[Solved] Which Django code snippet correctly publishes a message to a Redis channel named updates? — Ans: redis_client.publish('updates', 'New data available') | Django

Django - Celery and Background Tasks

Which Django code snippet correctly publishes a message to a Redis channel named updates?

Aredis_client.send('updates', 'New data available')

Bredis_client.subscribe('updates', 'New data available')

Credis_client.publish('updates', 'New data available')

Dredis_client.receive('updates', 'New data available')

Step-by-Step Solution

Solution:

Step 1: Identify the correct Redis method to send messages
The method to send messages is publish, not subscribe, send, or receive.
Step 2: Match method with channel and message
Using publish('updates', 'New data available') sends the message to the 'updates' channel correctly.
Final Answer:
redis_client.publish('updates', 'New data available') -> Option C
Quick Check:
Send message = publish method [OK]

Quick Trick: Use publish() to send, subscribe() to receive messages [OK]

Common Mistakes:

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Which Django code snippet correctly publishes a message to a Redis channel named updates?