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DSA Cprogramming~10 mins

Hash Table Concept and Hash Functions in DSA C - Execution Trace

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Concept Flow - Hash Table Concept and Hash Functions
Start: Insert or Search Key
Apply Hash Function to Key
Compute Index = Hash Value % Table Size
Access Bucket at Index
If Insert: Add Key-Value Pair to Bucket
If Search: Check Bucket for Key
Return Value or Indicate Not Found
The hash table uses a hash function to convert a key into an index, then accesses that index to insert or find the key-value pair.
Execution Sample
DSA C
int hash(int key, int table_size) {
    return key % table_size;
}

// Insert key 10 into table of size 5
int index = hash(10, 5);
This code computes the index for key 10 in a hash table of size 5 using modulo hash function.
Execution Table
StepOperationKeyHash ValueIndex (Hash % Size)Bucket StateVisual State
1Compute hash for key101010 % 5 = 0Bucket 0: [][] -> [] -> [] -> [] -> []
2Insert key-value pair10100Bucket 0: [(10, value)][(10)] -> [] -> [] -> [] -> []
3Compute hash for key151515 % 5 = 0Bucket 0: [(10, value)][(10)] -> [] -> [] -> [] -> []
4Insert key-value pair15150Bucket 0: [(10, value), (15, value)][(10)->(15)] -> [] -> [] -> [] -> []
5Search for key10100Bucket 0: [(10, value), (15, value)][(10)->(15)] -> [] -> [] -> [] -> []
6Found key 10 in bucket 010100Bucket 0 unchanged[(10)->(15)] -> [] -> [] -> [] -> []
7Search for key777 % 5 = 2Bucket 2: [][(10)->(15)] -> [] -> [] -> [] -> []
8Key 7 not found in bucket 2772Bucket 2 unchanged[(10)->(15)] -> [] -> [] -> [] -> []
💡 All operations complete; keys inserted or searched with hash function mapping to buckets.
Variable Tracker
VariableStartAfter Step 1After Step 2After Step 4After Step 6After Step 8
keyN/A101015107
hash_valueN/A101015107
indexN/A00002
bucket_0[][][(10, value)][(10, value)->(15, value)][(10, value)->(15, value)][(10, value)->(15, value)]
bucket_2[][][][][][]
Key Moments - 3 Insights
Why do multiple keys like 10 and 15 end up in the same bucket?
Because the hash function maps both keys to the same index 0 (10 % 5 = 0 and 15 % 5 = 0), causing a collision handled by storing both in the same bucket (see steps 3 and 4 in execution_table).
What happens when searching for a key not present in the table?
The hash function computes the index, but the bucket at that index is empty or does not contain the key, so the search returns not found (see steps 7 and 8 in execution_table).
Why use modulo (%) with table size in the hash function?
Modulo ensures the hash value fits within the table size range, giving a valid index (see step 1 and 3 where hash values are reduced by modulo).
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table at step 4, what is the state of bucket 0?
A[(10, value)]
B[(15, value)]
C[(10, value), (15, value)]
D[]
💡 Hint
Refer to the 'Bucket State' column at step 4 in execution_table.
At which step does the search for key 7 conclude it is not found?
AStep 8
BStep 6
CStep 7
DStep 5
💡 Hint
Check the 'Operation' and 'Key' columns for key 7 in execution_table.
If the table size changed from 5 to 10, what would be the index for key 15?
A0
B5
C10
D15
💡 Hint
Calculate 15 % 10 and compare with the 'Index' column logic in execution_table.
Concept Snapshot
Hash Table uses a hash function to convert keys into indexes.
Index = hash(key) % table_size ensures valid bucket access.
Collisions happen when multiple keys map to the same index.
Buckets store key-value pairs; search checks bucket contents.
Efficient average lookup, insert, and delete operations.
Full Transcript
A hash table stores data by converting keys into indexes using a hash function. The hash function computes a number from the key, then modulo operation limits it to the table size. This index points to a bucket where the key-value pair is stored. When inserting, if multiple keys map to the same bucket, they are stored together, handling collisions. Searching uses the same hash function to find the bucket and then looks for the key inside it. If the key is not found, the search ends. This method allows fast access to data by key.