The last pop() removes 2, which is the correct answer.
Final Answer:
2 -> Option C
Quick Check:
Last pop() = 2 [OK]
Hint: Track stack top after each push/pop [OK]
Common Mistakes:
Forgetting to update stack after pop
Mixing order of operations
Assuming pop removes bottom item
4. A programmer wrote this code to simulate a stack but it removes the first item added instead of the last: stack = []
stack.append(1)
stack.append(2)
stack.append(3)
removed = stack.pop(0) What is the error causing this behavior?
medium
A. pop() without index removes the first item
B. Using append() adds items to the bottom
C. Stack should use insert() to remove items
D. Using pop(0) removes the first item, not the last
Solution
Step 1: Understand pop() with index
pop(0) removes the item at index 0, which is the first item added.
Step 2: Correct stack removal method
To follow LIFO, pop() without index should be used to remove the last item.
Final Answer:
Using pop(0) removes the first item, not the last -> Option D
Quick Check:
pop(0) removes first item [OK]
Hint: pop() without index removes last item [OK]
Common Mistakes:
Using pop(0) instead of pop()
Thinking append() adds to bottom
Confusing insert() with removal
5. In a text editor, the undo feature uses a stack to reverse actions. If a user performs actions A, B, C in order, which sequence of undo operations correctly follows the LIFO principle?
hard
A. Undo B, then C, then A
B. Undo C, then B, then A
C. Undo A, then B, then C
D. Undo all actions simultaneously
Solution
Step 1: Understand stack use in undo
Actions are pushed onto a stack as they occur: A, then B, then C.
Step 2: Apply LIFO to undo
Undo removes the last action first, so undo order is C, then B, then A.
Final Answer:
Undo C, then B, then A -> Option B
Quick Check:
Undo order = last done, first undone [OK]
Hint: Undo reverses last action first [OK]
Common Mistakes:
Undoing actions in original order
Undoing multiple actions at once
Ignoring stack order in undo
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