📖 Scenario: Imagine you are managing a line of customers at a store where people can join or leave from both the front and the back of the line. This line is called a double ended queue or deque.
🎯 Goal: You will build a simple double ended queue (deque) using an array in C. You will add elements to the front and back, remove elements from the front and back, and finally print the current state of the deque.
📋 What You'll Learn
Create an array-based deque with fixed size 5
Use two integer variables front and rear to track ends
Implement functions to add to front and rear
Implement functions to remove from front and rear
Print the deque elements from front to rear
💡 Why This Matters
🌍 Real World
Deques are used in real-world scenarios like managing tasks where you can add or remove from both ends, such as undo-redo operations or browser history.
💼 Career
Understanding deque implementation helps in software development roles where efficient data handling and queue management are required.
Progress0 / 4 steps
1
Create the deque data structure
Create an integer array called deque with size 5. Also create two integer variables called front and rear and set both to -1.
DSA C
Hint
Use int deque[5]; to create the array. Initialize front and rear to -1 to show the deque is empty.
2
Add elements to the rear of the deque
Write a function called addRear that takes an integer value and adds it to the rear of the deque. Update rear and front accordingly when adding the first element.
DSA C
Hint
Check if rear reached 4 (end of array). If empty, set front to 0. Then increase rear and store the value.
3
Add elements to the front of the deque
Write a function called addFront that takes an integer value and adds it to the front of the deque. Update front accordingly. If the deque is empty, set front and rear to 0.
DSA C
Hint
If front is 0, no space to add front. If empty, set both front and rear to 0 and add value. Otherwise, decrease front and add value.
4
Print the current deque elements
Write a function called printDeque that prints all elements from front to rear separated by spaces. Then call addRear(10), addRear(20), addFront(5), and finally print the deque.
DSA C
Hint
Loop from front to rear and print each element with a space. Call the add functions as instructed before printing.
Practice
(1/5)
1. What is a Double Ended Queue (Deque)?
easy
A. A queue where insertion happens only at the rear and deletion at the front
B. A data structure where insertion and deletion can happen at both ends
C. A stack where insertion and deletion happen only at one end
D. A list that allows random access to elements
Solution
Step 1: Understand the definition of Deque
A Deque allows adding and removing elements from both front and rear ends.
Step 2: Compare with other data structures
Unlike a queue or stack, Deque supports operations at both ends.
Final Answer:
A data structure where insertion and deletion can happen at both ends -> Option B
Quick Check:
Deque = Both ends insertion/deletion [OK]
Hint: Deque means double-ended queue, both ends allowed [OK]
Common Mistakes:
Confusing deque with stack or queue
Thinking insertion is only at one end
Assuming random access like arrays
2. Which of the following is the correct syntax to initialize an empty deque in C using an array implementation?
easy
A. int deque[] = {}; int front = 0, rear = 0;
B. int deque[SIZE] = NULL; int front = 0, rear = 0;
C. int deque[SIZE]; int front = -1, rear = -1;
D. int deque[SIZE]; int front = 0, rear = -1;
Solution
Step 1: Understand initialization of deque with front and rear
Front and rear are set to -1 to indicate empty deque.
Step 2: Check array declaration and initial values
int deque[SIZE]; int front = -1, rear = -1; correctly declares array and sets front and rear to -1.
Final Answer:
int deque[SIZE]; int front = -1, rear = -1; -> Option C
Quick Check:
Empty deque front and rear = -1 [OK]
Hint: Empty deque front and rear start at -1 [OK]
Common Mistakes:
Setting front or rear to 0 initially
Using NULL for array initialization
Leaving array size unspecified
3. Consider the following operations on an empty deque of size 5 implemented using an array: insertRear(10); insertRear(20); insertFront(5); deleteRear(); insertFront(15); What is the content of the deque from front to rear after these operations?
medium
A. 15 -> 5 -> 10 -> null
B. 5 -> 15 -> 10 -> null
C. 15 -> 5 -> null
D. 10 -> 5 -> 15 -> null
Solution
Step 1: Perform insertRear(10) and insertRear(20)
Deque: 10 -> 20
Step 2: Perform insertFront(5)
Deque: 5 -> 10 -> 20
Step 3: Perform deleteRear()
Removes 20, Deque: 5 -> 10
Step 4: Perform insertFront(15)
Deque: 15 -> 5 -> 10
Final Answer:
15 -> 5 -> 10 -> null -> Option A
Quick Check:
Operations result in 15,5,10 order [OK]
Hint: Track front and rear insertions stepwise [OK]
Common Mistakes:
Forgetting deleteRear removes last element
Mixing order of insertFront and insertRear
Assuming insertFront adds at rear
4. Given the following code snippet for deque insertion at front, identify the error:
void insertFront(int deque[], int *front, int *rear, int value) {
if (*front == 0) {
printf("Deque is full at front\n");
return;
}
(*front)--;
deque[*front] = value;
}
medium
A. It incorrectly checks full condition only at front == 0
B. It decrements front before insertion causing invalid index
C. It does not check if deque is empty before insertion
D. It should increment front instead of decrement
Solution
Step 1: Analyze the full condition check
Checking only if front == 0 is not enough to detect full deque.
Step 2: Understand circular deque logic
Deque can be full even if front != 0, so this check is incomplete.
Final Answer:
It incorrectly checks full condition only at front == 0 -> Option A
Quick Check:
Full check must consider rear position too [OK]
Hint: Full deque check needs both front and rear positions [OK]
Common Mistakes:
Assuming front == 0 means full always
Not handling circular wrap-around
Decrementing front without boundary check
5. You have a deque of size 4 implemented using a circular array. Initially empty, you perform: insertRear(1); insertRear(2); insertFront(3); insertFront(4); deleteRear(); insertRear(5); What is the final state of the deque from front to rear?
hard
A. 4 -> 3 -> 1 -> null
B. 4 -> 3 -> 5 -> null
C. 3 -> 4 -> 1 -> 5 -> null
D. 4 -> 3 -> 1 -> 5 -> null
Solution
Step 1: InsertRear(1), InsertRear(2)
Deque: 1 -> 2
Step 2: InsertFront(3), InsertFront(4)
Deque: 4 -> 3 -> 1 -> 2 (deque full)
Step 3: DeleteRear()
Removes 2, Deque: 4 -> 3 -> 1
Step 4: InsertRear(5)
Deque: 4 -> 3 -> 1 -> 5 (full again)
Final Answer:
4 -> 3 -> 1 -> 5 -> null -> Option D
Quick Check:
Circular deque final state matches 4 -> 3 -> 1 -> 5 -> null [OK]
Hint: Track circular wrap and full capacity carefully [OK]
Common Mistakes:
Ignoring circular wrap-around
Misordering front and rear elements
Forgetting deleteRear removes last element
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