less than n to avoid accessing arr[n], which is out-of-bounds.

4fill in blank

hard

Fill both blanks to create a sliding window that finds the maximum sum of any window of size k.

DSA C

int max_sum = window_sum;
for (int i = [1]; i <= [2]; i++) {
    window_sum = window_sum - arr[i - k] + arr[i];
    if (window_sum > max_sum) {
        max_sum = window_sum;
    }
}

Drag options to blanks, or click blank then click option'

Ak

Bn - 1

Cn - k

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using n - k as loop end causes missing last windows.

Starting from 0 causes invalid subtraction.

Loop starts at k and runs until n-1 to cover all windows of size k.

5fill in blank

hard

Fill all three blanks to create a sliding window that stores sums of all windows of size k in an array.

DSA C

int sums[n - k + 1];
sums[0] = window_sum;
for (int i = [1]; i <= [2]; i++) {
    window_sum = window_sum - arr[i - k] + arr[i];
    sums[[3]] = window_sum;
}

Drag options to blanks, or click blank then click option'

Ak

Bn - 1

Ci - k + 1

Di

Attempts:

3 left

💡 Hint

Common Mistakes

Using i as index causes out-of-bounds in sums array.

Loop ending before n-1 misses last windows.

Loop starts at k and ends at n-1; sums are stored at index i - k + 1.

Practice

1. What is the main purpose of using a sliding window technique on arrays?

easy

A. To efficiently process subarrays of fixed size without recomputing everything

B. To sort the array in ascending order

C. To reverse the array elements

D. To find the maximum element in the entire array

Solution

1. Step 1: Understand sliding window concept

   The sliding window technique moves a fixed-size window over the array to process subarrays efficiently.

2. Step 2: Identify the main use

   It avoids recomputing sums or other values for each subarray by updating results incrementally.

3. Final Answer:

   To efficiently process subarrays of fixed size without recomputing everything -> Option A

4. Quick Check:

   Sliding window = efficient subarray processing [OK]

Hint: Sliding window avoids repeated work on overlapping subarrays [OK]

Common Mistakes:

• Thinking it sorts the array
• Assuming it reverses elements
• Confusing it with finding max of whole array

2. Which of the following is the correct syntax to initialize a sliding window sum for the first k elements in C?

easy

A. int sum = 0; for(int i = 1; i <= k; i++) sum += arr[i];

B. int sum = arr[0] + arr[k];

C. int sum = 0; for(int i = 0; i < k; i++) sum += arr[i];

D. int sum = arr[k]; for(int i = 0; i < k; i++) sum += arr[i];

Solution

1. Step 1: Check loop range for first k elements

   The loop should start at 0 and run while i < k to cover first k elements.

2. Step 2: Verify sum initialization and accumulation

   Sum starts at 0 and adds arr[i] for each i in 0 to k-1.

3. Final Answer:

   int sum = 0; for(int i = 0; i < k; i++) sum += arr[i]; -> Option C

4. Quick Check:

   Loop 0 to k-1 sums first k elements [OK]

Hint: Loop from 0 to k-1 to sum first k elements [OK]

Common Mistakes:

• Starting loop at 1 instead of 0
• Adding arr[k] which is outside first k elements
• Initializing sum incorrectly

3. What is the output of the following C code snippet?

int arr[] = {1, 3, 2, 6, -1, 4, 1, 8, 2};
int k = 5;
int max_sum = 0, window_sum = 0;
for(int i = 0; i < k; i++) window_sum += arr[i];
max_sum = window_sum;
for(int i = k; i < 9; i++) {
    window_sum += arr[i] - arr[i - k];
    if(window_sum > max_sum) max_sum = window_sum;
}
printf("%d", max_sum);

medium

A. 18

B. 16

C. 17

D. 15

Solution

1. Step 1: Calculate initial window sum of first 5 elements

   Sum = 1+3+2+6+(-1) = 11

2. Step 2: Slide window and update sums

   Next windows:
   i=5: sum=11 + 4 - 1 = 14
   i=6: sum=14 + 1 - 3 = 12
   i=7: sum=12 + 8 - 2 = 18
   i=8: sum=18 + 2 - 6 = 14
   Max sum found = 18

3. Final Answer:

   18 -> Option A

4. Quick Check:

   Max sliding window sum = 18 [OK]

Hint: Update sum by adding new and subtracting old element [OK]

Common Mistakes:

• Not subtracting the element leaving the window
• Wrong initial sum calculation
• Off-by-one errors in loop

4. Identify the error in the following sliding window code snippet and choose the correct fix:

int arr[] = {2, 1, 5, 1, 3, 2};
int k = 3;
int window_sum = 0;
for(int i = 0; i <= k; i++) window_sum += arr[i];
for(int i = k; i < 6; i++) {
    window_sum += arr[i] - arr[i - k];
    printf("%d ", window_sum);
}

medium

A. No error, code is correct

B. Change loop condition to i < k in second for loop

C. Initialize window_sum to arr[0]

D. Change loop condition to i < k in first for loop

Solution

1. Step 1: Check first loop range for initial sum

   Loop runs i = 0 to i = k (inclusive), so 4 elements summed instead of 3.

2. Step 2: Fix loop condition to sum exactly k elements

   Change condition to i < k to sum first 3 elements only.

3. Final Answer:

   Change loop condition to i < k in first for loop -> Option D

4. Quick Check:

   Initial sum must cover exactly k elements [OK]

Hint: Use i < k to sum first k elements, not i <= k [OK]

Common Mistakes:

• Using <= instead of < in loop condition
• Changing wrong loop's condition
• Assuming initialization error

5. Given an array of integers and a window size k, how would you find the minimum sum of any contiguous subarray of size k using the sliding window technique?

hard

A. Sort the array and pick first k elements to sum

B. Initialize sum of first k elements, slide window updating sum and track minimum sum found

C. Use nested loops to check all subarrays and find minimum sum

D. Reverse the array and sum last k elements

Solution

1. Step 1: Calculate initial sum of first k elements

   Sum the first k elements to start the sliding window.

2. Step 2: Slide window across array updating sum and track minimum

   For each new element, add it and subtract the element leaving the window, update minimum sum if current sum is smaller.

3. Final Answer:

   Initialize sum of first k elements, slide window updating sum and track minimum sum found -> Option B

4. Quick Check:

   Sliding window tracks sums efficiently to find minimum [OK]

Hint: Track min sum by updating window sum while sliding [OK]

Common Mistakes:

• Sorting array instead of sliding window
• Using nested loops causing inefficiency
• Ignoring elements leaving the window