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DSA Cprogramming~10 mins

Enqueue Operation in DSA C - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to add an element at the rear of the queue.

DSA C
queue->rear = (queue->rear + 1) % queue->capacity;
queue->array[queue->rear] = [1];
Drag options to blanks, or click blank then click option'
Acapacity
Brear
Citem
Dfront
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'rear' or 'front' instead of the item variable.
Assigning to the wrong index in the array.
2fill in blank
medium

Complete the code to check if the queue is full before enqueue.

DSA C
if ((queue->rear + 1) % queue->capacity == [1]) {
    return; // Queue is full
}
Drag options to blanks, or click blank then click option'
Aqueue->front
Bqueue->rear
Cqueue->capacity
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Comparing with rear or capacity instead of front.
Using incorrect modulo logic.
3fill in blank
hard

Fix the error in updating the rear index after enqueue.

DSA C
queue->rear = (queue->rear [1] 1) % queue->capacity;
Drag options to blanks, or click blank then click option'
A-
B+
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using subtraction or multiplication instead of addition.
Forgetting modulo operation.
4fill in blank
hard

Fill both blanks to correctly enqueue an item and update size.

DSA C
queue->rear = (queue->rear [1] 1) % queue->capacity;
queue->array[queue->rear] = [2];
queue->size++;
Drag options to blanks, or click blank then click option'
A+
Bitem
C-
Drear
Attempts:
3 left
💡 Hint
Common Mistakes
Using '-' instead of '+' for rear update.
Assigning wrong variable to array.
5fill in blank
hard

Fill all three blanks to enqueue an item safely with full check.

DSA C
if ((queue->rear [1] 1) % queue->capacity == queue->front) {
    return; // Queue full
}
queue->rear = (queue->rear [2] 1) % queue->capacity;
queue->array[queue->rear] = [3];
queue->size++;
Drag options to blanks, or click blank then click option'
A+
B-
Citem
Dfront
Attempts:
3 left
💡 Hint
Common Mistakes
Using '-' instead of '+' in condition or update.
Assigning wrong variable to array.

Practice

(1/5)
1. What does the enqueue operation do in a queue data structure?
easy
A. Adds an element to the rear of the queue
B. Removes an element from the front of the queue
C. Checks if the queue is empty
D. Returns the size of the queue

Solution

  1. Step 1: Understand the queue operations

    In a queue, enqueue means adding an element, while dequeue means removing one.
  2. Step 2: Identify the position of addition

    Elements are always added at the rear (end) of the queue during enqueue.
  3. Final Answer:

    Adds an element to the rear of the queue -> Option A
  4. Quick Check:

    Enqueue = Add rear [OK]
Hint: Enqueue always adds at the back of the queue [OK]
Common Mistakes:
  • Confusing enqueue with dequeue operation
  • Thinking enqueue removes elements
  • Assuming enqueue adds at the front
2. Which of the following is the correct syntax to enqueue an element 10 in a queue implemented using an array named queue with rear index rear in C?
easy
A. queue[rear] = ++10;
B. queue[rear++] = 10;
C. queue[rear] = 10++;
D. queue[++rear] = 10;

Solution

  1. Step 1: Understand post-increment vs pre-increment

    Post-increment (rear++) uses rear as index then increments it. Pre-increment (++rear) increments rear first then uses it as index.
  2. Step 2: Choose correct index update for enqueue

    To add at current rear position and then move rear forward, use post-increment: queue[rear++] = 10;.
  3. Final Answer:

    queue[rear++] = 10; -> Option B
  4. Quick Check:

    Post-increment rear after assignment [OK]
Hint: Use rear++ to assign then move rear forward [OK]
Common Mistakes:
  • Using pre-increment causing skip of first index
  • Trying to increment the value instead of index
  • Syntax errors with invalid increments
3. What will be the state of the queue array after executing the following code?
int queue[5];
int rear = -1;
queue[++rear] = 5;
queue[++rear] = 10;
queue[++rear] = 15;
medium
A. [5, 10, 0, 15, 0]
B. [0, 5, 10, 15, 0]
C. [5, 10, 15, 0, 0]
D. [15, 10, 5, 0, 0]

Solution

  1. Step 1: Trace each enqueue operation

    Initially, rear = -1.
    First enqueue: ++rear = 0, queue[0] = 5.
    Second enqueue: ++rear = 1, queue[1] = 10.
    Third enqueue: ++rear = 2, queue[2] = 15.
  2. Step 2: Determine final queue array state

    Positions 0,1,2 have 5,10,15 respectively. Others remain 0 (default uninitialized).
  3. Final Answer:

    [5, 10, 15, 0, 0] -> Option C
  4. Quick Check:

    Enqueue adds sequentially at indices 0,1,2 [OK]
Hint: Pre-increment rear before assignment fills array from index 0 [OK]
Common Mistakes:
  • Confusing post-increment with pre-increment
  • Assuming queue starts at index 1
  • Ignoring initial rear value -1
4. Identify the error in the following enqueue function for a queue implemented using an array and fix it:
void enqueue(int queue[], int *rear, int value) {
    queue[*rear] = value;
    (*rear)++;
}
medium
A. The value should be assigned after incrementing rear twice
B. The rear should not be incremented at all
C. The function should decrement rear instead
D. The rear should be incremented before assignment

Solution

  1. Step 1: Analyze the enqueue logic

    The function assigns value at current rear index, then increments rear.
    This causes the first element to be placed at rear=0 if rear was 0, which is correct only if rear points to next free slot.
  2. Step 2: Correct the order for standard enqueue

    Usually, rear points to last filled index, so increment rear first, then assign:
    queue[++(*rear)] = value;.
  3. Final Answer:

    The rear should be incremented before assignment -> Option D
  4. Quick Check:

    Increment rear first, then assign value [OK]
Hint: Increment rear before assignment to avoid overwrite [OK]
Common Mistakes:
  • Assigning value before incrementing rear
  • Incrementing rear twice accidentally
  • Decrementing rear instead of incrementing
5. Given a circular queue of size 5 with front = 3 and rear = 1, which of the following enqueue operations is valid and will not cause overflow?
hard
A. Enqueue at rear = 2
B. Enqueue at rear = 3
C. Enqueue at rear = 4
D. Enqueue at rear = 0

Solution

  1. Step 1: Understand circular queue indexing

    Queue size = 5, indices 0 to 4.
    front = 3, rear = 1 means elements occupy positions from front to rear wrapping around.
  2. Step 2: Check next rear position for enqueue

    Next rear = (rear + 1) % size = (1 + 1) % 5 = 2.
    If next rear equals front, queue is full (overflow). Here, next rear 2 != front 3, so enqueue at 2 is valid.
    But options show enqueue at rear = 2, 3, 4, 0. We must check which is correct next rear.
  3. Step 3: Validate each option

    Enqueue at rear = 2: rear=2 is next rear, valid.
    Enqueue at rear = 3: rear=3 equals front, overflow.
    Enqueue at rear = 4: rear=4 is not next rear, invalid.
    Enqueue at rear = 0: rear=0 is not next rear, invalid.
  4. Final Answer:

    Enqueue at rear = 2 -> Option A
  5. Quick Check:

    Next rear = (rear+1)%size = 2, enqueue valid [OK]
Hint: Next rear = (rear + 1) mod size; must not equal front [OK]
Common Mistakes:
  • Ignoring circular wrap-around logic
  • Enqueueing at front index causing overflow
  • Assuming rear can be any index
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