Insert at Beginning Head Insert in DSA C - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does 'Insert at Beginning' mean in a linked list?

It means adding a new node at the start (head) of the linked list, making it the first element.

beginner

Why is inserting at the beginning of a linked list efficient?

Because it only requires changing the head pointer and the new node's next pointer, which takes constant time O(1).

intermediate

In C, what pointer changes are needed to insert a new node at the beginning of a singly linked list?

Set the new node's next pointer to the current head, then update the head pointer to the new node.

beginner

What happens to the old head node after inserting a new node at the beginning?

The old head becomes the second node in the list, as the new node points to it.

intermediate

Show the basic C code snippet to insert a node at the beginning of a singly linked list.

struct Node* newNode = malloc(sizeof(struct Node)); newNode->data = value; newNode->next = head; head = newNode;

What is the time complexity of inserting a node at the beginning of a singly linked list?

A O(n)

B O(1)

C O(log n)

D O(n^2)

Inserting at the beginning only changes a few pointers, so it takes constant time O(1).

Which pointer must be updated to insert a new node at the beginning of a linked list?

A The head pointer

B The tail pointer

C The next pointer of the last node

D The previous pointer

The head pointer must point to the new node after insertion.

After inserting a new node at the beginning, what does the new node's next pointer point to?

A NULL

B The tail node

C The old head node

D Itself

The new node's next pointer points to the old head node, linking the list.

Which of these is NOT needed when inserting at the beginning of a singly linked list in C?

A Allocating memory for the new node

B Changing the new node's next pointer

C Updating the head pointer

D Traversing the entire list

Traversing the list is not needed because insertion is at the head.

What happens if you forget to update the head pointer after inserting a new node at the beginning?

A The list will lose the new node and may cause errors

B The new node becomes the tail

C The list remains unchanged

D The list will reverse

Without updating head, the new node is not linked as the first node, causing loss of access.

Explain step-by-step how to insert a new node at the beginning of a singly linked list in C.

Think about how pointers change to keep the list connected.

Describe why inserting at the beginning of a linked list is faster than inserting at the end.

Consider how many nodes you must visit for each insertion.

Practice

1. What does the "Insert at Beginning" operation do in a singly linked list?

easy

A. Deletes the first node of the list

B. Adds a new node at the end of the list

C. Adds a new node at the start of the list

D. Deletes the last node of the list

Solution

1. Step 1: Understand the operation

   Inserting at the beginning means placing a new node before the current first node.

2. Step 2: Effect on the list

   The new node becomes the head, pushing the old head to second position.

3. Final Answer:

   Adds a new node at the start of the list -> Option C

4. Quick Check:

   Insert at beginning = Add new head [OK]

Hint: New node becomes head, old head moves next [OK]

Common Mistakes:

• Confusing insert at beginning with insert at end
• Thinking it deletes nodes
• Assuming it inserts in the middle

2. Which of the following is the correct syntax to insert a new node at the beginning in C for a singly linked list?

easy

A. newNode->next = head; head = newNode;

B. head = newNode->next; newNode = head;

C. head->next = newNode; newNode = head;

D. newNode = head; head->next = newNode;

Solution

1. Step 1: Assign newNode's next to current head

   This links the new node to the existing list.

2. Step 2: Update head to newNode

   Now the new node is the first node in the list.

3. Final Answer:

   newNode->next = head; head = newNode; -> Option A

4. Quick Check:

   Link newNode to head, then update head [OK]

Hint: Point newNode->next to head, then head to newNode [OK]

Common Mistakes:

• Swapping assignments order
• Assigning head to newNode->next incorrectly
• Not updating head pointer

3. What will be the linked list after inserting nodes with values 10, then 20, then 30 at the beginning in that order? Assume the list was initially empty.

medium

A. 10 -> 20 -> 30 -> null

B. 10 -> 30 -> 20 -> null

C. 20 -> 30 -> 10 -> null

D. 30 -> 20 -> 10 -> null

Solution

1. Step 1: Insert 10 at beginning

   List becomes 10 -> null.

2. Step 2: Insert 20 at beginning

   List becomes 20 -> 10 -> null.

3. Step 3: Insert 30 at beginning

   List becomes 30 -> 20 -> 10 -> null.

4. Final Answer:

   30 -> 20 -> 10 -> null -> Option D

5. Quick Check:

   Last inserted is new head [OK]

Hint: Last inserted node is always head [OK]

Common Mistakes:

• Assuming insertion at end
• Reversing insertion order
• Confusing node values order

4. Given the following code snippet, what is the error that prevents correct insertion at the beginning?

struct Node {
  int data;
  struct Node* next;
};

void insertAtBeginning(struct Node** head, int val) {
  struct Node* newNode = malloc(sizeof(struct Node));
  newNode->data = val;
  newNode->next = NULL;
  *head = newNode;
}

medium

A. malloc size is incorrect

B. newNode->next should point to current head before updating head

C. newNode->data is not assigned

D. head pointer should not be double pointer

Solution

1. Step 1: Check newNode->next assignment

   It is set to NULL, losing the existing list.

2. Step 2: Correct linking

   newNode->next should point to current head before head is updated.

3. Final Answer:

   newNode->next should point to current head before updating head -> Option B

4. Quick Check:

   Link newNode->next to old head before head update [OK]

Hint: Link newNode->next to old head before head update [OK]

Common Mistakes:

• Setting newNode->next to NULL always
• Not using double pointer for head
• Forgetting to assign data

5. You have a singly linked list with nodes: 5 -> 15 -> 25 -> null. You want to insert a new node with value 10 at the beginning. After insertion, what will be the correct sequence of nodes?

hard

A. 10 -> 5 -> 15 -> 25 -> null

B. 5 -> 10 -> 15 -> 25 -> null

C. 10 -> 15 -> 25 -> 5 -> null

D. 5 -> 15 -> 25 -> 10 -> null

Solution

1. Step 1: Current list is 5 -> 15 -> 25 -> null

   This is the starting list before insertion.

2. Step 2: Insert 10 at beginning

   New node 10 points to current head (5), then head updated to 10.

3. Final Answer:

   10 -> 5 -> 15 -> 25 -> null -> Option A

4. Quick Check:

   New node becomes head, old head follows [OK]

Hint: New node points to old head, becomes new head [OK]

Common Mistakes:

• Inserting at wrong position
• Not updating head pointer
• Linking nodes incorrectly