List display configuration in Django - Mini Project: Build & Apply

List Display Configuration in Django Admin

📖 Scenario: You are building a Django web application to manage a bookstore. You want to customize the Django admin interface to show a list of books with specific details.

🎯 Goal: Configure the Django admin to display a list of books showing the title, author, and published_year columns.

📋 What You'll Learn

Create a Django model called Book with fields title, author, and published_year.

Create an admin class called BookAdmin.

Add a list_display attribute to BookAdmin with the fields title, author, and published_year.

Register the Book model with the BookAdmin class.

💡 Why This Matters

🌍 Real World

Customizing the Django admin list display helps administrators quickly see important information about data entries, improving management efficiency.

💼 Career

Knowing how to configure Django admin is essential for backend developers working with Django to build maintainable and user-friendly admin interfaces.

1

Create the Book model

Create a Django model called Book in models.py with these exact fields: title as a CharField with max length 100, author as a CharField with max length 50, and published_year as an IntegerField.

Django

# Your code here to define the Book model

Need a hint?

Use models.CharField for text fields and models.IntegerField for numbers.

2

Create the BookAdmin class

In admin.py, import admin and the Book model. Then create a class called BookAdmin that inherits from admin.ModelAdmin.

Django

from django.db import models

class Book(models.Model):
    title = models.CharField(max_length=100)
    author = models.CharField(max_length=50)
    published_year = models.IntegerField()

# Your code here to create BookAdmin class

Need a hint?

Remember to import admin and Book before defining BookAdmin.

3

Add list_display to BookAdmin

Add a list_display attribute to the BookAdmin class with the exact list: 'title', 'author', and 'published_year'.

Django

from django.db import models
from django.contrib import admin
from .models import Book

class BookAdmin(admin.ModelAdmin):
    # Your code here to add list_display

Need a hint?

Use a tuple with the field names as strings for list_display.

4

Register Book with BookAdmin

Register the Book model with the BookAdmin class using admin.site.register(Book, BookAdmin).

Django

from django.db import models
from django.contrib import admin
from .models import Book

class BookAdmin(admin.ModelAdmin):
    list_display = ('title', 'author', 'published_year')

# Your code here to register Book with BookAdmin

Need a hint?

Use admin.site.register() with two arguments: the model and the admin class.