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Denoframework~10 mins

deno bench for benchmarking - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to import the benchmarking function from Deno standard library.

Deno
import { [1] } from "https://deno.land/std@0.177.0/testing/bench.ts";
Drag options to blanks, or click blank then click option'
Arun
Btest
Cmeasure
Dbench
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'test' instead of 'bench' causes confusion with tests.
Using 'run' or 'measure' are not valid imports here.
2fill in blank
medium

Complete the code to define a benchmark named 'array push'.

Deno
bench({ name: "array push", fn() { const arr = []; arr.[1](1); } });
Drag options to blanks, or click blank then click option'
Aappend
Bpush
Cadd
Dinsert
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'append' which is not a JavaScript array method.
Using 'add' or 'insert' which do not exist on arrays.
3fill in blank
hard

Fix the error in the benchmark function to correctly await an async operation.

Deno
bench({ name: "async wait", async fn() { await [1](100); } });
Drag options to blanks, or click blank then click option'
Adelay
Bwait
Csleep
Dpause
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'wait' or 'delay' which are not standard Deno functions.
Using 'pause' which does not exist.
4fill in blank
hard

Fill both blanks to create a benchmark that measures sorting an array of numbers.

Deno
bench({ name: "sort numbers", fn() { const nums = [3, 1, 2]; nums.[1]((a, b) => a [2] b); } });
Drag options to blanks, or click blank then click option'
Asort
B-
C+
Dreverse
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'reverse' instead of 'sort' changes order but does not sort numerically.
Using '+' in compare function causes incorrect sorting.
5fill in blank
hard

Fill all three blanks to create a benchmark that times a loop incrementing a counter.

Deno
bench({ name: "loop increment", fn() { let count = 0; for(let i = 0; i < [1]; i[2]) { count [3] 1; } } });
Drag options to blanks, or click blank then click option'
A1000000
B++
C+=
D--
Attempts:
3 left
💡 Hint
Common Mistakes
Using '--' decreases the loop variable causing infinite loop.
Using '+' instead of '+=' does not update the counter.

Practice

(1/5)
1. What is the main purpose of deno bench in Deno?
easy
A. To format code automatically
B. To check for syntax errors in code
C. To deploy Deno applications to the cloud
D. To measure how fast a piece of code runs

Solution

  1. Step 1: Understand the role of benchmarking

    Benchmarking is used to measure the speed or performance of code.
  2. Step 2: Identify what deno bench does

    deno bench runs benchmark tests to measure execution time of code snippets.
  3. Final Answer:

    To measure how fast a piece of code runs -> Option D
  4. Quick Check:

    Benchmarking = measuring speed [OK]
Hint: Benchmark means measuring speed or performance [OK]
Common Mistakes:
  • Confusing benchmarking with syntax checking
  • Thinking it deploys code
  • Assuming it formats code automatically
2. Which of the following is the correct syntax to define a benchmark in Deno?
easy
A. bench({ name: "test", fn: () => { /* code */ } })
B. bench = function(name, fn) { /* code */ }
C. benchmark test() { /* code */ }
D. bench: { name = "test", fn() { /* code */ } }

Solution

  1. Step 1: Recall the official benchmark syntax

    The correct way is to call bench with an object containing name and fn properties.
  2. Step 2: Compare options to the correct pattern

    bench({ name: "test", fn: () => { /* code */ } }) matches the pattern bench({ name: "test", fn: () => { } }). Others are invalid syntax.
  3. Final Answer:

    bench({ name: "test", fn: () => { /* code */ } }) -> Option A
  4. Quick Check:

    Use object with name and fn keys [OK]
Hint: Use bench({ name, fn }) to define benchmarks [OK]
Common Mistakes:
  • Using assignment instead of function call
  • Incorrect object syntax
  • Using invalid keywords like 'benchmark'
3. What will be the output behavior when running this benchmark code with deno bench?
bench({
  name: "sum test",
  fn() {
    let sum = 0;
    for (let i = 0; i < 1000; i++) {
      sum += i;
    }
  }
});
medium
A. It prints the time taken to run the loop 1000 times
B. It prints the sum value after the loop
C. It throws a syntax error because of missing return
D. It runs but does not show any output

Solution

  1. Step 1: Understand what deno bench does

    It runs the benchmark function multiple times and reports the time taken.
  2. Step 2: Analyze the code behavior

    The code sums numbers but does not return or print the sum. The benchmark tool measures execution time, not return values.
  3. Final Answer:

    It prints the time taken to run the loop 1000 times -> Option A
  4. Quick Check:

    Benchmarks show timing, not return values [OK]
Hint: Benchmarks report time, not return values [OK]
Common Mistakes:
  • Expecting printed sum output
  • Thinking a return is required
  • Assuming no output is shown
4. Identify the error in this benchmark code:
bench({
  name: "test",
  fn: () => {
    let x = 0
    for (let i = 0; i < 10; i++) {
      x += i;
    }
  }
});
medium
A. Missing semicolon after let x = 0
B. Using arrow function instead of regular function
C. No error, code runs fine
D. Missing await keyword inside fn

Solution

  1. Step 1: Check syntax carefully

    JavaScript allows optional semicolons. Automatic Semicolon Insertion (ASI) inserts a semicolon after let x = 0 before the for loop since for cannot continue the previous statement.
  2. Step 2: Verify other potential issues

    Arrow functions are valid for fn. The code is synchronous, so no await is needed. The code is syntactically valid and runs fine.
  3. Final Answer:

    No error, code runs fine -> Option C
  4. Quick Check:

    ASI handles missing semicolon before for [OK]
Hint: Semicolons are optional in JS; ASI works before for loops [OK]
Common Mistakes:
  • Thinking missing semicolon is a syntax error
  • Believing arrow functions are invalid in benchmarks
  • Assuming await is needed for synchronous loops
5. You want to benchmark two functions: one that sums numbers from 1 to 1000, and another that multiplies numbers from 1 to 1000. How should you write the benchmark code to compare their speeds correctly?
hard
A. Run one function inside bench and call the other outside
B. Define two separate bench calls each with a unique name and function
C. Put both functions inside one bench call and run them sequentially
D. Use bench only for the sum function and measure multiply manually

Solution

  1. Step 1: Understand benchmarking multiple functions

    Each benchmark should be defined separately with a unique name to measure independently.
  2. Step 2: Why separate bench calls are needed

    Running both in one bench mixes timings and does not isolate performance.
  3. Final Answer:

    Define two separate bench calls each with a unique name and function -> Option B
  4. Quick Check:

    Separate benchmarks for accurate comparison [OK]
Hint: Use separate bench calls with unique names [OK]
Common Mistakes:
  • Combining multiple tests in one bench
  • Measuring one function outside bench
  • Skipping benchmark for one function
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10 questions~5 mineasy hard