Error handling and logging in Deno - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the purpose of error handling in Deno?

Error handling in Deno helps the program manage unexpected problems gracefully, preventing crashes and allowing the developer to respond to errors properly.

beginner

How do you catch errors in Deno using try-catch?

You wrap the code that might fail inside a try block and handle errors in the catch block, like this:

try {
  // risky code
} catch (error) {
  console.error(error);
}

beginner

What is the role of logging in Deno applications?

Logging records important events or errors during program execution. It helps developers understand what happened and diagnose issues.

beginner

How can you log messages in Deno?

You can use console.log() for general messages and console.error() for error messages. Deno also supports advanced logging modules for structured logs.

intermediate

What is a simple way to handle asynchronous errors in Deno?

Use try-catch inside an async function or handle errors with .catch() on promises to catch errors from asynchronous operations.

Which block is used to handle errors in Deno?

A catch

B try

C finally

D handle

The catch block is used to handle errors thrown inside the try block.

What does console.error() do in Deno?

A Sends errors to a file

B Stops the program

C Catches errors automatically

D Logs error messages to the console

console.error() prints error messages to the console, helping developers see problems.

How do you catch errors from an async function in Deno?

A Using try-catch inside the async function

B Using only try without catch

C Using console.log

D Errors cannot be caught in async functions

You use try-catch inside async functions to catch errors from awaited operations.

Which of these is NOT a valid way to log in Deno?

A console.log()

B console.print()

C console.error()

D Using third-party logging modules

console.print() is not a valid logging method in Deno.

Why is error handling important in Deno applications?

A To avoid writing logs

B To make the program run faster

C To prevent program crashes and manage unexpected issues

D To automatically fix bugs

Error handling helps keep the program running smoothly by managing unexpected problems.

Explain how to use try-catch blocks for error handling in Deno.

Think about wrapping risky code and catching errors.

Describe the role of logging in debugging Deno applications.

Logging helps you see what happened inside your program.

Practice

1. What is the main purpose of using try...catch in Deno?

easy

A. To handle errors and keep the program running smoothly

B. To speed up the program execution

C. To create new files automatically

D. To log messages to the console

Solution

1. Step 1: Understand the role of try...catch

   The try...catch block is used to catch errors that happen during program execution.

2. Step 2: Identify the effect on program flow

   By catching errors, the program can handle them gracefully and continue running instead of crashing.

3. Final Answer:

   To handle errors and keep the program running smoothly -> Option A

4. Quick Check:

   Error handling = To handle errors and keep the program running smoothly [OK]

Hint: Try...catch blocks catch errors to prevent crashes [OK]

Common Mistakes:

• Thinking try...catch speeds up code
• Confusing error handling with logging
• Believing try...catch creates files

2. Which of the following is the correct syntax to log an error message in Deno?

easy

A. console.log.error('An error occurred')

B. console.error('An error occurred')

C. console.err('An error occurred')

D. console.errorMessage('An error occurred')

Solution

1. Step 1: Recall the console methods in Deno

   Deno uses standard JavaScript console methods like console.error() to log error messages.

2. Step 2: Check each option's syntax

   Only console.error('An error occurred') is valid syntax for logging errors.

3. Final Answer:

   console.error('An error occurred') -> Option B

4. Quick Check:

   console.error() logs errors = console.error('An error occurred') [OK]

Hint: Use console.error() to log errors clearly [OK]

Common Mistakes:

• Using non-existent console methods
• Mixing console.log and error methods incorrectly
• Misspelling console.error

3. What will be the output of this Deno code?

try {
  throw new Error('Oops!')
} catch (e) {
  console.log('Caught:', e.message)
}

medium

A. Caught: Oops!

B. Error: Oops!

C. Caught: undefined

D. No output

Solution

1. Step 1: Understand the throw and catch behavior

   The code throws an error with message 'Oops!'. The catch block catches it and accesses e.message.

2. Step 2: Analyze the console.log output

   The catch block logs 'Caught:' followed by the error message, so output is 'Caught: Oops!'.

3. Final Answer:

   Caught: Oops! -> Option A

4. Quick Check:

   Catch logs error message = Caught: Oops! [OK]

Hint: Catch block logs error.message after throw [OK]

Common Mistakes:

• Expecting full error object printed
• Confusing error message with undefined
• Thinking no output occurs

4. Identify the error in this Deno code snippet:

try {
  const data = JSON.parse('{ bad json }')
} catch {
  console.log('Parsing failed', e.message)
}

medium

A. console.log should be console.error

B. JSON.parse syntax is correct

C. Missing error parameter in catch block

D. try block should not have code

Solution

1. Step 1: Check catch block syntax

   In Deno (and modern JavaScript), catch block can omit error parameter, but to access error details, it must be declared.

2. Step 2: Identify the problem with missing error parameter

   The code tries to catch error but does not declare error variable, so error details can't be accessed if needed.

3. Final Answer:

   Missing error parameter in catch block -> Option C

4. Quick Check:

   Catch needs error param to access error = Missing error parameter in catch block [OK]

Hint: Always include error param in catch to access error info [OK]

Common Mistakes:

• Assuming catch() always requires error param
• Thinking console.log is wrong for errors
• Believing try block can't have code

5. You want to log an error with a timestamp and the error message in Deno. Which code snippet correctly does this?

hard

A. try {
throw new Error('Fail')
} catch (e) {
console.log('Error:', e)
}

B. try {
throw new Error('Fail')
} catch (e) {
console.error(e)
console.log(new Date())
}

C. try {
throw new Error('Fail')
} catch {
console.error('Error occurred')
}

D. try {
throw new Error('Fail')
} catch (e) {
console.error(`[${new Date().toISOString()}] Error: ${e.message}`)
}

Solution

1. Step 1: Understand the requirement for timestamp and message

   The log must include current time in ISO format and the error message.

2. Step 2: Check each option for correct formatting

   try { throw new Error('Fail') } catch (e) { console.error(`[${new Date().toISOString()}] Error: ${e.message}`) } uses template literals to combine timestamp and error message in one console.error call, which is correct.

3. Final Answer:

   try { throw new Error('Fail') } catch (e) { console.error(`[${new Date().toISOString()}] Error: ${e.message}`) } -> Option D

4. Quick Check:

   Timestamp + error message in one log = try { throw new Error('Fail') } catch (e) { console.error(`[${new Date().toISOString()}] Error: ${e.message}`) } [OK]

Hint: Use template literals with new Date().toISOString() for timestamps [OK]

Common Mistakes:

• Logging error and timestamp separately
• Missing error parameter in catch
• Using console.log instead of console.error for errors