Reverse URL resolution with reverse in Django - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ component_behavior

intermediate

What is the output of reverse() with named URL and no args?

Given the following URL pattern and code, what will reverse('home') return?

Django

from django.urls import path, reverse
from django.http import HttpResponse

urlpatterns = [
    path('', lambda request: HttpResponse('Home'), name='home'),
]

url = reverse('home')

A "/"

B "/home/"

C ""

D "/index/"

💡 Hint

Think about the URL pattern for the empty string path.

The URL pattern named 'home' matches the empty string path ''. So reverse('home') returns '/' which is the root URL.

📝 Syntax

intermediate

Which reverse() call correctly resolves URL with one argument?

Given the URL pattern path('article//', view, name='article-detail'), which reverse call correctly builds the URL for id=5?

Django

from django.urls import reverse

# URL pattern: path('article/<int:id>/', view, name='article-detail')

A reverse('article-detail', args={'id': 5})

B reverse('article-detail', kwargs={'pk': 5})

C reverse('article-detail', args=[5])

D reverse('article-detail', kwargs=[5])

💡 Hint

Check the parameter name and how args and kwargs are used.

The URL pattern uses id as the parameter name. Using args=[5] passes the positional argument correctly. Option C uses wrong key pk. Option C uses wrong type for args. Option C uses wrong type for kwargs.

🔧 Debug

advanced

What error does this reverse() call raise?

Given the URL pattern path('profile//', view, name='profile'), what error occurs when calling reverse('profile') without arguments?

Django

from django.urls import reverse

# URL pattern: path('profile/<str:username>/', view, name='profile')
url = reverse('profile')

A NoReverseMatch

B TypeError

C ValueError

D KeyError

💡 Hint

The URL requires a parameter but none was given.

The reverse function raises NoReverseMatch when required arguments are missing for URL parameters.

❓ state_output

advanced

What is the value of url after reverse with kwargs?

Given the URL pattern path('blog//', view, name='blog-detail'), what is the value of url after this code?

url = reverse('blog-detail', kwargs={'slug': 'my-first-post'})

Django

from django.urls import reverse

# URL pattern: path('blog/<slug:slug>/', view, name='blog-detail')
url = reverse('blog-detail', kwargs={'slug': 'my-first-post'})

A "/blog/my-first-post"

B "/blog/my-first-post/"

C "/blog//"

D "/blog/my_first_post/"

💡 Hint

Check the trailing slash in the URL pattern.

The URL pattern ends with a slash, so the reversed URL includes it. The slug is inserted as given.

🧠 Conceptual

expert

Why use reverse() instead of hardcoding URLs in Django templates?

Which is the best reason to use reverse() or the {% url %} template tag instead of hardcoding URLs in Django projects?

A It automatically translates URLs to different languages.

B It makes the code run faster by caching URLs at compile time.

C It allows URLs to be encrypted for security.

D It ensures URLs update automatically if URL patterns change, avoiding broken links.

💡 Hint

Think about maintainability and avoiding mistakes.

Using reverse() or {% url %} keeps URLs consistent with URL patterns. If you change a URL pattern, all references update automatically, preventing broken links.