Longest Palindromic Substring in DSA C - Time & Space Complexity

Time Complexity: Longest Palindromic Substring

O(n²)

Understanding Time Complexity

We want to know how the time needed to find the longest palindromic substring changes as the input string gets longer.

How does the number of steps grow when the string size increases?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

int expandAroundCenter(char *s, int left, int right, int n) {
    int L = left, R = right;
    while (L >= 0 && R < n && s[L] == s[R]) {
        L--;
        R++;
    }
    return R - L - 1;
}

char* longestPalindrome(char * s) {
    int start = 0, end = 0;
    int len = strlen(s);
    for (int i = 0; i < len; i++) {
        int len1 = expandAroundCenter(s, i, i, len);
        int len2 = expandAroundCenter(s, i, i + 1, len);
        int maxLen = (len1 > len2) ? len1 : len2;
        if (maxLen > end - start) {
            start = i - (maxLen - 1) / 2;
            end = i + maxLen / 2;
        }
    }
    s[end + 1] = '\0';
    return s + start;
}
    

This code finds the longest palindromic substring by expanding around each character and its neighbor.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: The while loop inside expandAroundCenter that expands outwards checking characters.
• How many times: For each character in the string (n times), we call this expansion twice, each expanding up to n steps in worst case.

How Execution Grows With Input

As the string length grows, the number of expansions grows roughly with the square of the length.

Input Size (n)	Approx. Operations
10	About 100 expansions
100	About 10,000 expansions
1000	About 1,000,000 expansions

Pattern observation: Doubling the input size roughly quadruples the work done.

Final Time Complexity

Time Complexity: O(n²)

This means the time needed grows roughly with the square of the input size.

Common Mistake

[X] Wrong: "The expansion around center runs in linear time overall because it stops early."

[OK] Correct: While each expansion stops early for many centers, in the worst case (like a string of identical characters), expansions can reach the full length, making total work quadratic.

Interview Connect

Understanding this time complexity helps you explain why this approach is efficient enough for many cases and when to consider faster algorithms.

Self-Check

"What if we used dynamic programming to store palindrome checks instead of expanding around centers? How would the time complexity change?"

Practice

1. What is the main goal when finding the Longest Palindromic Substring in a given string?

easy

A. To find the longest substring with all unique characters

B. To find the longest substring that contains only vowels

C. To find the longest continuous sequence of characters that reads the same backward and forward

D. To find the longest substring that is sorted alphabetically

Solution

1. Step 1: Understand palindrome definition

   A palindrome reads the same backward and forward, like 'madam' or 'racecar'.

2. Step 2: Identify substring requirement

   The substring must be continuous characters in the string, not scattered.

3. Final Answer:

   To find the longest continuous sequence of characters that reads the same backward and forward -> Option C

4. Quick Check:

   Longest palindromic substring = continuous palindrome [OK]

Hint: Look for continuous same backward-forward sequences [OK]

Common Mistakes:

• Confusing substring with subsequence
• Looking for unique characters instead of palindrome
• Ignoring continuity of characters

2. Which of the following C code snippets correctly initializes variables to find the longest palindromic substring length?

easy

A. int maxLength = 0; int start = -1; int len = strlen(s);

B. int maxLength = 1; int start = 0; int len = strlen(s);

C. int maxLength = 1; int start = 0; int len = length(s);

D. int maxLength = 1; int start = 0; int len = s.length;

Solution

1. Step 1: Check correct function for string length in C

   In C, strlen() is used to get string length, not length() or s.length.

2. Step 2: Verify variable initialization

   Longest palindrome length starts at 1 (single char), start index at 0, and length is string length.

3. Final Answer:

   int maxLength = 1; int start = 0; int len = strlen(s); -> Option B

4. Quick Check:

   Use strlen() for string length in C [OK]

Hint: Use strlen() to get string length in C [OK]

Common Mistakes:

• Using length() instead of strlen() in C
• Initializing maxLength to 0 instead of 1
• Using Java or C++ string length syntax in C

3. What will be the output of the following C code snippet that finds the longest palindromic substring length?

char s[] = "babad";
int maxLength = 1, start = 0;
int len = strlen(s);
for (int i = 0; i < len; i++) {
    int low = i - 1;
    int high = i + 1;
    while (high < len && s[high] == s[i])
        high++;
    while (low >= 0 && s[low] == s[i])
        low--;
    while (low >= 0 && high < len && s[low] == s[high]) {
        low--;
        high++;
    }
    int length = high - low - 1;
    if (maxLength < length) {
        maxLength = length;
        start = low + 1;
    }
}
printf("%d", maxLength);

medium

A. 3

B. 2

C. 4

D. 5

Solution

1. Step 1: Understand the palindrome expansion logic

   The code expands around each character to find palindromes, including duplicates and symmetric characters.

2. Step 2: Trace the longest palindrome in "babad"

   Longest palindromic substrings are "bab" or "aba", both length 3.

3. Final Answer:

   3 -> Option A

4. Quick Check:

   Longest palindrome in "babad" = 3 [OK]

Hint: Check palindrome centers and expand outwards [OK]

Common Mistakes:

• Assuming entire string is palindrome
• Counting non-continuous characters
• Ignoring multiple palindrome centers

4. Identify the bug in the following C code snippet intended to find the longest palindromic substring length:

char s[] = "cbbd";
int maxLength = 1, start = 0;
int len = strlen(s);
for (int i = 0; i < len; i++) {
    int low = i - 1;
    int high = i + 1;
    while (low >= 0 && high < len && s[low] == s[high]) {
        low--;
        high++;
    }
    int length = high - low - 1;
    if (maxLength < length) {
        maxLength = length;
        start = low + 1;
    }
}
printf("%d", maxLength);

medium

A. The code does not check for even length palindromes correctly

B. The variable 'start' is not updated properly

C. The initial maxLength should be 0, not 1

D. The loops use wrong comparison operators

Solution

1. Step 1: Analyze palindrome detection logic

   The code expands around a single center character, missing even length palindromes like "bb" in "cbbd".

2. Step 2: Identify missing even length palindrome check

   Even length palindromes require checking centers between characters, which is not done here.

3. Final Answer:

   The code does not check for even length palindromes correctly -> Option A

4. Quick Check:

   Missing even length palindrome check = bug [OK]

Hint: Check centers between characters for even palindromes [OK]

Common Mistakes:

• Only checking odd length palindromes
• Not updating start index correctly
• Wrong initial maxLength value

5. Given the string "forgeeksskeegfor", which approach correctly finds the longest palindromic substring and what is its length? A) Brute force method, length 8 B) Dynamic programming method, length 12 C) Expand around center method, length 12 D) Expand around center method, length 10

hard

A. Brute force method, length 8

B. Dynamic programming method, length 12

C. Expand around center method, length 12

D. Expand around center method, length 10

Solution

1. Step 1: Identify longest palindrome in "forgeeksskeegfor"

   The longest palindromic substring is "geeksskeeg", length 10.

2. Step 2: Check method correctness and length

   Expand around center method can find the longest palindrome correctly. The longest palindrome is "geeksskeeg" (length 10).

3. Step 3: Re-examine options

   Expand around center method, length 10 says expand around center method, length 10 which is correct. Other options have incorrect lengths or methods.

4. Final Answer:

   Expand around center method, length 10 -> Option D

5. Quick Check:

   Longest palindrome "geeksskeeg" length 10 [OK]

Hint: Longest palindrome is "geeksskeeg" length 10 [OK]

Common Mistakes:

• Assuming full string is palindrome
• Confusing length 12 with actual palindrome length
• Mixing method with incorrect length