It means removing the last element from an array, reducing its size by one.
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beginner
How do you delete the last element of an array in C?
You reduce the array's size count by one, effectively ignoring the last element.
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intermediate
Why can't you physically remove an element from a static array in C?
Because static arrays have fixed size; you can only change the logical size, not the allocated memory.
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beginner
What happens if you try to delete an element from an empty array?
It causes an error or undefined behavior because there is no element to remove.
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beginner
What is the time complexity of deleting the last element in an array?
O(1) because you just reduce the size count without shifting elements.
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What is the main step to delete the last element of an array in C?
ADecrease the size count by one
BShift all elements to the left
CAllocate new memory
DSet last element to zero
✗ Incorrect
Deleting the last element means reducing the logical size by one; no shifting or memory allocation is needed.
What happens to the last element after deletion at the end?
AIt is physically removed from memory
BIt is copied to the front
CIt remains but is ignored logically
DIt is replaced with zero
✗ Incorrect
In static arrays, the element stays in memory but is ignored by reducing the size count.
What is the time complexity of deleting the last element in an array?
AO(log n)
BO(1)
CO(n)
DO(n^2)
✗ Incorrect
Deleting the last element is O(1) because it only involves reducing the size count.
Which of these is NOT required when deleting the last element of an array?
AReducing size count
BUpdating logical size
CChecking if array is empty
DShifting elements
✗ Incorrect
No shifting is needed when deleting the last element.
What should you check before deleting the last element?
AIf the array is empty
BIf the array is sorted
CIf the array is full
DIf the array has duplicates
✗ Incorrect
You must check if the array is empty to avoid errors when deleting.
Explain how to delete the last element from an array in C and what happens to the array size.
Think about how arrays store size and how deletion affects it.
You got /4 concepts.
Describe the time complexity of deleting the last element in an array and why it is efficient.
Consider what operations are needed to remove the last element.
You got /4 concepts.
Practice
(1/5)
1. What happens to the size of an array when you delete an element from the end in a typical static array implementation?
easy
A. The size decreases by one
B. The size stays the same
C. The size increases by one
D. The size becomes zero
Solution
Step 1: Understand array size after deletion
Deleting an element from the end means removing the last element, so the total number of elements reduces by one.
Step 2: Effect on array size
The size variable or count of elements decreases by one to reflect the removal.
Final Answer:
The size decreases by one -> Option A
Quick Check:
Deleting last element reduces size by 1 [OK]
Hint: Deleting end element reduces size by one [OK]
Common Mistakes:
Thinking size stays same after deletion
Assuming size increases after deletion
Confusing deletion with insertion
2. Which of the following is the correct way to delete the last element from an array arr of size n in C?
easy
A. free(arr[n-1]);
B. arr[n] = 0;
C. n = n - 1;
D. arr = arr - 1;
Solution
Step 1: Understand array deletion in C
In static arrays, deleting means reducing the size count. So, decreasing n by 1 removes last element logically.
Step 2: Analyze options
n = n - 1; correctly reduces size. arr[n] = 0; tries to set element but doesn't change size. free(arr[n-1]); is invalid as free is for dynamic memory. arr = arr - 1; is invalid pointer arithmetic.
Final Answer:
n = n - 1; -> Option C
Quick Check:
Decrease size variable to delete last element [OK]
Hint: Reduce size variable to delete last element [OK]
Common Mistakes:
Using free() on static array elements
Trying to set last element to zero without changing size
Incorrect pointer arithmetic
3. What will be the output of the following C code?
int arr[5] = {10, 20, 30, 40, 50};
int n = 5;
n = n - 1;
for(int i = 0; i < n; i++) {
printf("%d ", arr[i]);
}
medium
A. 10 20 30 40 50
B. 10 20 30 40
C. 20 30 40 50
D. 10 20 30
Solution
Step 1: Understand size after deletion
Initially, n is 5. After n = n - 1;, n becomes 4, so loop runs from 0 to 3.
Step 2: Loop prints elements from index 0 to 3
Elements printed are arr[0]=10, arr[1]=20, arr[2]=30, arr[3]=40.
Final Answer:
10 20 30 40 -> Option B
Quick Check:
Loop runs n=4 times, prints first 4 elements [OK]
Hint: After reducing size, loop prints fewer elements [OK]
Common Mistakes:
Printing all 5 elements ignoring updated size
Starting loop from 1 instead of 0
Confusing array indices
4. Identify the error in the following code snippet that attempts to delete the last element of an array arr of size n.
void deleteEnd(int arr[], int n) {
arr[n] = 0;
n = n - 1;
}
medium
A. Accessing arr[n] is out of bounds
B. Size variable n should not be changed
C. Setting arr[n] to 0 deletes the element
D. Function should return the new size
Solution
Step 1: Check array index usage
Array indices go from 0 to n-1. Accessing arr[n] is out of bounds and causes undefined behavior.
Step 2: Understand deletion logic
To delete last element, reduce size n by 1. Setting arr[n] to 0 is invalid and does not delete element.
Final Answer:
Accessing arr[n] is out of bounds -> Option A
Quick Check:
Array index must be less than size [OK]
Hint: Array last index is n-1, not n [OK]
Common Mistakes:
Using arr[n] instead of arr[n-1]
Assuming setting element to zero deletes it
Not updating size correctly
5. Given a dynamic array implemented with a pointer int *arr and current size n, which of the following correctly deletes the last element and updates the array size safely in C?
hard
A. free(arr[n-1]); n = n - 1;
B. arr[n-1] = 0; n = n - 1;
C. arr = arr - 1; n = n - 1;
D. n = n - 1; arr = realloc(arr, n * sizeof(int));
Solution
Step 1: Understand dynamic array deletion
To delete last element, reduce size n by 1 and resize memory using realloc to avoid wasted space.
Step 2: Analyze options
n = n - 1; arr = realloc(arr, n * sizeof(int)); correctly reduces size and resizes memory. arr[n-1] = 0; n = n - 1; sets element to zero but wastes memory. free(arr[n-1]); n = n - 1; incorrectly uses free on element. arr = arr - 1; n = n - 1; does invalid pointer arithmetic.
Final Answer:
n = n - 1; arr = realloc(arr, n * sizeof(int)); -> Option D
Quick Check:
Reduce size and resize memory with realloc [OK]
Hint: Use realloc after reducing size for dynamic arrays [OK]
Common Mistakes:
Not resizing memory after deletion
Using free() on array elements
Incorrect pointer arithmetic
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