Check if Number is Even or Odd Using Bits in DSA C - Build from Scratch

Check if Number is Even or Odd Using Bits

📖 Scenario: You are building a simple program that checks if a number is even or odd using bit operations. This is like checking if a number is divisible by 2 without using division or modulus. It is a fast way computers decide even or odd.

🎯 Goal: Create a program that uses bitwise AND to check if a number is even or odd and prints the result.

📋 What You'll Learn

Create an integer variable named number with the value 29

Create an integer variable named check to hold the bitwise AND result

Use bitwise AND operator & with number and 1 to set check

Print "Even" if check is 0, otherwise print "Odd"

💡 Why This Matters

🌍 Real World

Checking even or odd numbers quickly is useful in many programs like games, data processing, and hardware control.

💼 Career

Understanding bitwise operations is important for low-level programming, embedded systems, and performance optimization.

1

Create the number variable

Create an integer variable called number and set it to 29.

DSA C

# Your code here

Hint

Use int number = 29; to create the variable.

2

Create the check variable

Create an integer variable called check to store the bitwise AND result.

DSA C

int number = 29;
# Your code here

Hint

Declare int check; without initializing it yet.

3

Use bitwise AND to check even or odd

Set check to the result of number & 1 using the bitwise AND operator.

DSA C

int number = 29;
int check;
# Your code here

Hint

Use check = number & 1; to get the last bit.

4

Print if number is Even or Odd

Write an if statement to print "Even" if check is 0, else print "Odd".

DSA C

int number = 29;
int check;
check = number & 1;
# Your code here

Hint

Use if (check == 0) to check even, else print odd.