0
0
Data Structures Theoryknowledge~10 mins

BST property and invariant in Data Structures Theory - Step-by-Step Execution

Choose your learning style9 modes available
Concept Flow - BST property and invariant
Start at root node
Check left subtree
All left nodes < current node?
NoBST property violated
Yes
Check right subtree
All right nodes > current node?
NoBST property violated
Yes
Repeat for all nodes
If all checks pass
BST property holds
The BST property means every node's left subtree has smaller values and right subtree has larger values. This must hold for every node.
Execution Sample
Data Structures Theory
Node(10)
 /      \
5       15
/ \     / \
2  7   12  20
A BST where each node's left children are smaller and right children are larger, maintaining the BST property.
Analysis Table
StepNode CheckedLeft Subtree ValuesRight Subtree ValuesBST Property Holds?
110[5, 2, 7][15, 12, 20]Yes, all left < 10 and right > 10
25[2][7]Yes, all left < 5 and right > 5
315[12][20]Yes, all left < 15 and right > 15
42[][]Yes, no children
57[][]Yes, no children
612[][]Yes, no children
720[][]Yes, no children
8All nodes checked--BST property holds for entire tree
💡 All nodes satisfy the BST property, so the tree is a valid BST.
State Tracker
VariableStartAfter Step 1After Step 2After Step 3After Step 8
Current Noderoot (10)51520All nodes checked
Left Subtree ValuesN/A[2][12][]N/A
Right Subtree ValuesN/A[7][20][]N/A
BST Property HoldsUnknownYesYesYesYes
Key Insights - 3 Insights
Why do we check all nodes, not just the root?
Because the BST property must hold at every node, not just the root. The execution_table shows checks at each node (steps 1-7).
What if a left subtree node is greater than the current node?
Then the BST property is violated. The flow would go to 'BST property violated' as shown in the concept_flow diagram.
Why do leaf nodes automatically satisfy the BST property?
Leaf nodes have no children, so no left or right subtree to violate the property, as shown in steps 4-7 in the execution_table.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table, what is the left subtree values checked at node 5?
A[2]
B[5, 2, 7]
C[]
D[7]
💡 Hint
Check row with Step 2 in execution_table under 'Left Subtree Values'
At which step does the execution_table confirm all nodes have been checked?
AStep 1
BStep 7
CStep 8
DStep 3
💡 Hint
Look for the row mentioning 'All nodes checked' in execution_table
If a node's right subtree contains a value less than the node, what happens?
ABST property holds
BBST property violated
CCheck continues to next node
DTree becomes balanced
💡 Hint
Refer to concept_flow where right subtree check fails leading to violation
Concept Snapshot
BST Property:
- For each node, all left subtree nodes < node value
- All right subtree nodes > node value
- Must hold for every node
- Ensures efficient search, insert, delete
- Violation means tree is not a BST
Full Transcript
The BST property means every node's left subtree contains only smaller values and the right subtree only larger values. This rule applies to every node in the tree. We check each node's left and right subtree values to confirm this. Leaf nodes automatically satisfy the property as they have no children. If any node violates this rule, the tree is not a BST. The execution table shows step-by-step checks for each node, confirming the property holds throughout the tree.