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DSA Cprogramming~10 mins

Delete Node by Value in DSA C - Execution Trace

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Concept Flow - Delete Node by Value
Start at head
Check if head is NULL
Stop
Delete head
Update head
Stop
Delete node
Stop
Start from the head node, check if it matches the value to delete. If yes, delete head. Otherwise, traverse to find the node and delete it if found.
Execution Sample
DSA C
struct Node {
  int data;
  struct Node* next;
};

void deleteNode(struct Node** head, int val) {
  // delete node with value val
}
Deletes the first node with the given value from a singly linked list.
Execution Table
StepCurrent Node ValueConditionActionList State
110head != NULLCheck head value10 -> 20 -> 30 -> 40 -> NULL
21010 == 20?No, move to next10 -> 20 -> 30 -> 40 -> NULL
32020 == 20?Yes, delete this node10 -> 30 -> 40 -> NULL
430Continue traversal?No, node deleted10 -> 30 -> 40 -> NULL
5NULLEnd of listStop10 -> 30 -> 40 -> NULL
💡 Node with value 20 found and deleted, traversal stops.
Variable Tracker
VariableStartAfter Step 1After Step 2After Step 3Final
head10 -> 20 -> 30 -> 40 -> NULL10 -> 20 -> 30 -> 40 -> NULL10 -> 20 -> 30 -> 40 -> NULL10 -> 30 -> 40 -> NULL10 -> 30 -> 40 -> NULL
current1010202030
previousNULLNULL101010
Key Moments - 3 Insights
Why do we check if the head node contains the value before traversing?
Because if the head node has the value, we must update the head pointer to the next node. This is shown in execution_table steps 1-2 where the head value is checked.
What happens if the value is not found in the list?
The traversal reaches the end (NULL) without deleting any node, as shown in execution_table step 5 where the list remains unchanged and the function stops.
Why do we keep track of the previous node during traversal?
To update the previous node's next pointer to skip the deleted node. This is shown in variable_tracker where 'previous' points to the node before 'current' to adjust links.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table, what is the list state after deleting the node with value 20?
A10 -> 20 -> 30 -> 40 -> NULL
B10 -> 30 -> 40 -> NULL
C20 -> 30 -> 40 -> NULL
D10 -> 40 -> NULL
💡 Hint
Check the 'List State' column at step 3 in execution_table.
At which step does the traversal stop after deleting the node?
AStep 2
BStep 3
CStep 4
DStep 5
💡 Hint
Look at the 'Action' column where it says 'node deleted' and traversal stops.
If the value to delete was 10 (head node), what would happen to the head pointer?
AIt stays the same
BIt moves to the next node
CIt becomes NULL immediately
DIt points to the deleted node
💡 Hint
Refer to key_moments about deleting the head node and updating the head pointer.
Concept Snapshot
Delete Node by Value in Linked List:
- Start at head node
- If head matches value, update head to next
- Else traverse list with previous and current pointers
- When node found, link previous->next to current->next
- Free deleted node
- Stop when node deleted or end reached
Full Transcript
To delete a node by value in a singly linked list, start checking from the head node. If the head node contains the value, update the head pointer to the next node and delete the head. Otherwise, traverse the list keeping track of the previous and current nodes. When the node with the target value is found, update the previous node's next pointer to skip the current node, then delete the current node. If the value is not found, the list remains unchanged. This process ensures the linked list remains connected and valid after deletion.