[Solved] Identify the issue in this async Django view:async def data_view(request): result = fetch_data() return JsonResponse({'data': result})Assuming fetch_data() is a slow synchronous function. | Django

Django - Async Django

Identify the issue in this async Django view:

async def data_view(request):
    result = fetch_data()
    return JsonResponse({'data': result})

Assuming fetch_data() is a slow synchronous function.

ACalling a synchronous function without await blocks the async event loop

BMissing <code>async</code> keyword before <code>fetch_data()</code>

CJsonResponse cannot be used in async views

DThe view should return a string, not JsonResponse

Step-by-Step Solution

Solution:

Step 1: Recognize sync call in async view
Calling a blocking synchronous function inside an async view blocks the event loop.
Step 2: Consequence
This defeats the purpose of async and can degrade performance.
Final Answer:
Calling a synchronous function without await blocks the async event loop -> Option A
Quick Check:
Sync calls block async views unless run in thread [OK]

Quick Trick: Sync functions block async views unless awaited properly [OK]

Common Mistakes:

MISTAKES

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